Find the equations for a straight line with points 2,0 and 0,2 .

y=-x-2

Assumption: y=ax+b

1. If you pass the point (-2,0), then 0=-2a+b

2. If you cross the point (0, -2), then -2=b

So a=-1 b=-2

Straight-line equations. for: y=-x-2

Assumption: y=ax+b

1. If you pass the point (-2,0), then 0=-2a+b

2. If you cross the point (0, -2), then -2=b

So a=-1 b=-2

The equation for the straight line is: y=-x-2

Let the equation of the straight line be y=kx+b, and bring in two coordinate points to get -2k+b=0, b=-2, and k=-1. The equation for a straight line is y=-x-2.

There is no hole in the general equation of a straight line: any straight line can be written in the form ax by c 0 (a, 0 when b is not the same).

Two-point expression represents the straight line y-y1) (y2-y1) = (x-x1) (x2-x1) (x1≠x2≠y2).

Crossing points (-1, 0) and (0, -2).

Substitute x1=-1, y1=0 and x2=0, y2=-2 respectively.

y-0) (2-0)=(x-(-1)) 0-(-1))y (-2)=(x+1)) 1) Bridge).

y/2=x+1

x+1+y/2=0

2x+y+2=0

According to the condition of the problem, the two-point equation of the straight line passing points (-1,0) and (0,-2) is:

y-0)/(2-0)=(x+1)/(0+1)2x+y+2=0

For example, if you use a two-point equation, (y-0) (2-0)=(x+1) (0+1).

Finishing, -y 2=x+1

The linear equation x+y slag changes to volt 2+1=0.

Let the equation of the straight potato line be y=kx+b, and bring in the two number coordinates to have -k+b=0, b=-2.

k=b=-2 is solved, so the equation for the destruction of the straight line is y=-2x-2. Macro remainder.

The easiest way. Set the old line y=k +c

Defeat Cong Sheng (substitution.

1=c3=2k+1

k=(3-1) Zheng Li2=1

y=ⅹ+1-y+1=0

The slope of the straight line k=(3-1) (2-0)=2, so the old equation of the straight line is :

y-1=2(x-0).

y-1=2x

So the general equation is:

2x-y+1=0.

Defeated by the limbs.

Equations for straight lines can be obtained.

y-1) (3-1) = (x-0) (2-0) The general bright group of the calendar key tremor is:

x-y+1=0.

Let the linear rift equation be y=kx+b, and the coordinates of the two points can be obtained by substituting the coordinates of the two points into the equation with the virtual argument for the source of combustion, b=0, 2k+b=4. i.e. k=2, so the equation is y=2x.

From the two-point equation of the equation of the straight line, the equation for the straight line is:

y-spike difference 0) (4-0) = (x-0) (2-0) simplification and guess the remaining skin:

y=2x。

The slope of the line that passes through these two points is (4-0) (2-0)=2

A point of this line (x,y) passes through (0,0), and the slope is (y-0) (x-0)=2

y-2x=0

Hello. Conclusion y=2x

You can use the drawing method as well as solve the equations.

Slope k = (4-0) talk about potatoes (2-0).

Socks burn k=2

The two-point formula of the linear equation: Good preparation refers to the linear equation written with the coordinates of the two points (x1,y1) and (x2,y2) of the two points.

The equation is y y1=[(y2-y1) (x2-x1)]*x x1). In this problem, the tall socks brother uses the two-point equation to find the straight line equation as y 2x

Answer: Analysis: Let the tangent point be p(x0,y0) From, the equation of the straight line is y y0 (x x0) From the point (2,0) on the straight line, x02y0 2 x0 is obtained, and then by p(x0,y0) on the curve, x0y0 1 is obtained, x0 1,y0 1 can be solved simultaneously, and the equation of the straight line is x y 2 0 Analysis:

To find the slope of the tangent using the derivative method, the tangent point must be required, and the point (2,0) is not a tangent point, so the tangent point must be set first

Solution: Let the solution of the equation of the straight line be y=kx+b, then there is 0=b, 4=2k+b

Solution: Blind feast k = 2, b = 0

The solution of the equation of the straight line rises to y=2x

Let the wild space y=ax+b, and substitute the missing search (respectively) into the formula Song search for the blind, that is: 0=, 4=2a+b, and solve the system of simultaneous equations, so that b=0, a=2, then the original formula y=2x

Let the linear equation be y=kx+b, and bring in the coordinate points to get b=0 and 2k+b=4. So k=2. The equation for a straight line is y=2x

Let the equation for the straight large and medium positive rolling line be: y=kx+b

Substituting the coordinates of two points, b=0

2k+b=4

2k=bk=2

The equation for the straight line is pun: y=2x

y = 2x, this is the equation over (0,0),(2,4).

<> according to the two-point formula of the straight line to hold the square beam to hold the Cheng Oak Demolition Qing:

y-0) (6-0)=(x+2) (0+2),y 6=(x+2) 2,y 3=x+2,y=3x+6, answer: The linear equation is y=3x+6.

Crossing the dot (2, 1).

This can be set to: y-1=k(x-2).

Point (a,2) is substituted for random luck.

2-1=k(a-2)

k=1/(a-2)

When a is not equal to 2, the linear equation modulo is:

y=[1/(a-2)](x-2)+1

When a=2, the linear equation is x=2