Who s going to help me tell me a math problem I can t think about it for 1 hour

One day, Mr. Wang rode to the mall to buy prizes, and then went to school, and walked 2+2+1=5 kilometers.

Set the cycling speed to x km/h and walk x km/m.

5 x = km min = 15 km h.

Set up walking x km h, cycling.

Direct to school: 1 x

Home to the mall and then to school (10 minutes to buy prizes): 5 Therefore: 5, get x=6km h, ride 15km hAll of the above units are hours.

If the cycling speed is s meters, the walking speed is 2s 5 meters.

Usually walk 1000 meters to school, but walk to school on this day: 2x2000 + 1000 = 5000 meters.

Yes: 1000 (2s 5)+20=5000 s+10 can be found: s=250 m min.

Let the no-speed be x and the cycling speed is.

then there is 1 x=5

Two equations: first: the speed of the car is times the speed of walking;

Second: it takes 20 minutes longer to ride and buy groceries than the normal walking time;

10 60 + 3 car speed = 1 walking speed + 20 60 to solve.

Let the walking speed v, the walking time t to school, vt=1,,, the simultaneous solution v=6,

Let the walking speed be xkm h, then the cycling speed is km h, the cycling speed is 5km on the bike, and the equation is established according to the time relationship

5 + 10 60 = 1 x + 20 60 solution x = 6, and the cycling speed is 6*

Set up walking x meters per minute.

1000/x+(20-10)=(2000*2+1000)/(1000/x+10=2000/x

1000/x=10

x = 250 meters per minute on a bicycle.

If the walking speed is x km h, then the cycling speed is km h

5/ + 10/60 = 1/x + 20/60

Get x=6, and the cycling speed is 6*

5 (x=km/min, which is the walking speed.)

Summary. Hello, please send us the question.

Would like to ask a math problem, thank you.

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How is this derived?

Okay, I'll take a look.

Since you didn't have it before, I'll start here and start by bringing in the abscissa values of m and n to find the coordinates of m and n.

Then we use the point-oblique equation.

Because both the m and n2 points are in a straight line.

So the ratio of the difference between the ordinate and the abscissa of the two points is the slope.

Then there is the point oblique equation.

You can find the analytic formula of the equation.

(1-m)x=-4m,x=-4m (1-m) If you want to have a solution, then the denominator cannot be 0, so 1-m≠0 to find m≠1.

The answers are all here, and the math problems should be inferred, and the following things may be helpful.

When there is no solution to the fractional equation.

Solving fractional equations is generally to convert the fractional equation into an integral equation, and then find the solution of the fractional equation. Some fractional equations have solutions, some fractional equations have no solutions, and the absence of a solution to fractional equations can be considered from two perspectives:

First, there is no solution to the integral equation into which the fractional equation is converted;

The second is that the integral equation to which the fractional equation is converted has a solution, but this solution makes the value of the simplest common denominator of the fractional equation 0.

Example: A fractional equation about x.

322133xmx

xx has no solution, find the value of m. Analysis: There are two situations in which the fractional equation is unsolved: one is that the integral equation obtained after removing the denominator has no solution, and the other is removing the denominator.

The resulting integral equation has a solution, but this solution makes the value of the simplest common denominator of the fractional equation 0, and the fractional equation has no solution. Therefore, in order to determine the value of the letter to be determined according to the absence of a solution to the fractional equation, the above two cases must be considered.

The first case: when 1m, this integer equation has no solution, so when 1m, the original equation has no solution. The second scenario:

For equation (1)2mx when 3x, 3 is the root of the original equation, and the original equation has no solution, so when (1)32m, that is, 5

At 3m, there is no solution to the original equation. So when the value of m is 1m or 5

At 3m, there is no solution to the original equation.

Solution: Simplify x+m=m(x-3).

x(m-1)=4m

1) When there is no solution to the above equation, m=1;

2) If there is an increase in roots, bring in the increase in roots x=3, there is.

3m-3=4m

m = -3 in summary, m = 1 or -3

x+m=mx-3m

m-1)x-4m=0

When m=1, we get -4=0 and there is no solution.

and x≠3, so 3(m-1)-4m=0, that is, m=-3, there is no solution so m=1 or -3

is m=1, multiply x-3 to the right, and simplify (1-m)x=-4m; Let 1-m=0, that is, the solution.

Answer: m=1

The divisor m-1 so m=1 in addition m= - 3

The first shift term is discussed in two cases: primary and quadratic functions, and there is no solution to discriminant formula 0 in quadratic functions.

x+m=m(x-3) 4m=(m-1)x

If m=1, there is no solution.

m is not equal to 1 x = 4m (m-1), and x is not equal to 3 from the title, i.e. m = -3

Above is a quadrangular pyramid.

Below is the cylinder.

Volume formula for quadrangular pyramid.

v=(1/3)sh v=1/3*1/2*2*1*2*1*3*1/2=1

s is the base area of the pyramid.

h is the height of the quadrangular pyramid.

The derivation process uses the definite integrals of our university).

Formula for calculating the volume of a cylinder.

v= r h=pi square of radius height v= approximately equal to (note that when you do it, you should also pay attention to the same unit radius and height should be the same) so'v=

(1) Lower cylinder volume = bottom area height = (2 2) 2 = 2 (2) upper quadrangular pyramid volume = 1 3 bottom area height = 1 3 (4 1 2 1 1) 2 -1 )

Geometry volume = lower cylinder volume + upper quadrangular pyramid volume = 2 +2 3 3=

A regular quadrangular pyramid on the top and a cylinder on the bottom with a radius of 1According to the Pythagorean theorem, the height is the lower three, and the side length of the square is the lower two, 1 3sh + r h

First find the volume v=s*h of the cylinder below, and then the volume v of the cone above'=s*h*1/3

It can be obtained from the question.

The first alcohol has 40% 80 = 32 grams.

The second alcohol has 30% 120 = 36 grams.

So there is a total of 32 + 36 = 68 grams.

Because the agricultural liquid has 80 + 120 = 200 grams.

So the concentration is 68 200 100% = 34%.

It can be obtained from the question. Forward speed 200 10=20km.

Reverse speed 120 10=12km.

Forward speed = boat speed + water speed 1

Reverse speed = boat speed - water speed 2

1+2 = twice the speed of the ship = 20+12 = 16km at 32km.

248 16 = hours.

The order of operations is as follows: first calculate the square of a, then open the root number, then subtract a, and then take the absolute value.

The square of a is a square, after the root number is -a (because a < 0), after subtracting a is -2a, and after taking the absolute value, it is -2a

D... The square of a under the root sign is negative a, (because a is negative, and the opening should be positive).