Ask a few math questions and ask one math problem

1) Let each cow eat x kg of grass per day, and each sheep eat y kg of grass per day.

This gives 8x+3y=136

2x-3y=4

The solution is x=14 y=8, that is, each cow eats 14 kg of grass per day, and each sheep eats 4 kg of grass per day.

2) Set x yuan for each piece of soap and y yuan for each towel.

3x+4y=

5y-3x=

The solution is x= y= i.e. each piece of soap and each piece of towel.

So each bar of soap is cheaper than a towel.

1.Let's say that each cow eats x kg of grass per day and each sheep eats y kg of grass per day. The column binary system of equations is as follows:

8x+3y=136

2x-3y=4

The solution is x=14 and y=8

A: Each cow eats 14 kg of grass per day and each sheep eats 8 kg of grass per day.

2.Set $x for each bar of soap and $y for each towel. The column binary system of equations is as follows:

3x+4y=

5y-3x=

The solution gives x=, y=, then y-x=

A: Each bar of soap is cheaper than a towel.

1。Set 3 sheep to eat x kg of grass per day.

then there is x+(8 2)*(x+4)=136

The solution is x=24

So 2 cows eat grass 24 + 4 = 28 (kg) per day, so a sheep eats grass 24 3 = 8 (kg) per day

A cow eats grass 28 2 = 14 (kg) per day

2。Each bar of soap is cheaper than a towel.

Then 3 towels are 3x yuan more expensive than 3 pieces of soap, so the total value of 2 towels is (so (

The solution is x=

1.Let's say that each cow eats x kg of grass per day and each sheep eats y kg of grass per day. Get the system of equations:

8x+3y=136

2x-3y=4

The solution is x=14 and y=8

2.Set $x for each bar of soap and $y for each towel. Get the system of equations:

3x+4y=

5y-3x=

The solution gives x=, y=, then y-x=

Each bar of soap is cheaper than a towel.

1.Solution: Let each cow eat x kg of grass per day, and each sheep eat y kg of grass per day.

8x+3y=136

2x-3y=4

The solution is x=14 and y=8

Answer: Slightly. 2.Solution: Set each bar of soap for x yuan and each towel for y yuan.

3x+4y=

5y-3x=

Solution: x=, y=

is cheaper. Answer: Slightly.

1) Solution: If the sheep eats x kg of grass every day and the cow eats y kg of grass every day, then the equation can be obtained according to the meaning of the question

3x+8y=136

2y-3x=4

Solution, we get: {x=8 y=14.}

After testing, it is in line with the topic.

A: ......2) Solution: If the soap is a piece of x yuan and the towel is a piece of y yuan, then the system of equations can be obtained according to the meaning of the question:

3x+4y=

5y-3x=

Solution: {x=,y=

After testing, it is in line with the topic.

A: ......

1. A sheep eats x kilograms per day, and a cow eats y kilograms per day.

3x+8y=136 2y=3x+4

y=14 x=8

2. X yuan for each piece of soap and Y yuan for each towel.

3x+4y= 5y=3x+

y= x=cheap yuan.

Let's say each cow eats x kilograms per day and each sheep eats y kilograms per day.

can be obtained. 3y+8x=136（2）

2x-3y=4（1）

1)+(2) got.

2x-3y+3y+8x=136+4

10x=140

x=14 substituting x=14 into (2) to obtain, 2*14-3y=4 y=8A: Each cow and each sheep eat kilograms of grass per day.

Suppose soap is $ x and towel is $ y.

3x+4y=

5y-3x=

1)+(2) got.

9y=y=substitution[2]x=

So each bar of soap is cheaper than a towel of $?

1.Each cow eats 14 kg of grass and each sheep eats 8 kg of grass.

2.Each bar of soap is cheaper than a towel.

Let the sheep eat x kg per day and the cow eat y kg per day, then 3x+8y=136 2y-3x=4 solution y= x=

The second course is so on.

1-1/2）×-1-1/3）×（1-1/4）×-1-1/5）…-1-1 2003) (1-1 2004) You will find that the listing is 1 2x

3x3/4x-4/5…2003/2004

Multiplication equals 1 2004

9x11111x2x1111-

3x1111x6x11111=0

2. Such a question is a proportional relation.

Each time it is multiplied by 2.

You can just do it upside down.

The opposite, multiplied by 2, finally equals 16

1 (1-4 20) (1 12+1 20) = (16 20) (8 60) = 16 20 * 60 8 = 6 (hours).

2. (284-1*48) (70+48) = 2 (hours) 1. Set the remaining part to be completed in x hours.

x（1/12+1/20）=1-4/20

The solution is x=62, and set B to complete the task in x hours.

x（48+70）=284-48

The solution is x=2

1 Let the remaining A and B cooperate. The rest will be completed in x hours.

1-4*1 20=(1 20+1 12)*x set B to cooperate with A again, and B completed the task in x hours.

284-48=（48+70）*x

1.Set the remaining part to be completed in x hours.

1/12）x

Set B did x hours to complete the task.

48+70）x=x=2

I understand the first question, why don't I ask the math teacher?

The second question is 16.

Send us the question.

Ask a math problem.

It's best to take a ** ha.

How to shoot**.

It's just that after taking a picture with a mobile phone camera, click on the plus sign in the lower right corner and send it over.

Okay, wait a minute.

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Why did the order fail a?

Ask about custom messages].

Summary. Let's take a picture of the specific topic, classmates.

Let's take a picture of the specific topic, classmates.

Then, if you want to ask for the volume of the bottle, you need to add the volume of water to the volume of the air part.

The volume of water obtained from Figure 1 is: 4 6 = 24 (cubic centimeters) and the volume of air from Figure 2 is a cylinder 2 cm high, and the volume of air is:

8-6) 6 12 (cubic centimeters).

Add the two together to get the volume of the puzzle: 24 + 12 = 36 (cubic centimeters) The equation for the solution process:

4 6 = 24 (cubic centimeters).

8-6) 6 12 (cubic centimeters).

24 + 12 = 36 (cubic centimeters).

A: The volume of the bottle is 36 cubic centimeters.

The symmetry point p' of P is done over o, then F1PF2P'is a parallelogram and o is its diagonal intersection. Vector pf1 + vector pf2 = vector pp'=-2 vector op = vector oq

If q coordinates (x,y), then p(-x 2, -y 2), the following derivation should be understood.

In fact, q is on an ellipse twice as large as the major and minor axes of the original ellipsoid.

Excessive words of the individual with bone gigma.

1、 （1+1）/（1/50+1/70）= 582、（100-86）/（86-84）+1=83、 （24+26+30+34+38+40）/3/4=164、 （45+60+65+70）*3/3/4=6013、 105 85 95 90 。。The integer part of 19 numbers is 91

Question 1: x=7 12 or -(7 12);

y=-2=>x+y=-17 12 or -(31 12) Question 2: y=kx+b

y=bx+k

Take the above two primary functions as a system of equations, and the values of x and y are the intersection points of the two straight lines==> x=1, y= b+k;

Introduction: The image is roughly two intersecting straight lines, and the intersection point is on (1,b+k)Question 3: I think the condition of this problem should be x (x 2-x+1) = 1 3.

then x 2 -x + 1 = 3x

x^2 - 4x + 1 = 0

x-2)^2 -3 = 0

x = √3 +2

Bring it into the equation you want.

x^2／（x^2+x+1）

The result is (2+ 3) 5

x 2-y x 2-xy:

x^2-y^2=（x-y）*（x+y）

x^2-xy =(x-y)* x

Approximate up and down, and subtract (x-y) to get x (x+y)8(m-n) 4/3 (n-m) 2:

4（n-m）^2=4（m-n）^2

Up and down is about 1 2 (m-n).

hectares of grass can feed 11 cows for 10 days, and we can ask Kaichun to launch 30 hectares of grass for 66 cows for 10 days. Similarly, the second plot of 6 hectares can feed 12 cows for 14 days, i.e. 30 hectares can be considered to feed 60 heads for 14 days.

Suppose 1 cow eats one unit of grass in 1 week, so the growth of the pasture in (14-10) days is 60 * 14-66 * 10 = 180 units, so the growth of the pasture in 1 day is 180 4 = 45 units. From this, it is calculated that there are 66 * 10-10 * 45 = 210 units of grass on the 30 hectares of grassland.

Thus, there is 8 hectares of grassland with 210 * (8 30) = 56 units of grass on the pasture, and the increment of 8 hectares of grassland in 1 day is 45 * (8 30) = 12 units.

19 cows on 8 hectares of pasture: 56 (19-12) = 8 days.

So it should be 8 days.