C language array applet problem. C language array problem.

In the whole main function, only this one variable, whether it is the first for or the second for, is the same i, the second for will have i=-1, in the case of i= -1, and printf("%d ",a[i]);Statement. So fear not! When there is no second for the case:

After the first for is executed, i has become 10, but the size of your array is 10, if i is 10, it points to the 11th position of your array, your subscript is out of bounds, and the consequences of crossing the line will cause your program to crash, but now there is no crash, the output must be garbled code, -36 is just a superficial phenomenon, in fact, a[10] is an indefinite number, it may be -36, or it may be other numbers. Summary:1

To check subscripts, subscripts that go out of bounds is a common mistake made by programmers, resulting in system crashes, memory leaks, and sometimes looking for a long time without finding the problem. 2. In the for statement, even if there is only one statement, add {} to develop good programming habits!

The output must be the value of a[i] in the second for will not appear i = -1, your i > = 0 has been given a limit is not -36, if there is no second for, the output value must be 9, do you check whether other places have done other operations for a[i]?

It's the ia in the second for, and the second for will have i = -1, but it's only executed in the background program The output is only stopped until a[0], and the third case is not clear.

The first dimension of a two-dimensional array can be omitted, but the second dimension cannot be omitted, and the value of the first dimension can be obtained by assigning the value of the second dimension and the array.

In this problem, there are 10 array elements, 10 5=2

Thus, it can be seen that the first dimension is 2 choices b

Select B 2

9 elements are defined, and the size of the second dimension is 5, so the size of the first dimension is 2

The initial value of array c is 0.

The array s is then recycled to compute the value of array c.

i=0, c[s[0]]+c[1]++0++i=1, c[s[1]]+c[2]++0++i=2, c[s[2]]+c[3]++0++ and so on, the array c[1] is ++ 4 times, c[2] is performed 3 times, c[3] is performed 3 times, c[4] is performed 2 times.

Answer: B

This is the count sorting.

The sentence c[s[i]]+ is the number of s[i] counts.

Specifically, for example, if s[i]=1;

c[s[i]]=c[1], then the following is ,..s[i]=4; c[s[i]]=c[4];

c[s[i]]+ is the number of s[i] counted.

for(int i=1; i<5;i++) outputs the number of 1, 2, 3, and 4 in turn.

printf("%d ", c[i]);

It is the number of numbers corresponding to the output s[i].