Knowing that x square 3x 1 0, find the fourth power of x square x 3x square 1

The question is unclear about the fourth power of x-3x square.

The analysis is as follows: Bi slow burning:

x x 2-3x+1=1 gives x 2-4x+1=0, x 2,=4x-1 generation x 2 x 4-9x 2+1=4x-1 [4x-1][4x-10]+1=4x-1 4x 2-44x+11

4x-1 -28x+7=-1 Repentance 7 adopts the method, which does not respect the generation.

Summary. It is known that x-square-x-1=0+, then the cubic of x +2xsquare-4x-2018

x^2-3x+1=0

Both sides are divided by x:

x+1/x = 3

x+1 x) 2 = 9 [where represents the power] x 2+1 x 2+2 = 9

x^2+1/x^2+1 = 8

1/(x^2+1/x^2+1) = 1/8x^2/(x^4+1+x^2) = 1/8x^2/(x^4+x^2+1) = 1/8

Search the code module x 2+3x+1=0 with x on both sides of the world to obtain: x+3+1 x search module calendar 0

So, x+1 x -3

Square both sides, get: x 2 + 2 + 1 x 2 9

x^2+1/x^2＝7

x^4+1/x^4=(x^2+1/x^2)^2-2=49-2=47

x+1 x=3 squared on both sides to get x +1 x =7 Multiply x on both sides to get the fourth power of x +1=7x and add x to the same power on both sides to get x to the fourth power +x +1=8x

And because x +1 x =7 gives x =(7+3 5) 2 or (7-3 5) 2

Thus the fourth power of x +x +1 = 28 + 12 5 or 28-12 5

x+1 x=3, then x -3x+1=0, i.e. x = 3x-1

x4+x²+1=（3x-1）²+3x-1）+1=9x²-3x+1=27x-9-3x+1=24x-8

The formula x -3x+1=0 can be calculated with a formula to calculate the value of x, which can be substituted for 24x-8.

(14 plus minus 6 times root number 5) (3 plus or minus root number 5).

From x+1 x=3, we get x 2=3x-1

x^4+x^2+1=(3x-1)^2+x^2+1=10x^2-6x+2=10(3x-1)-6x+2=24x-8=8(3x-1)=8x^2

It seems that the non-solvable equation x 2 = 3x-1 is indispensable.

x+1 x=3, multiply both sides by x to get: x 2-3x+1=0 So: x 2+1=3x, square both sides get:

x 4 + 2 x 2 + 1 = 9x 2 so x 4 + x 2 + 1 = 8x 2 = 8 (3x-1) = 24x-8 in x 2-3x + 1 = 0 combined with the root formula to obtain x = 3 plus or minus the root number 5, and the result is 28 plus or minus 12 root number 5

x+1 x=3 x=—1 2 Substituting x=—1 2 into the fourth power of x x +x +1 yields: x x to the fourth power +x +1=4 21

Solution: x+1 x=x x+1 x=3 x=1 2 x 2 x 4+x 2+1=five and a quarter.

x+1 x=3 square x +1 x =7 x cannot be equal to 0 if not, 1 x is meaningless.

And because (x to the fourth power+x +1) x =x +1+1 x =7+1=8

So x x to the fourth power + x +1 = 1 8

x+1 x=3, so x 2 + 1 x 2=(x+1 x) 2-2=7

Obviously, x is not equal to 0, and the numerator and denominator are divided by x 2 at the same time to obtain x x to the fourth power + x +1 1 [x 2 + 1 + (1 x 2)] = 1 8

Solution: x+1 x=2,(x+1 x) =4x +2+1 x =4

x +1 x = 2, both the numerator and the denominator are divided by x ) the original formula = (x +m+1 x ) 3x+m+3 x)(2+m) (6+m)=5

2+m=30+5m

4m=-28

m=-7。Note: The conditions for this question are: x +1 = 2x, (x-1) = 0, x = 1.