A math rookie s question, a math problem, a rookie is cautious

Differential calculus is actually very easy to learn, the key is to understand the geometric meaning of differentiation and differentiation, the minimum of preparatory knowledge is element theory, limit theory, number series, functions (just get a calculus book must be elemental theory at the beginning), and buy a book on calculus, I feel that basically the books of calculus are basically the same, it is recommended to use some books from famous schools, such as Tongji or Tsinghua, cattle people write cattle books, this is not acceptable. It is best to get this exercise and exercise problem solution, just say that you can't practice, especially the calculation of differential, each problem must be trained, because the later integral is the inverse of the differential operation, and it is impossible to understand it if you don't understand it. **I really don't know.,Actually, it's good to read the book carefully.,If you don't dislike it, you can leave a message or email me.,I used to help people who didn't understand a little bit too high the day before the exam.,I don't dare to say it.,But help you straighten out your thinking.,It's okay to answer some questions.,But I do have the courseware I left over from class.,If you need to, you can pass it to you.。

If you are interested, you can send me an email Of course, all the premise is that you are willing, and I also saw it at the beginning of high school, and I took a lot of detours at the beginning, haha, it made me think of the past.

Hello, calculus is a compulsory course for almost all majors in college, I mean you have to learn sooner or later, and personally, (I'm a math major), calculus is really simple, maybe some theorem proving process may not be very clear, if you do it purely to do the problem, the medium problem is a small case, the middle can think about it, and the upper one is not easy to say. Now that you're a freshman in high school, you can go to the bookstore and look at the college calculus textbooks, which are more useful than anything else.

Hope the above can help you a little.

Sorry to read wrong.

Then I'll do it in an easy way.

Because x1-y1=2 and x2-y2=2 so x-y=2 x=2+y

Substituting it gets: y 2+4y+4+m 2(y+2)+n=0, so y 2+(4+m 2)y+(2m 2+n+4)=0, because y 2+5my+7=0 so 4+m 2=5m ,2m 2+n+4=7 (corresponding to the equal coefficients) so m=1 or 4 can be excluded by the eradication discriminant 1 so m=4, n=-29

Solution: x1 - y1 = 2, x2 - y2 = 2 The addition of the two formulas obtains: (x1+x2)-(y1+y2)=4x1+x2=-m 2, y1+y2=-5m, substituting the above equation m 2-5m+4=0

m=4 (you've already figured out 1 to exclude).

x1=2+y1,x2=2+y2

n=x1*x2=(2+y1)(2+y2)

4+2(y1+y2)+y1*y2

where y1+y2=-5m=-20, y1*y2=7, so n=4-40+7=-29

167 calculated the steps of m=4 and didn't write it, and the guy in front of me was also done.