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Anonymous users2024-02-07When k=0, f(x) is <> in the interval
The upper monotonically increases, and f(x) is <> in the interval
on monotonically decreasing;
When k=0, f(x) is <> in the interval
On monotonically increasing, in the interval <>
On monotonically decreasing, in the interval.
on monotonically increasing; When <>
, f(x) is <> in the interval
On monotonically decreasing, in the interval.
On monotonically increasing, in the interval <>
on monotonically decreasing;
Piecewise functions should be treated in segments, and since each segment is a composite function of the basic elementary function, it should be studied with derivatives.
Because <>
So <>
1) When x<1, 1-x>0, <>
When <>, <>
In the <> is constant, so f(x) is <> in the interval
on monotonically increasing;
When <>, order <>
The solution is <>
And <>
time, <>
When <>, <>
Therefore, f(x) is <> in the interval
On monotonically decreasing, in the interval.
on monotonically increasing;
2) When x>1, x-1>0,<>
When <>, <>
In the <> is constant, so f(x) is <> in the interval
on monotonically decreasing;
When <>, order <>
The solution is <>
And <>
time, <>
When <>, <>
Therefore, f(x) is <> in the interval
On monotonically decreasing, in the interval.
on monotonically increasing;
In summary, when k=0, f(x) is <> in the interval
The upper monotonically increases, and f(x) is <> in the interval
on monotonically decreasing;
When k=0, f(x) is <> in the interval
On monotonically increasing, in the interval <>
On monotonically decreasing, in the interval.
on monotonically increasing; When <>
, f(x) is <> in the interval
On monotonically decreasing, in the interval.
On monotonically increasing, in the interval <>
on monotonically decreasing;
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Anonymous users2024-02-06(1) When <>
, the function <>
Monotonically increasing on the <>, when <>
, the function <>
The monotonically increasing interval is <>, and the function is <>
The monotonically decreasing interval of is <>
<> test question analysis: This question comprehensively examines the mathematical knowledge and methods of functions and derivatives and the use of derivatives to find monotonic intervals and maximums, highlighting the comprehensive application of mathematical knowledge and methods, the ability to analyze and solve problems, and the examination of classified discussion ideas and transformation ideas. The first question is to write <> first
Analytical, find the <>, discuss the parameter <>
of positive and negative, solution inequality, <>
<> monotonously increasing and <>
<> monotonically decreasing; In the second question, the known conditions are first transformed, which are equivalent to <>, so this question examines the maximum value of the function, which is <>
Seek guidance and make <>
The root is obtained, the given definition domain is broken into a list, the monotonicity is judged, and the maximum value is obtained. The third question is to transform the question into a <>, using the conclusion of the first question to <>, so <>, that is, <>
Heng was established, that is, <>
Constant establishment, so the key to this question is to seek <>
maximum. Analysis of test questions: (1) <> should be <>
, the function <>
Monotonically increasing on the <>, when <>
time, by the <>
<>, the function <>
The monotonically increasing interval is <>
<>, the function <>
How would you rate this?
Put away the <>
Let the function , where1) Discuss in.
Let the function f(x)=alnx+(x-1) (x+1), discuss the function f....
Known Functions ,1) discussed.
Let the function f(x)=x-1 x-alnx(a r) (1) discuss the function.
Let the function fx=x 1 2ln x discuss the monotonicity of the function fx.
Known functions , 1) try to discuss the single function of .
Known function , 1) If , let the function.
Known Functions1) When and ,, try the sub-expression containing .
What are the early symptoms of Helicobacter pylori infection?
Why is South Korea a nation**?
Does washing your hair with water really make bald head thicker?
What are some interesting trivia in life?
Individual and corporate infringement complaints.
Illegal and harmful information, please select below and submit.
Category: Pornography, vulgarity.
Suspected of violating the law and committing a crime.
Current political information is not true.
Spam ads. Low-quality irrigation.
We will notify you of the report result as soon as possible through message, email, etc. Illustrate.
Submit for cancellation. Claim your rewards.
My wealth is worth it.
Redeem the goods. Go to Login My Cash.
I got the withdrawal.
Go log in and do the quest to open the treasure chest.
Cumulative completion. 10 tasks.
Slightly, slightly....50 tasks.
Slightly, slightly....100 tasks.
Slightly, slightly....200 tasks.
Slightly, slightly....The task list is loading.
Newbie help. How to answer the question.
Gain and use wealth value.
How to play. Know**.
Know the team. Gang Gang Partner Certification.
High-quality Q&A.
Your account status is normal.
Complaints and suggestions. Feedback.
Appeal: Report of illegal information.
Know the protocol. Corporate promotion.
Auxiliary mode.
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Anonymous users2024-02-051) Collapse <>
Define the maximum value within the domain next to the source for the <>;
<> in its defined domain
There is no minimum value in it.
2) Proof omitted.
(1) When <>
time, <>
<> in its defined domain
The inner is the increasing function, and there is no maximum; ......1 point.
When <>, <>
By <> "And <> time, <>
Increment within <>; <>
time, <>
It decreases within the <>, so it <>
is the maximum value of the <> in the defined domain;
<> in its defined domain
There is no minimum value in it. 4 points.
2) Easy to prove by mathematical induction. …Hail accompanies oak .........8 points.
When <>, it is <> from sub-question (1).
The establishment of <> Heng is known by the <>
So <>
So <>
Apparently <>
Because <>
So <>
time, <>
So <>
Comprehensive knowledge is <> everything
14 points.
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Anonymous users2024-02-04) to define the domain <>
1 point. <>
When <>, <>
<> monotonically decreasing;
<> monotonously increasing and <>When <>
time, <>
<> monotonously increasing and <>4 points.
By <>
The <> makes known functions <>
5 points. <>
When <>, <>
7 points. When <>
time, <>
<> monotonically decreasing;
time, <>
<> monotonously increasing and <>8 points.
That is<> "In <> monotonically decreasing, 9 points.
On the <>, <>
If <> Heng is established, it will be <>
10 points. This question examines the use of derivatives in research functions. The use of the sign of the derivative to determine the monotonicity and the use of extreme and most chaotic values.
1) In the first question, the parameter a should be classified and discussed, and the derivative symbol should be determined to determine its monotonic interval.
2) If the inequality is constant next to the source, the constructor solves the maximum value of the function to hail the oak.
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Anonymous users2024-02-03(1) When <>
time, <>
On <> is an increment function; When <>
time, <>
On <> is an increment function;
On <> is a subtractive function.
Question Analysis: Solution: (
2 points. When <>
There is always a <>
then the <> is an additive function on the <>; 4 points.
When <>, when <>
time, <>
then the <> is an additive function on the <>;
When <>, <>
then the <> is a subtraction function of 6 points on <>.
To sum up, when <>
time, <>
On <> is an increment function; When <>
time, <>
On <> is an increment function;
On <> is a subtractive function. 7 points.
From the meaning of the title to the <> of arbitrary
When <>, there is always <>
Established, equivalent to <>
Because <>
So <>
From ( ) to know: when <>
time, <>
On <> is a subtractive function.
So <>
10 points. So <>
i.e. <> because of <>
So <>
So real numbers <>
The value range is <>
12 points. Comments: It mainly examines the use of derivatives in research functions, which is a basic question.
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Anonymous users2024-02-02I don't have a problem here.
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Anonymous users2024-02-01<> monotonously increases in the <> and in the <>
Monotony is reduced. <>
1) Determine the domain of the function and then find the derivative <>
Solve inequalities within the defined domain of the function <>
and <> to find the monotonic interval (2) according to the monotonicity of the first questionf（x1-f（x2|≥2|x1
The domain of x2 is (0,+.)
When <>, <>
0, so <>
In (0,+ monotonically increased;
When <>, <>
0, so <>
At (0,+ monotonically decreased;
When -1 <>
At 0 o'clock, the order <>
0, the solution is <>
then it should be <>
time, <>
time, <>
Therefore, the <> increases monotonously in the <>, and in the <>
Monotony is reduced. Let's assume <>
And <>-1, known by ( ) in (0,+ monotonically decreased, thus.
<> equivalent. <>
The <> is <> equivalent to <>
At (0,+ monotonically decreased, ie.
Thus <>
The value range of the <> is <>(-.)
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