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Anonymous users2024-02-0725(sinx)^2+sina-24=0
How can there be an x?
If yes: 25(sina) 2+sina-24=025sina-24)(sina+1)=0
Neither sina = 24 25 nor sina=-1 is a (3 2,2) if a is changed to [3 2,2 ).
then a = 3 2
cos(a 2)=cos(3 4)=- 2 2Welcome to exchange!
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Anonymous users2024-02-0625(sinx)^2+sina-24=0
sina+1)(25sina-24)=0
Because a belongs to (3 2,2), sina = 24 25a belongs to (3 2,2), cos(a 2)< 0, sin(a 2)>0cos(a 2)-sin(a 2)} squared = 1-sina = 1 25, sin(a 2)-cos(a 2) = 1 5
The square of cos(a 2) + sin(a 2)} = 1 + sina = 49 25, cos(a 2) + sin(a 2) = 7 5 (the problem is found here).
But I think you can learn something along the way.
Happy studying.
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Anonymous users2024-02-05sina + cosa = 6 21 + 2 sina cosa = 6 4 sin(2a) =6 4 - 1 = 1 2 a belongs to (0, orange jujube imitation 4) 2a belongs to the genus Yanchangyu (0, 2) 2a = 6 a = 12sin(a-5 round fiber 4) = sin( 12-5 4) =sin(-14 12) = sin(-7 6)= sin(- 6)= sin(...)
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Anonymous users2024-02-04a ( 2, ) and sina = 4 5, so cosa = -3 5sin (a + 4) + cos(a + skin 4) sinacos 4 + cosasin 4 + cosacos 4-sinasin 4
Root No. Burning Chi Xiang Dan Hood 2) 2] (sina + cosa + cosa-sina).
Root number 2) cosa
3 (root number 2) 5
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Anonymous users2024-02-03sina = 2 3, a belongs to ( 2, ).
cosa=-√5/3
cosβ=-3/4..Belongs to (, 3, 2) sin = 7 4
cos (Ming Tan -
cosαcosβ+sinasinβ
5 3*(-3 4)+2 3* 7 4 5 4+ 7 6
cosα=3/
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Anonymous users2024-02-02Knowing that a belongs to (3 2,2) and 25sin 2a+sina--24=0, then cos2 a=sina +1)(25sina-24)=0
sina=-1
24 25 (a belongs to pei chun (3 with paragraph 2, 2), rounded) a = 3 2, a 2 = 3 4, cosa 2 = (-Gen Ran Bridge No. 2) 2
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Anonymous users2024-02-011.Simplification of sin(a- 4)=7 2 10 yields sina-cosa=7 5
cos2 = 7 25, i.e., (cos a-sin) (cosa sin) = 7 25, substituting sina-cosa = 7 5 to get cosa sin = 1 5
Solution: sina = 4 5, cosa = -3 5 tana = sina cosa = -4 3
tan(a π/3)=[tana tan(π/3)]/[1-tana*tan(π/3)]=(-4/3 √3)/(1 √3*4/3)=(48-25√3)/39
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Anonymous users2024-01-31Square the formula sina + cosa = 7 13 to get 2 sinacosa = -120 169
According to the argument that a belongs to (- 2,0), it can be shown which sina "carry key height 0 cosa>0
Let cosa-sina = x>o squared.
1-2 sinacosa = x2 = 289 169 x = 17 13
So according to. sina+cosa=7/13
cosa-sina=17/13
cosa=12/13;sina = -5 13 substituting results in 13 159
Seek guidance first. '(x)=3x^2-x+b
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