-
Anonymous users2024-02-08Let the specific heat capacity of the water be c
The kettle volume is v
The density of water is p
Establish the equation pvc*(100-18)=i 2*r*t, that is, only the power i 2*r=pvc*(100-18) t can be found, and the current i and resistance r cannot be found.
-
Anonymous users2024-02-07Your topic is incomplete and not easy to calculate, how much is a jug of water?
-
Anonymous users2024-02-061)i=p/u=1280/220=
2)p=ri^2
The solution is r=ohan.
3)q=(t1-t2)cm
m=1kgc=4200j/(kg·℃）
Q = (100-18) 4200 1 344400J effective power P1 = Q T = Q 350 984W Actual power p 210 2
Productivity = (p1 p) 100
-
Anonymous users2024-02-05The specific heat of the water taken c = 4200 wct = pt = uit = u 2 r t w is the water quality c is the specific heat t t is the temperature difference t time p power.
i=p/u=1280/220=
p=i 2r=u 2 r r=u 2 p=boiling water wct=1*4200*82=344400 kettle u 2 r t=210 2 *350=efficiency=344400
-
Anonymous users2024-02-04Boil water to 100 for 5 minutes? The time when the water temperature is above 60 during the boiling process is about a minute.
-
Anonymous users2024-02-03Didn't ** huh? The power and rated voltage of the electric kettle should be marked out1) The heat absorbed by the water is: Q absorption = C water * M * δt = degrees Celsius) * degrees Celsius = 2) Assuming that the rated voltage of the electric kettle is U amount, then the actual voltage of the circuit u real = u amount * actual power p rated power p = u amount * 50 (revolutions min) * 60 (min) 3000 revolutions = u amount, therefore, the actual voltage of the circuit is u amount.
3) Assuming that the power of the electric kettle is p (in w), then according to the heat absorbed by the water = electricity consumption, there is:
Q=C*M*Δt=P (unit W)*T (Unit H)*So: Time t=C water*m*δt (P*Celsius)*Celsius (P*Put the power and rated voltage on the nameplate of the electric kettle into the result, I hope it can help you!)
-
Anonymous users2024-02-02Solution: (1) The mass of water is m = v = 1000
The heat absorbed by water q=cm(t-t0)=4200 (2) The electric energy consumed by the electric kettle w = 1 3000 50kwh = 1 60kwh = 60000j
The power of the electric kettle p=w t=60000 60w=1000w(3) the time to boil a pot of water t=w p=604800 1000s=
-
Anonymous users2024-02-01It is obtained by q suction = cm (t-t0).
M=Q absorbs the history of the eggplant and exacerbates the socks C(T-T0) 3kg
-
Anonymous users2024-01-31y=ax+b...When x=0, y=25, b=25....y=100, x=5, a=15
y=15x+25...y=60, x=7 for 3 min.
1) How long does it take for the water temperature to stay above 60 during this process?
2(5-x)+1=2*8 3+1=19 3 minutes (2) How long did it take to boil water until the water temperature returned to 25?
2*5+1=11 minutes.
-
Anonymous users2024-01-30Solution: p=ui
The normal working current of the teapot is i=
p amount u amount.
1100w\ 220v =5a；Split the head button.
= m v The heat absorbed by water is q=cm t=c v Qin Bi t=;
q w consumes electrical energy w=
q \ηx80% =
p=w \t
The heating time is t=
w p = 1100w travel.
So the answer is: 5;;
-
Anonymous users2024-01-29It will take more than ten minutes @ please please!!
-
Anonymous users2024-01-28Q suction = cmδt =
Electricity consumed =
Answer: If 70% of the electricity consumed is converted into heat absorbed by water, then the electricity consumed to boil the kettle of water is.
-
Anonymous users2024-01-27Solution: m=5kg The change in temperature is 85 degrees Celsius q=c·t m=6th joule multiplied by 10.
q = w multiplied by 70% w = multiplied by 10 to the 6th joule.
A: It is necessary to absorb heat for ......
The electricity consumed is .........
In fact, to do this kind of question, you can look at the unit. The unit of c indicates that q=c·t m
-
Anonymous users2024-01-26Solution: From the problem, it can be seen that v1 = 100 v2 = 15 70% by the formula:
q=mc(v1-v0) obtains:qwater=5kg*j is obtained by the formula: =qwater, w:
Electricity = 70% then W electricity = J A: Electrical energy required: J
-
Anonymous users2024-01-25At standard air pressure, the boiling point of water is 100. So, the elevated temperature δt = 85.
The amount of heat that needs to be absorbed is q=cmδt=1785000J
The amount of electrical energy that needs to be consumed is w=q 70 =2550000j.
-
Anonymous users2024-01-241) From the nameplate of the electric kettle, it can be seen that when the kettle is working normally, p=1280w, u=220v, and i=p is deformed from p=ui
u1280w
2) by p=u
r = up(220v).
1280w3) by p=u
r is plural. u2 real.
r(210v)
4) According to p=w
If you want to determine the power of the electric kettle, you must first measure the electric energy consumed and the power on time, so the experimental equipment required: timer and electric energy meter
Answer: (1) The current of the kettle when it is working normally is.
2) The resistance of the heating wire of the electric kettle is.
3) The power of the electric kettle is spike back.
4) Experimental equipment should be prepared, such as a hole touch timer and an electric energy meter
When using, that is, be careful not to be electrocuted, and do not fill too much water, if it exceeds the upper limit of the liquid level specified in it, there may be problems. Personally, I think that the details of the electric kettle are more reflected in the choice when buying. When buying an electric kettle, you must look at the material, and many electric kettles on the market are made of high manganese steel and 304 stainless steel. >>>More
In general, the volume ratio of rice and water is:
Rice: Water In other words, one serving of rice, one and a half parts of water is enough, and the cooked rice is the same as in the TV commercial. The rice grains do not stick to each other, and the water absorption is full, and the rice fragrance is rich. >>>More
No, the word is just a word in the word.
For example, buckets and sewage are both water words. >>>More
This is because when water and minced meat are frozen, the coagulation temperature of water solidification into ice and minced meat jelly is different, and the water solidifies into ice below 0 degrees Celsius, and when it is frozen in the refrigerator, the water has solidified into ice, and the minced meat has not yet begun to solidify, so there will be water separated from the minced meat into ice, and when it is taken out of the refrigerator, it will come out and the water and meat will separate.
When I was <>a child, I lived in my hometown, and one of my favorite snacks is "Liangfen" every week on vacation, I will follow my mother to catch up with the market, mainly because I want to eat Liangfen, we ** are even days when they are in the market, there is no one in the singular number, anyway, you can eat once a week, in the summer is generally to eat cold salad, in winter to eat fried, all year round to eat, not only I like to eat, many friends like to eat, eating cold powder with a baked cake is the coolest, Later, when I grew up, I went out to work and rarely ate this kind of jelly, just a few days ago in the supermarket I saw that there was a buy authentic pea jelly, I bought two packs and came back to make jelly, the taste is really good, the following will tell you the steps and methods of jelly. >>>More