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1: Choose a and take a closer look at the definition of relative atomic mass.
2: Choosing d atoms can be divided into protons and neutrons Allotropes Illustration 2 Error 3 is clearly wrong.
3: Pick a isotope allotrope Conceptual problem of atom composition 4: Choose d definition.
5: Select c The number of neutrons is different, and the mass is different.
6: Pick d Mathematics problem H has four different permutations 4*3=127: Pick C is more complicated, so I won't talk about it.
It's also a math problem.
9:1) 1:1 The quantity of the substance is the same and the mass is the same 2) 1:1 2:3 1:2 1:2
10: 1:4 There is an easy way to do this
These 10 questions are all conceptual questions, as long as you are proficient in concepts, you will be fine.
I hope you succeed in the college entrance examination.
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1.Pick B.
AC3H7Cl can represent 1-chloropropane and 2-chloropropane.
Can only represent propane.
It can represent n-pentane, isopentane, and neopentane.
It can represent n-butane and isobutane.
2.Choose A. In K+ and OH- are ionic bonds, and O-H is covalent bonds.
It contains only the ionic bond of Ca2+ and Cl-.
Only O-H covalent bonds are present in .
Only n-h covalent bonds are present in .
3.Select C, the highest valence of elements 11 and 17 increases sequentially, from +1 +7.
4.There is no correct one.
It is more lively than cu, and zn is the negative pole.
The quality remains the same.
c.Current flows from the copper sheet through the wire to the zinc sheet, and electrons flow from the zinc sheet through the wire to the copper sheet.
5.Option B, industrial alcohol contains methanol, methanol is toxic, no.
AC is correct and can oxidize ethylene, which is the hormone that ripens fruits.
6.I choose BC. [If it is a single choice, select C].
b.Benzene and bromine are extracted and faded, and it is not possible to judge whether they are added.
c.It is necessary to add an oxidant to change I- to I2 first, and then you can add CCL4 for extraction.
7.Select, y-o, c-si, d-s.
a.False, h2o is neutral.
b.False, H2S is easily oxidized to S by oxygen.
c.Correct, C forms the largest variety of organic matter.
d.False, the chemical formula of hydrate corresponding to the most ** oxide of S is H2SO4.
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1b (C3H8 has no isomers, you can draw it yourself) 2a (there is a covalent bond in OH-, and there is an ionic bond between k+ and oh-) 3 No Figure 4 No answer 5b (will die) 6C (extraction occurs with bromine water in benzene).
7c (x is c carbon).
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Al2O3+N2+3C===2AlN+3Co N2 is an oxidizing agent and C is a reducing agent.
For every 1 mol of ain, 3 mol of electrons need to be transferred.
The valency of nitrogen in AIN is -3
The molar mass of AIN is 41g mol
Detailed process of b:
From the original equation, we can see that n2 2aln
In this process, 6 mol of electrons are transferred, and 2mol of ALN is generated, so 3 mol of electrons need to be transferred for every 1 mol of AIN generated.
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Al2O3+N2+3C===2AlN+3Co, in this reaction, the number of electrons transferred, taking n as an example, changes from N2 to Aln, the valency changes from 0 valence to -3 valence, and every n becomes Aln, and the number of transferred electrons is 3E.
Therefore, for every 1 mol of ain, 3 mol of electrons need to be transferred.
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The transfer of electrons is the valence of valence.
al2o3+n2+3c===2aln+3co1mol 2*3e-
Caption: 1molAl2O3 reaction Then N2 either 0 valence becomes -3 valence or 3 valence transfers 3mol electrons, and there are 2 n decreasing to -3 valence n, which is 2 times 3 e-
So it is to transfer 6mol electrons.
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Item A, the drop is reduced, N2 is used as an oxidant, and the valence state of each element in Al2O3 remains unchanged, which is not an oxidant. Mistake.
B term, 1molAln is generated, the valence state of N element decreases from 0 to minus three, 3mol electrons are obtained, C is increased from 0 to 2, due to the generation of 1molAln consumption, a total of electrons are lost, and one loss is a transfer, a total of 3mol electrons are transferred, correct.
c term, n valency should be -3, false.
D, the molar mass should be 41g mol, false. Pick B.
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Correct answer. Option A, the valency of N changes from 0 to -3, decreasing, N2 is the oxidizing agent, and the valency of aluminum oxide does not change.
Option b is correct.
The valency of Al has not changed.
1molaln is generated, n is generated to obtain three mol electrons, and 3mol electrons are transferred.
option c, which should be -3, shows the positive valence of the metal in the compound.
Option d The molar mass should be 41g mol, the unit is not right.
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Choosing B, if 2molALN is generated in the equation, the valence of N is reduced by 6 valence, then 1mol is generated and 3mol electrons are transferred.
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Item B: The valency of n in AIN is 3 valent. So for every 1 molain generated, 3 mol of electrons need to be transferred, and b is correct.
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d,feso4
If the butyl solution is dropped into solution B, it is found that there is a white dust and clear color precipitate generated, and the dropwise precipitation disappears, it can be known that Ding is NaOH and B is Al2(SO4)3
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d.Ferrous sulphate.
B is aluminum sulfate; buty is sodium hydroxide; A is barium chloride.
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Ding must be sodium hydroxide, and B must be aluminum sulfate. The first is barium chloride. Then propylene must be ferrous sulfate.
2naoh+so2=na2so3+h2o naoh+so2=nahso3
The composition is sodium bisulfite = y, sodium sulfite = x >>>More
Generally speaking, an outer electron number of 8 is a stable structure, and atoms have a tendency to make their outermost electrons become 8-electron stable structure. The X element with an outer electron number of 3 can gain 5 electrons or lose 3 electrons (the subouter shell is generally 8 electrons) can make itself a stable structure with the outermost shell of 8 electrons, because it is much more difficult to get 5 electrons than to lose 3 electrons, so it often loses the outermost 3 electrons and becomes a stable structure with the outermost 8 electrons, showing a valency of +3 valence. >>>More
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1, Na2CO3 + CO2 = 2NaHCO3, so A is not good, if it is not saturated, there will be the above reaction. >>>More
Select C to generate Al(OH)3 precipitates.
Al2(SO4)3 reacts with soda ash solution, and trivalent aluminum ions will be double-hydrolyzed with carbonate ions to form trivalent hydroxide precipitate and carbon dioxide gas. >>>More