Math than the application of the problem, tomorrow to be handed in, so please as soon as possible

Soccer: (390-10) 7 (7+5+7)=140 (pcs) Volleyball: (390-10) 5 (7+5+7)=100 (pcs) Basketball:

390-150-100 = 150 (pieces) of the medicine accounts for one hundred and one (1 201) kilograms of the potion is equal to 4020 grams, and 40200 times 201/1 is equal to 200

Final answer: 200 grams.

Column equations and whatevers are the least technical

Soccer: (390-10) 7 (7+5+7)=140 (pcs) Volleyball: (390-10) 5 (7+5+7)=100 (pcs) Bad balls: 390-150-100=150 (pcs).

If there are 7x footballs, then 5x volleyballs and 7x+107x + 5x + 7x +10 = 390x = 20

So. Football 140

100 in volleyball and 150 in basketball

Solution: Suppose there are 7x footballs, (7x+10) basketballs, and 5x volleyballs.

This yields: 7x+(7x+10)+5x=3907x+7x+10+5x=390

x=20 There are 140 for football, 150 for basketball, and 100 for volleyball (oh

1.A kind of brine, the mass ratio of salt to water is 1:25, how many grams of salt can be prepared into such a brine?

Analysis and Solution: It can be known from the problem setting.

Salt water Brine.

As can be seen from the above, grams of brine can be prepared.

2.The ratio of the number of boys to girls in the fifth grade of Tsing Wan Street Primary School is 13:12 It is known that there are 3 more boys than girls in the fifth grade, how many students are there in the fifth grade of this school?

Analysis and Solution: It can be known from the problem setting.

Boys and girls altogether.

The number of people per serving is 3 (13-12)=3.

Therefore, there are 25 3 = 75 students in the fifth grade.

3.The degree ratio of two acute angles of a right triangle is 7:8, how many degrees are these two acute angles?

Analysis and Solution: From the problem design, it can be seen that the sum of the degrees of these two acute angles is 90 degrees.

90 (7+8) 7=42 degrees.

90 (7+8) 8=48 degrees.

1.It is possible to prepare x grams of such brine.

1：（1+25）=：x

Solution: x=403

So 403 grams of such brine can be prepared.

2.According to the title, if there are 13x boys and 12x girls, then 13x--12x=3 will be solved to get x=3

So 13x+12x=25x=25*3=75Answer: There are 75 people in total.

3. Set two acute angles of 7x and 8x respectively

then 7x+8x=90

The solution is x=6

So the two acute angles are 42 degrees and 48 degrees, respectively.

It can be mixed with x grams of such brine.

25*x=2, there are x girls in the fifth grade.

13/12=（x+3）/x

13x=12（x+3)

13x=12x+36x=36

A: There are 105 students in Grade 5.

3. Set two acute angles, one for 7x and one for 8x

7x+8x+90=180

15x=90

x=67x=6*7=42

8x=6*8=48

A: One angle is 42° and the other angle is 48°

1.g) A: Can be prepared into grams of such brine.

2.13-12=1 1*3=3 (person) 3*13=39 (person) 3*12=36 (person).

39 + 36 = 75 (people).

A: There are 75 students.

3.7+8=15 180 degrees 15=12 degrees 12 degrees * 7 = 84 degrees 12 degrees * 8 = 96 degrees.

A: These two acute angles are 84 degrees and 96 degrees, respectively.

people, including 39 boys and 26 girls.

3.They are 48 degrees and 42 degrees.

The average score of the three people is 80 points, and the total score is 80*3=240 because the score ratio of the three people is 5:3:4

If Zhang Hua, Zhao Ming and Li Li score 5x, 3x, and 4x respectively, then 5x+3x+4x=240, you can get x=20

So Zhang Hua scored 5x=100, Zhao Ming scored 3x=60, and Li Li scored 4x=80

Solution: Let Zhang Hua, Zhao Ming and Li Li score 5x, 3x, 4x5x+3x+4x=80*3 respectively

Get x=20, so 5x=100

3x=604x=80

The total score of the three is: 3 80 = 240 points.

Zhang Hua's score is: 240 5 (5+3+4)=240 5 12=100 pointsZhao Ming's score is: 240 3 (5+3+4)=240 1 4=60 pointsLi Li's score is: 240-100-60=80 points.

1.Copper = 400*5 (3+5), tin = 400*3 (5+3).

2.Milk candy = 720*4 (4+3+2), fruit sugar = 720*3 (4+3+2), halva = 720*2 (4+3+2), 3Let the number of people in the first group be A, the second group is B, and the third group is C, and a total of d trees should be planted, and the first group should plant trees: D*A (A+B+C) trees.

The second group should be planted: d*b (a+b+c) trees.

The third group should be planted: d*c (a+b+c) trees.

1. Copper: 400 5 (5 + 3) = 250 kg Tin: 400 3 (5 + 3) = 150 kg.

2 questions, toffee: 720 4 (4 + 3 + 2) = 320 kg fruit sugar: 720 3 (4 + 3 + 2) = 240 kg halva: 720 2 (4 + 3 + 2) = 160 kg 3 questions, the conditions are incomplete.

1. Set copper to 5x tin to 3x

5x+3x=400

8x=400

x=505x=50*5=250

3x=50*3=150

2. Set 4x toffee 3x fruit candy x halva 2x

4x+3x+2x=720

9x=720

x=804x=80*4=320

3x=80*3=240

2x=80*2=160

3. I don't understand that the question is the whole course