Knowing that the straight line x 2y 4 0 is parallel to the straight line 2x my m 3 0, what is the di

The slope of a straight line is known k1=-a b=-1 2

The slope of another straight line k2=-a b=-2 m

Two straight lines are parallel.

k1 = k2, then -1 2 = -2 m

Solution: m=4

That is: the straight line is 2x+4y+7=2(x+2y+7 2)=0, and the distance between the two straight lines =|-4 - 7/2|/√1²+2²

The two straight lines are parallel and the slope is equal.

Straight line 1: y -x 2+2

Straight line 2: y -2x m - (3+m) m

i.e. -2 m -1 2 m 4

Therefore the straight line 2: y -x 2-7 4

The slope of two straight lines k -1 2 is known

A straight line y perpendicular to two lines and past the origin'＝2x

The distance between the intersection points and the intersection points of two straight lines (1,2) (7 10,7 5) is the distance between the straight lines.

From parallel, 2 1 m 2, m=4, when x=0, substitute x+2y-4=0, and the other straight line is x+2y+7 2 to find the straight line point as (1,3 2)d=|1+3+7/2|+/√1²+2²=3√5/2

y=a2+4 is parallel to y=a2x m-(m+3) m.

A 1 2 = a 2 m

m=4(m+3)/m=7/4

The intersection point of the straight line 2 +4y+7=0 and the y-axis is (0, a7 4).

The distance between the two lines is.

丨1 0+(a7 4)x2-4丨 (1 +2 The distance between the two straight-line lines is.

First, find the constant fixed point of the following line, which is (,-1).

Then, according to the parallel of the two straight lines, the value of m is obtained by using the slope of the straight line of the first question.

Finally, the final result can be obtained according to the formula for the distance between two straight lines.

Parallel, 1 2 = 2 m

Thus m=4 is obtained

2x+4y+7=0, ie.

x+2y+distance=|

Summary. Hello dear.

The formula for the distance of two parallel straight lines: If the two straight lines are ax+by+c1=0 and ax+by+c2=0 respectively, then the distance is |c1-c2|/√a²+b²)。

The straight line 4x+2y-3=0 and the straight line 2x-my=0 are parallel to each other, so what is the distance between them?

Hello dear, good morning dear, I'm glad to answer this question for you, oh dear, this question is answered by me for you, the distance is 3/10 times the root number 5 oh dear.

Hello dear two parallel straight line distance formula laughing grandson: if the two straight lines touch the balance chain do not block ax+by+c1=0 and ax+by+c2=0, then the distance is |c1-c2|/√a²+b²)。

Can you help me take a look?

Hello dear, it's a pleasure to serve you oh pro the option for the first picture is b

Let y=0, then x=-1 6, then just calculate the distance from (-1 6 0) to 3x+y-3=0, you can draw the first equation on the coordinate axis, it is handed over to the axis of the beacon x=1(a),y=3(b), the second square wheel answers the paddle wheel to a point, that is, (-1 6 0) this point is the c point, the trigonometric function can be calculated, the triangle aob and the triangle adc are right angles, and the d point is the distance from the c point to ab, It is also the answer of the landlord

Solution: by the meaning of the topic.

3x+y-3=0 is parallel to 6x+my+1=0, so 3:1=6:m3m=6m=2

6x+2y+1=0

That is, 3x+y+1 2=0

The distance between these two parallel lines of the circle is d=l-3-1 2l 107 107 10 20

Answer: Slightly.

3x-4y-1=0 slope = 3 4

6x-my+3=0 slope = 6 m

3x-4y-1=0 //6x-my+3=03/4=6/m

1/4=2/m

m=80, 1 4 ) on the straight line 3x-4y-1=0.

0, 1 4 ) to the straight line 6x-8y+3=0.

6(0)-8(1/4)+3|After talking about (6 2+8 2), the distance between the two parallel lines containing the state is 3x-4y-1=0 and 6x-my+3=0 is =1 10

The straight line x+ay+3=0 is parallel to the straight line 4x+1=0.

So 1 4=a 0≠3 1, so a=0

The distance between the two straight Hu Zheng lines.

The distance between two parallel lines 2x-4y+3=0 and 2x-4y+1=0 is obtained d=|3-1|Root number (2 2 4 2) 2 Root number 20 2 (imitation 2 root number 5) Root number 5 5

Formula: The distance between the two parallel lines ax+by+c1=0 and ax+by+c2=0 is d=|c1-c2|Root number (A 2 + B 2).

The two straight lines are parallel, so the slope k is equal, and we get -6 m=-3, so m=2 straight line is 6x+2y+1=0

It is obtained by the formula d= c1-c2 (a 2 + b 2) for the distance between two parallel lines.

The distance between 3x+y-3=0 and 3x+y+1 2=0 d=7 10 20

y=-3x-3 is parallel to my=-6x-1, then the slope k is equal, so there should be -6 m=-3 m=2 y=

And then you draw a diagram and it's easy to solve, and you can solve it with similar triangles.

y=-3x+3

y=-6x/m-1/m

Because it is parallel, -3=-6 m

Therefore, m=2, i.e., 6x+2y+1=0, which is converted into 3x+y+, the distance between parallel lines, is c1-c2, the root number a2+b2, where c is the constant in the equation of the straight middle line.

The premise is that the coefficients of xy are to be the same.

Distance = Closed root number 10

Xie Ye Shen: Because the two straight lines are parallel, the empty ridge carries m=-2

So the equation of two straight lines can be reduced to 3x+y-3=0, 3x+y+1 2=0

The distance between two parallel lines d=|c1-c2|A 2 + B 2 = 7 (root 10) 20 under the root number