The total time is a problem, and time does not solve all problems

That's not a good question.

First of all, you should be able to find the speed at the rated power, in the car from the speed of the rated power to the maximum speed, the process is a process of variable speed movement, because the size of the force in this process has to change, which you can see from the V-T diagram. The acceleration of this process is a little bit smaller. The speed gradually reaches its maximum.

If this time is required here, it may be necessary to use an integral or equivalent method. It's hard to ask.

The two upstairs didn't give the right idea, the first floor was purely writing formulas, and the second floor was talking about a little bit of content, and didn't talk about the main thing at all. But the landlord, you don't give complete conditions, I can only talk about this problem according to what conditions are needed to solve the time, I believe it will help you, hehe.

This question is actually quite easy to do. The car starts with constant acceleration, in the case of constant resistance by default, traction is a fixed value, before the actual power of the car reaches the rated power, it has been doing uniform acceleration movement, as long as the value of the rated power and the value of traction are given, we can find the final velocity of the uniform acceleration movement by p=fv. Then from f-f=ma and v1=at, we can calculate the time of uniform acceleration motion, which is expressed by t1.

After that, the traction force continues to decrease, the car does a variable acceleration movement, when the traction force f is equal to the resistance f, the speed reaches the maximum value, that is, there is a rated power p=fv2=fv2, as long as we know the magnitude of the resistance f and the rated power value, we can calculate the maximum speed. Finally, if you know the displacement s of the variable speed motion, list a kinetic energy theorem equation, let the variable speed motion time t2, then there is pt2-fs=1 2*m(v2 2-v1 2), v1 and v2 represent the initial and final velocities of the variable speed respectively, you can find t2, therefore, the time from starting to reaching the maximum speed is t=t1+t2, the solution is completed, hehe.

We often say, wait for time. Time can heal everything, but time doesn't solve everything.

Unprocessed memories are like corpses buried in ice and snow, and once the ice and snow on the surface are blown away or melted away by the storm, the corpses will reappear vividly, catching us off guard.

But no matter how scarred and broken we are on the surface, we are still valuable. This value is innate and no one can take it away.

There is no one but yourself who can devalue you. We cannot change events that have already occurred, but we can change how those events affect us.

Don't let the past ruin our ability to enjoy the good things in front of us.

The relieving pain in life is like salt, depending on how big a container you dissolve it in. If you put it in a pocket-sized milk pot, it's over, and you'll be pickled. If it's a bay, then the clouds are light and the wind is light.

Bi Shumin).

hours, because the passenger car is faster than the truck and the world inspection returns, the passenger car first arrives at the station of Jie Da B, it takes 6 hours, at this time the truck travels for 6 hours (that is, 240 kilometers), and then the encounter problem, the remaining total distance is 120 kilometers, and the time required for the passenger car and the truck to meet can be listed in an equation: (60 + 40) x = 120 solution x = so the total time is hours.

It takes 6 hours for the bus to travel from station A to station B.

The truck needs to be sharpened for 9 hours from station A to station B.

When the bus arrived at station B, it took a total of 6 hours, and the truck drove 240 kilometers at this time, and the remaining 120 kilometers (360-240) can be seen as a meeting between the bus and the truck.

120 divided by (40+60) 100 equals hours, so the total number of trips from departure to meeting is (6+ hours.

From no bird out of the middle to meet a total of 2 whole journeys, okay.

360 2 720 (1,000 lead meters).

From departure to encounter.

720 (60 40) km).

All of the above are positive solutions, and the thinking mode of the 5th floor is also very good. The things on the first floor are the easiest thinking patterns for ordinary mouths, and the ridges on the second floor are the simplest and fastest thinking patterns.

A's work efficiency: 9 14-1 8x5=1 56

A alone to stop the collision into the need to send rotten want; Jian Xian talks about 1 1 56 = 56 (days).