Does the break time in the elementary math schedule problem count

For example, when calculating the distance of 20 kilometers, walking for 50 minutes, resting for 20 minutes, and walking for 50 minutes, to find his speed, it must be calculated according to 2 hours, not 100 minutes.

No, math problems are an ideal state, not exactly the same as real life, and when the problem does not indicate that there is a break, it can be regarded as no rest, and has been exercising.

It's a bit wrong to go upstairs.

When finding the average speed, the general rest time is counted, unless the question requires that the rest time is not counted.

In short, if the question requires a break to be included, it should be counted; If you ask for a break period, you shouldn't consider it.

The general rest time is counted.

It's a bit wrong to go upstairs when finding the average speed, and if the question requires a break time, it should be counted, unless the question asks for a break time to be counted. In a word.

Absolutely not, our math teacher has emphasized it to us countless times!!

It cannot be a hard and fast rule whether it is counted or not, it should be determined according to the topic. Generally, it is not counted, unless the two may be added in the case of comparing distance, speed, and time.

No, because the distance and time don't matter.

It should be counted, unless it is specifically noted in the test paper or workbook (according to the teacher).

There are two kinds, counting and not counting: 1Don't count: what is not said in the title and rest together. 2.It's just a person resting (how to calculate, depending on the title).

That depends on your title.

Generally, it doesn't count.

Calculate. The total distance traveled is divided by the total time.

I think that if a serious student should take both kinds of back, first write "If you count the time of breaks" to list the relevant formulas. Then write "If you ignore the break" to list the relevant formulas. This must be right!

I can't say for sure! If the question mentions rest, it is considered a break, and if it is not mentioned in the question, it is not counted.

The distance divided by the time is equal to the speed (definitely).

Whether it counts or not depends on how the problem is solved. General requirements do not count.

In addition to the question request)

Generally, it doesn't count, but it depends on the specific requirements of the topic.

Generally, it is not counted, but it depends on the requirements of the topic.

There are two kinds, counting and not counting, if you don't explain that you don't count, you have to count the rest time, and if you want to explain it, it doesn't count.

If you want to look at the question, if you say it on the question, it will be counted, and if you don't say it on the question, it will not be counted.

A runs 100 meters plus 10 seconds and stays for 10 seconds for a total of 100 5 + 10 = 30 seconds, and B runs 100 meters plus a stay for 10 seconds for a total of 100 4 + 10 = 35 seconds.

It can be known that it takes 5 seconds for every 100 meters B. 5 seconds of 25 meters in a row--- 25 meters per cycle (35 seconds) distance. It takes 100 25 = 4 cycles.

B needs 400 400 meters 4 + 3 * 10 = 130 seconds A needs 500 5 + 4 * 10 = 140 seconds for 500 meters B arrives at 400 meters and stays for 10 seconds, exactly when A arrives.

Therefore, it takes 140 seconds for A to catch up with B.

In the journey of 3 10, Dad was 5 minutes faster than Xiao Ming, and the whole process, Dad was faster than Xiao Ming: 5 3 10 = 50 3 (minutes) that is, Xiao Ming took 50 3 minutes more.

When Dad caught up with Xiao Ming, he was gone: 1-3 10 = 7 10, and Xiao Ming was gone: 7 10 -5 10 = 2 10, so :

Dad's speed is Xiao Ming's speed: 7 10 2 10 = 7 2 = times) The distance is certain, the speed is inversely proportional to the time, Dad's speed is twice the speed of Xiao Ming, and the time it takes for Xiao Ming to walk from home to school must be times the time of Dad's total time from home to school. If Dad's time is 1 part, Xiao Ming's time is a share, and Xiao Ming's time is more than Dad's), one copy is:

50 3, servings: 50 minutes).

From "when you have completed half the distance" to "there is still 3 10 miles to complete", it can be seen that walking 2 10 is equal to riding a bicycle 1 2 distance, so it can be concluded that the walking speed is equal to the cycling speed of 2 5.

5 1 2 = 10 (minutes).

10 2 10 = 50 (minutes).

1. After Dad catches up with Xiao Ming, the time taken by Xiao Mingyuan 3 10 minus the time taken by Dad 3 10 = 5 minutes;

2. The speed ratio of Dad's speed to Xiao Ming's speed is 7:2, the ratio of time taken to travel the same 3 10 is 2:7;

3. Let the walking time be x, then x:(5-x)=7:2, get x=7 minutes, otherwise, the time taken by Dad is 2 minutes.

Divide by 3 10 and the total walking time = 70 3 minutes = 23 minutes and 20 seconds.

Solution: If Xiao Ming walks from home to school in x minutes, in the process of chasing Xiao Ming, Dad walks 1-3 10 7 10 distance, Xiao Ming travels 5 10-3 10 2 10 distance, then Dad takes 2x 7 minutes to walk the whole process, and Xiao Ming walks in the middle of the journey, which takes x 2 minutes.

x/2-2x/7=5

x=70/3

A: It takes 70 to 3 minutes for Xiao Ming to walk from home to school.

Solution: If Xiao Ming walks from home to school in x minutes, in the process of chasing Xiao Ming, Dad walks 1-3 10 7 10 distance, Xiao Ming travels 5 10-3 10 2 10 distance, then Dad takes 2x 7 minutes to walk the whole process, and Xiao Ming walks in the middle of the journey, which takes x 2 minutes.

x/2-2x/7=5

x=70/3

A: It takes 70 to 3 minutes for Xiao Ming to walk from home to school.

Let Xiao Ming walk from home to school in x minutes, set the distance to 1, Xiao Ming's speed is 1 x, Dad walked 7 10 in the distance of Xiao Ming walking 7 10-1 2=1 5, the speed is Xiao Ming's 7 2 quilt, Dad speed is 7 (2x), get the equation.

7 10) (1 x) + (3 10) (7 (2x)) = x-5, and the solution is x=70 3.

Solution: Set the time to x the time of the bicycle to y

7y/10=x/5

3(x-y)/10=5

Solution: x=70 3

y=20/3