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The decimal part of the date variable with a value of less than 1 corresponds to the time of day from 0:00:00 to 24:00:00
Equivalent to 12:00:00
Equivalent to hours, hours are 24 minutes, so it is equivalent to 14:24:00
1 hour 60 minutes.
Let the decimal value less than 1 be a
24 * a
The integer part of the result is the hour.
The decimal part * 60
The integer part of this result is the minute.
The decimal part * 60
The integer part of this result is the second.
You'll find out if you try it yourself.
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Change a or b to a number greater than 1, and you will find that in fact, the value of a or b is the number of days calculated from 0:00:00 on January 1, 1900, the decimal part is *24 hours, and the minutes and seconds are the same, if it is less than 1 day, only hours and minutes and seconds are displayed, and if it is greater than one day, only the year, month and day are displayed.
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The 3rd floor is correct.
If you try it, it's 2 hours and 24 minutes, and it's 14 minutes and 24 seconds.
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Use 24 hours* to get the hour, and the hour is 14
Hour 24 minutes is converted into time format 14:24:00
Using 24 hours* to get 12 hours is 12:00:00
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That is, we define the data type of a b as time, and divide 1 into 24 hours.
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month is the month in which the date is found, so the first result is 5
day is the day on which the date is found, so the second result is 16
So the result is 21
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Month (5) of the first term + day (16) of the second term = 21
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2003 Zaobi 11 22 -40 is equivalent to 2003 November 22 pushed forward 40 days, that is, October 13, 2003.
month( -40) is to find month(
So the resulting value is 10
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month(##
is the month of the calculation date (2003-11 or 22-40).
This is how it works in the program. First of all. ##
It will be converted into a standard form of annihilation. And then.
Compute. Date. ##
This corresponds to 22 November 2003, which is 40 days forward, i.e. 13 October 2003.
Date obtained.
Finally, the month function is used.
calculates the month of , so the result is 10
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