How to determine the single digit of 7 to the power of 1995

Answer: 7, 9, 3, 1 ,,, correspond to 95 divided by 4, and the remaining 3 digits are 3

7)1 = 7 (7)2 = 49 (7)3 = 343 (7)4 = 2401 So, the single digit of (7)4 is imaginary = 1 (7)1997 = 7)(1996 + 1) =7)1996 x (7)1 = 7)4]499 x 7 Therefore, the single digit of (7)1997 = 7)4]The single digit of 499 x 7 = 1)499 x 7 = 7

7 1997 = >7 4) 499*7 = > closed flame (2401) 499*7 =>1 499*7 =>1*7 =>7

The single digit to the power of 8 is 8

The single digit to the 2nd power of 8 is 4

The number of the first 3rd power of 8 is 2

The single digit to the power of 8 is 6

The single digit of 8 to the 5th power is an 84-bit loop.

The single digit of 1998 to the power of 1999 is the same as that of 8 to the power of 1999, and the single digit of 8 to the fourth power is 6, and the single digit of 8 to the 8th power is also 6

8 to the power of 1999 = 8 to the power of (4 * 2499 + 3) to the power = 8 to the power of (4 * 2499) * 3 power of 8.

The single digit is the same as 6*8 to the 3rd power, which is 2

The same can be obtained:

The single digit of 1999 to the power of 1998 is the same as the power of 1*9 to the power of 2, which is 1

The result after the most scattered bridge is: 2*1=2

The mantissa of 7 1 is 7

The mantissa of 7 2 is 9

The mantissa of 7 3 is 3

The mantissa of 7 4 is 1

7, 9, 3, 1 cycles.

99/4=24……3 So the mantissa of 7 99 is the same as 397, just look at the single digit, 8, 3, 2, 97 to the n power of the single digit is ......The single digit is a sequential cycle.

Therefore, the mantissa of 3, 1, 97 and 1 in the single digit is 7

The mantissa of 97 2 is 9

The mantissa of 97 3 is a swim 3

The mantissa of 97 4 is 1

7, Bishen 9, 3, 1 cycle.

99/4=24……3 So the mantissa of 97 99 is 3x y is to the y power of x), 0, look at the single digit.

7*7=9 digits

7 x 7 x 7 = single digit 3

7*7*7*7=Single digit Shen Huibi 1

7*7*7*7*7 = single digit 7

7*7*7*7*7*7*7=Unit 9

Four in a cycle

The answer is 1,0,

3*3*3*3=81, after multiplying every 4, the number of people is 1, 1998 = 4*499 + 2, so it should be 3*3 9, and the number of multiplication and branches is the number of 1 at the end of the multiplication, and the result is 9

The single digit of 3 times the power of 1994 multiplied by 7 to the power of 1995 multiplied by the power of 13 of 1996 is the single digit of 9*3*1=27, which is 7

The single digit to the power of 8 is 8

The single digit to the 2nd power of 8 is 4

The single digit to the power of 8 is 2

The single digit to the power of 8 is 6

The single digit of 8 to the 5th power is an 84-bit loop.

In 1995, the number of power units was 5, in 1996 the number of power units were 6, and in 1997, the x power were ...loop, when x = 1997, 1997 4 = 499 and 1, that is, the 1997 power of 1997 is 7, and the y power of 1998 is .loop, when y = 1998, 1998 4 = 499 remainder 2, that is, the 1998 power of 1998 is 4

5+6+7+4=22, so the last digit in parentheses is 2

The mantissa law of the power of 2 is: 2 1=2, 2 2=4, 2 3=8, 2 4=16, 2 5=32, 2008=4*505 is a multiple of 4, so (1995 to the power of 1995 + 1996 to the power of 1996 + 1997 to the power of 1997 + 1998 to the power of 1998) The single digit of the value of the power of 2008 should be 6

6 It's not a guess, you need a process to ask.