Let s calculate this intellectual math, how to solve this mathematical puzzle

It is divided into four sections: 1 ring, 2 rings, 3 rings, and 5 rings.

The 11-day allocation is:

Day 1 Give 1 ring; 1

Day 2 Take back 1 ring, give 2 rings; 2

Day 3 Whoever takes back 2 rings, gives 3 rings; 3

Day 4 Give 1 more ring; 3＋1

Day 5 Take back 1 and 3 rings, give 5 rings; 5

Day 6 Give 1 ring; 5＋1

Day 7 Take back 1 ring, give 2 rings; 5＋2

Day 8 Whoever takes back 2 rings, gives 3 rings; 5＋3

Day 9 Give 1 more ring; 5+3+1

Day 10 Whoever gets 1 ring back, gives 2 rings; 5+3+2 Day 11 Give 1 more ring. 5+3+2+1

Divide. On the first day, I knocked down 1 payment, I had 10 left, and the boss 1.

The next day, knock down 2 payments, get one back, and have 8 + 1 left for yourself, and 2 for the boss.

Pay 1 on the third day, 8 for yourself, 2 + 1 for the boss.

On the fourth day, knock down and pay 4, get 3 back, and leave 2 plus 1 plus 4 boss 4.

Pay 1 on the fifth day, 2 + 4 for yourself, 4 + 1 for the boss.

On the sixth day, pay 2, get 1 back, have 1 + 4 left, and 2 + 4 bosses.

Pay 1 on the seventh day, 4 for yourself, 1 + 2 + 4 for the boss.

On the eighth day, pay 4 to get back 1 + 2, you have 1 + 2 left, and the boss adds 4 plus 4.

Pay 1 on the ninth day, 2 for yourself, 1 + 4 + 4 for the boss.

On the tenth day, pay 2 to get 1 back, 1 left for yourself, 2 + 4 + 4 for the boss.

Pay 1 on the 11th day.

So in the end, it is concluded that the segmentation method is 1+2+4+4

Just divide it into 4 sections

Four paragraphs, 1, 2, 4, 4

On the first day, give 1

The next day, give 2 and ask for 1 back

On the third day, give 1 more

On the fourth day, give 4 and ask back 1 and 2

And so on until eleven days.

Lost $75 in cash and $25 in stuff.

The buyer gave a counterfeit bill, which means that he did not give money, and took away the 25 yuan thing and the 75 yuan real banknote.

The vendor gave a hundred dollars in change, and later asked for a hundred dollars in real money, and neither side lost anything.

200. Give 100 to the vendor. 75 to the person who bought something. Plus $25 stuff.

$100. 25 yuan of things (sold for fake money, no profit) + 75 yuan of real money change = 100 yuan.

The loss to the vendor is offset by the change returned.

$100.

The man took $25 and $75 in change and walked away—the $100 was the $100 the shopkeeper lost.

And "the shopkeeper had to find a real hundred-dollar bill for the vendor" — 100 dollars in this case with.

I went to the vendor next door and exchanged 100 yuan for 100 yuan in change."

The amount of lost counterfeit money: $100.

Climb (4-3) meters every day, the tree is 10 meters high, the snail only needs to climb to 6 meters, and it takes the remaining 4 meters in 6 days, and it is completed at once during the day.

So, climb to the top of the tree on day 7.

(10-4) (4-3)+1=7 (days).

A: The snail climbs to the top of the tree on day 7.

The answers to the 16 questions are not complicated.

Just fill a 3-quart bucket twice and pour water into a 5-quart bucket, leaving only 1 quart in 3, then pour 5 quarts of water, pour 1 quart into a 3-quart bucket, and pour 3 quarts of water into 4 quarts.

I'm a veteran.,Reputation is half-like.

Fill in 17 and let the number in the top corner be a, the number in the lower left corner is b, the number in the lower right corner is c, and the middle number a, b, c satisfies the following formula:

b to the power a + c

As long as the thief listens to the lecture seriously, the thief does the questions seriously, the thief corrects the wrong questions seriously, and the thief seriously reviews the wrong questions, the thief can do well in the test.