Ask for a junior high school question, urgently, solve a junior high school problem

Let the three-digit digit number be a, a+1, a+2

Then the three-digit number is: a*100+(a+1)*10+(a+2) and the five-digit number is: 10000+a*1000+(a+1)*100+(a+2)*10+5

From the meaning of the title: 50*[A*100+(A+1)*10+(A+2)]-465=10000+A*1000+(A+1)*100+(A+2)*10+5

Solve the equation to obtain: a=

Let this number be x, then the number with 1 in front and 5 after it is 10000+10x+5, and the relationship is: 50x-465=10000+10x+5, just solve the equation.

It seems that the question you gave is not quite right.

Solution: Let this number be x

It is derived from the equation of the title.

10005+10x=50x-465

The rest is up to you.

If there is a problem with the question, check it again.

This problem is a total of two formulas, there are two unknowns are x and y, multiplying the left and right sides of the first equation by 2 becomes 2x minus 2y equals 8. After that, the first formula is added and merged with the second formula to form a single formula. The combined formula is 6x equals 8-1.

Explain that 6x = substituting x equals 7 6 into the first equation gives y=-17 6

Since it is a junior high school math problem, one of the methods of solving a system of binary equations in junior high school is substituted for the elimination method.

Solution: Shift the term x y=4 to get x=4+y substitution solution: 4(4+y)+2y= 1

Solution: y= 3 8 is substituted into x=4+y

The solution is x=29 8

x 7/6.

y minus seventeen out of six.

Since the diagonals of the parallelogram are bisected with each other, it corresponds to a triangle with 8 on one side and 3 on the other, so it is 10 22

The line segment from the intersection of the diagonal of length 6 and another diagonal to the vertex is long 3, and the length of the other diagonal is x, then.

8+3>x/2

8-3 to get 10

The root number 11 is greater than 3 and less than 4, so a few parts are the root number 11-3

A few parts of 5-root number 11 are 4-root number 11

So a+b is equal to 1, a-b is equal to 2 times, and the root number is 11-8

Solution: Because it makes sense to be under the root (x-1) + under the root (9-x).

So: 1<=x<=9 for air travel

Absolute value (x-1) + root (x-9) = x-1 + 9-x=8 bucket wheel pin to tung this selection b

Option b When x=-1, y=-3 When x=-3, y=-3 then (-1, -3) and (-3, -3) are broken with respect to the axis of symmetry, and the axis of symmetry is x=-2

The denominator is physical and chemical, and the denominator (root number 3 - root number 2) needs to be multiplied (root number 3 + root number 2) in order to make the denominator without a root number, instead of multiplying (root number 3 - root number 2), in fact, it is the learned square difference formula (a-b) (a+b) = a -b (root number 3 - root number 2) (root number 3 + root number 2).

Root No. 3) - Root No. 2).

1 In this way, the root number of the denominator can be removed, so this problem is to multiply the numerator and denominator at the same time (root number 3 + root number 2), multiply the denominator equals 1, and the numerator is equal to (root number 3 + root number 2), and the result is (root number 3 + root number 2).

The rational-chemical process is to multiply the letters at the same time (3 + 2), and the denominator is (3-2) ( 3 + 2) = 3-2 = 1, so a will be ( 3 + 2).

Since one-part of a is equal to one-half of the root number 3 minus one-half of the root number, the number of root number 3 minus one-half of the root number minus one-half of the root number minus one-half of the root number is equal to zero must be satisfied.

What topics, I can teach you.

The denominator is physical and chemical, the numerator and the denominator are multiplied by the root number three, and the root number is changed to one.