c

I used the knowledge of high school mathematics, and now I give Brother Ren a way of thinking, and the problem solving process is as follows:

Known: The experience base is 200, which is the first level, and the experience difference of each base is 200 The solution is as follows: Known:

The base is 200, each level is incremented by 1, and the base difference is 200

Set the new level to n, the new level of experience to A, and the new level to B

then the new level of experience is.

a=200+200*（n-1）

The new levels are: b=n+1

Write it out according to the steps of high school math solving, and apply it to the program at a glance :) apply it to the program.

Experience Difference = Level * 200

XP required = (Level * Level +1) 2) *200

f(x)=f(x-1)+200*x

A recursive approach should be used.

A data structure is a relationship between data storage and integration, such as arrays, linked lists, etc.

Algorithms are sub-internal to the interaction between data.

Sequences and methods, such as the Rong: bubbling method.

They are two different concepts, but they are often compatible and dependent on each other.

To give a layman's example: suppose your goal is to "move forward";

When you're using a "data structure" like a bicycle, you can use the "push hard" method.

When you're using a "data structure" like a car, you can use the "gas pedal" method.

There is a fit and dependency relationship between them and they are not interchangeable.

C, on the other hand, is a type of computer programming language and is not necessarily related to the above two.

Let's just explain (float) c 5, which means that c is converted to float and then divided by 5, which is equivalent to , and the result is, if you don't convert, it's just 4 5, and the result is 0

Arithmetic basic priority, first multiplication and division, then addition and subtraction, the same level from left to right so 7 3 2 * 2

For more information, see C Arithmetic Operators.

It's about setting a variable, e.g. m:

m=a%3+b*b/(float)c/5;

The compiler will figure it out automatically.

a%3=1；b*b=(-2)*(2)=4b*b (float)c 5=4 5=priority questions are divided backwards) so the correct solution is: a%3+b*b (float)c 5=1+(4 (you can verify it yourself).

float)c=cast to floating-point number); (float)c 5=(float)c is still 4 when it is output alone, and it will be automatically converted to a decimal place when the operation occurs.