AB: How many kilometers are the two places apart, as the question Thank you

Support for 26th floor calculation method: handshake: handshake:

The Handshake B car traveled 3 times, 54 km = 162 km, and 42 km of the 162 km traveled from A to B, so 42 km was removed from the 162 km. The remaining 120 kilometers is a whole journey of car B from place B to place A

There are n algorithms for this question, but there is only one answer, namely: 120 kilometers. Relative to fourth-grade students, generally speaking, the simplest algorithm is fine.

To 54 3-42 is good. I can't imagine that so many peers and friends on the forum participated, and here, I would like to express my heartfelt thanks to all of you. Thank you!

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Two cars, A and B, travel at an average speed from A and B at the same time. At a distance of 54 km from place B, the first encounter; Two cars from the two places at the same time to each other at an average speed, at a distance of 54 kilometers from place B So since the two cars are driving at the same time at an average speed, at this time from 54 kilometers away from place B, is it not 54 kilometers away from place A Is the car breaking down on the road; p The road conditions are still different; p View original post".

When they met for the first time, the two cars traveled a total of 1 whole way; When they met for the second time, the two cars traveled 3 times the whole way; From this, it can be seen that "the time traveled by the two cars during the second encounter" is three times the time traveled by the two cars during the first encounter; That is, at the time of the first encounter, the distance traveled by car B is 54 km; At the time of the second encounter, the total distance traveled by car B was 3 x 54 km; View the original post

I'll use the high school equation method to solve it, and it's a bit of a fuss: let AB be separated by S, the speed of car A is v A, and the speed of car B is v B. The first encounter, the distance traveled by car A (S-54) and car B 54, the time taken by the two is equal, and an equation can be obtained

s-54) v A 54 v B When they meet for the second time, car A travels a distance of (2s 42) and car B travels a total distance of (s+42), and the total time used for them is also equal, i.e.: (2s-42) v A (s+42) v B Substituting v A in the formula into the equation can eliminate v B in the equation to obtain a unary quadratic equation: s 2-120s=0 is solved as:

S1 = 120, S2 = 0 (meaningless, rounded) then, AB is 120 km apartView the original post

I'm coming to you ab is 177 kilometers away! And maybe 162 km! There are many more solutions, so there are many answers! Don't believe you push by the number I gave you! It's been a long time since I sprinkled the family! View the original post

Meet at a distance of 50 kilometers from the midpoint.

Let's meet in x hours, then.

200x-50=160x+50

200x-160x=50+50

40x=100

x = hours) = (500-50) x 2

450x2900 (km).

Let the distance between A and B be 2x, then A travels x-50, B travels x+50, (x-50) 160 = x+50) 200

5(x-50) =4(x+50)

x = 450 , the distance between the two places is 900 km

Yes, there is a long distance.

Analysis: When they met for the first time, A and B traveled 1 AB and 2 places, and A traveled 48 kilometers;

When they meet for the second time, A and B travel 3 AB and the whole course of the two places, then A travels a total of 48 3 = 144 kilometers;

It is also known that when they meet for the second time, the difference between A is 96 kilometers, and the distance between the two places is (144+96) 2=240 2=120 (kilometers) Solution: (48 3+96) 2

120 (km).

A: AB and the two places are 120 kilometers apart.

Have fun.

Let the distance between ab be sThe speed of A and B is v1 and v2 respectively. Knowing from the title v2>v1

Then the equation (s 2-100) v1=(s 2+100) v2 <1> s v1+(s 2) (2v)=(3s 2) v2 <2> dividing the two formulas gives s=2200

Topic: A passenger car drove from A to B, after 40% of the whole journey, there are still 36 kilometers from the end point, how many kilometers are the two places apart?

Solution: The die wheel is set AB and the two places are separated by x kilometers, 40% x+36=xx=36

x=60A: abThe two places are 60 kilometers apart.

Common. Strip. Untie; Let the velocity of A be xkm h, then the velocity of B is (x-20)km h

4(x+x-20)=4x+3x

8x-80=7x

x=804x+3x=7*80=560

Answer; ab The two places are 560 kilometers apart.

Topic: How many kilometers is the distance between AB and AB after a bus travels 40% of the way from A to B, and there are 36 kilometers to the end of the journey?

Solution: Let AB be x kilometers apart, 40%x+36=xx=36

x=60A: abThe two places are 60 kilometers apart.

Use equations to solve.

Solution: Let the speed of A be x kilometers, then the speed of B is (x-20) kilometers.

4(x+x-20)=4x+3x

8x-80=7x

x=804x+3x=7*80=560

Answer; ab The two places are 560 kilometers apart.

Let B have a speed of x kilometers per hour and A as x+20

Let ab be y kilometers apart.

Rule. (x+x+20)*4=y

x+20)(4+3)=y

Solution. x＝60

Y 560ab The two places are 560 km apart.

Let the distance between A and B be x thousand chain meters, and the sum of the speed is x 2Increases the speed of the cluster and is x 2+2So infiltration x 2 + 2) = 2xThe solution is x=36

Later speed and.

2 divided by 3 and 36 60 = 5 9

Front speed and: 1 2

1+1) (5 9-1 2).

36 (1,000 meters high).

The increased speed is divided by the corresponding fraction and it is good).

My Fang Qi Yin method is good@@@

ab The two places are separated by x thousand hulu meters.

x/2+2)*18/5=2x

x = 36ab (36 per cent).

Kilometers ruin.

Let AB be separated by l kilometers, so that the sum of the speeds of the two is A, then there is a calendar: Limb Friend Book.

2*2*a=(a+2)*

a=18, while l=2*a=36

Or use the building to tell the hunger.

Set ab two places Zen collapse cover is far away from S Qianhe noisy meter.

Then there are jujubes. 2s/

Solution. s=36

Let AB be separated by a distance of S, B velocity is V, and C will meet after T minutes after C departs.

s=(15+t+7)*40+60(t+7)①s=(15+t)*40+(15+t)v②

t+7+63)*60=(15+t+7+63)v is obtained by = 100t+1300=(40+v)t+600+15vvt=60t+700-15v

De, 60T+4200=85V+TV

The two formulas are juxtaposed, and 60t+4200=85v+60t+700-15vv=50 is known by T = 5

then s = 1800 meters.

i.e. kilometers. Ask for extra points.

Let A and B meet first on the way to the high barrier bush for x minutes, the distance between the two places is S meters, and B walks Y meters per minute.

40+y) *x =s

40*(x+7) +60*(x +7 -15) =sy*(x+7+63) =60*(x+7+63 -15) is not easy to calculate, Qi Ying will calculate it herself.