Wire current loss problem? 100

The most fundamental cause of loss is that the wire also has resistance, and according to u=i*r, the resistance of the wire affects the voltage drop.

The drop in voltage obtained by the appliance will also affect the drop in current, which is related to the appliance, not the wire. According to your requirements, if the electrical characteristics of the electrical appliances that are used are unknown, that is, the electrical characteristics of the load, this problem is not possible.

As a simple pure resistance load can be calculated, assuming that the calculation is 220V, 100 meters of line, at room temperature, r = ohm, electrical resistance = 220V 15A = ohm, current after 100 meters = 220V (.

The longer the wire, the more the loss, the same amount of current flowing, and the loss is manifested as heat.

Because the wire is resistant, the longer the resistance, the greater the resistance, and the resistance will consume electricity. This is available in a calculation table and is available online.

Any cable will have a certain resistance, and the size is proportional to the length of the cable. The voltage drop across the cable is equal to the resistance of the cable multiplied by the current. With the same magnitude of current, the longer the cable, the greater the cable resistance, and the greater the voltage drop.

The time is the same current size, the same time, the longer the cable, the greater the cable resistance, the greater the loss.

The loss rate of wires is different for different quota items, for example: copper core insulated wires, lighting circuits, the loss rate is 16% of the gods, according to the provisions of the quota.

The fixed loss rate of the cable is 1%, the cable consumption is 1%, which is the waveform, bending, and radian coefficient, and the wire is taken as an example: 100 + reserved wire length) +.

Power system. The wire and cable products used mainly include overhead bare wires and busbars.

busbar), power cable (plastic cable, oil-paper power cable (basically replaced by plastic power cable), rubber sheathed cable, overhead insulated cable, branch cable (replacing part of the bus), magnet wire and electrical equipment wire and cable for power equipment, etc.

Quality identification:

One has to see. See if there is a quality system.

Certificate of Acknowledgement; See whether the certificate is standardized; See whether there is the factory name, factory address, inspection seal, and production date; See if there are trademarks, specifications, voltages, etc. printed on the wires. It is also necessary to look at the cross-section of the copper core of the wire, and the high-grade copper.

The color is bright, the color is soft and quiet, otherwise it is defective.

Second, we have to try. A wire head can be repeatedly bent by hand, where it feels soft, has good fatigue strength, plastic or rubber feels elastic and the wire is insulator.

If there is no crack on it, it is a superior product.

Dear, hello, I am glad to answer the wire power loss calculation for you, 1. Calculate line resistance: 20, aluminum resistivity: ; Copper, the total length of the single-phase 220V circuit is 2*L, the total length of the three-phase circuit is, and the cross-sectional area of the wire is S, then, the line resistance r = resistivity * total length Line current:

The current value can be measured or calculated, single-phase 220V line current = equipment rated power 220, three-phase line current = equipment rated power rated voltage power factor. 3. Wire loss: Single-phase 220V circuit wire loss power = line current square * r, three-phase circuit wire loss power = line current square * 3 * power factor square * three-phase unbalanced, calculated according to the maximum current.

Calculation of cable engineering quantity loss method 1, no loss is added when calculating engineering quantity. 100m2.(116) in the main material of the 5m lighting wire quota, so whether the unit price is considered according to (116) is considered.

That is, the unit price is multiplied by the coefficient. 2. When calculating the quantity set price, only the reserved amount of the incoming cabinet is considered, and the loss is not considered, and the loss is only added when the material consumption plan is raised. Wire and cable material quota calculation method 3, if the calculated engineering quantity is used for valuation, then the engineering quantity = the length measured on the drawing ten into the reserved amount of the cabinet box, the loss in the set of quota when the main material engineering quantity will automatically change; If it is used as a material quantity plan, then, the engineering quantity:

The length measured on the drawing is the reserved length of the ten-panel cabinet (1 + loss rate), and the loss can not be added when the engineering quantity of pipe threading is calculated, and only the reserved amount that enters the box or connected equipment is added; However, cable laying needs to calculate the laying slack of the cable.

How much is the loss of the wire is reasonable, how much is the loss of the wire transmission line.

Hello dear! We will be happy to answer your questions; The loss rate of the cherry blossom wire is different from the different quota subheadings, for example: copper core insulated wire, according to the Yanming circuit, the loss rate is 16%, according to the provisions in the quota.

The fixed loss rate of the cable is 1%, and the silver consumption of the cable is 1%, which is the waveform, bending, and radian coefficient, and the wire is taken as an example: 100 + reserved wire length) +. The wire and cable products used in the power system mainly include overhead bare wires, busbars (busbars), power cables (plastic cables, oil-paper power cables (basically replaced by plastic power cables), rubber cables, overhead insulated cables, branch cables (replacing part of the busbar), electromagnetic wires and wires and cables for electrical equipment for power equipment.

1. The loss of the wire is mainly related to the current and the resistance of the line. The higher the current, the greater the loss of the wire, and the smaller the current, the smaller the loss of the wire.

The resistance of the line is related to factors such as the material, cross-sectional area, length, and temperature of the wire. Therefore, when the power is increased to 10kw, the current increases, the loss of the wire will also increase, and the line loss of charging 100 kWh of electricity will also increase accordingly. When the power drops, the current decreases, the loss of the wire will also decrease, and the line loss of charging 100 kWh of electricity will also decrease accordingly.

In practice, due to the length of the line, the material of the wire and other factors, the specific value of the line loss will be different.

2: The proportional relationship between current and line loss is: the square of the current is proportional to the line resistance, that is, i 2r=p, where i represents the current, r represents the line resistance, and p represents the line power. The line loss is also proportional to the square of the current, i.e., the line loss is proportional to the square of the current.

According to the information you provide, when the power is increased from 6kw to 10kw, the current will increase, assuming that the current is increased by 2 times, then the line loss will increase to 4 times of the original, that is, the line loss will increase to 80 degrees. In the same way, when the power is reduced from 6kw to, the current decreases, assuming that the current is reduced by half, then the line loss will be reduced to the original 1 4, that is, the line loss will be reduced to 5 degrees.

It is important to note that the line resistance is also affected by factors such as ambient temperature, wire cross-sectional area, and material, so the actual line loss will vary.

There is a certain proportional relationship between the current and the line loss, and the greater the current of the wire, the greater the line loss. This is because the resistance of the wire is constant, and when the current passing through the wire increases, the resistance inside the wire causes the wire to heat up, losing a part of the electrical energy, so the line loss increases.

In your example, assuming that the power supply voltage of the charging pile is 220V, and the power of 6kW is about . If the power is increased to 10kw, the current will increase to about, which will lead to an increase in the line loss of the wire, so the line loss of 100 kWh may increase.

Similarly, if the power drops, the current will be reduced to approximately, and the line loss of the wire may be reduced, so the line loss of 100 kWh of electricity may be reduced.

It should be noted that the line loss is also related to the length, cross-sectional area, wire material and other factors of the wire, so only the current size is not enough to determine the line loss.

The loss of wire is related to factors such as power, current and wire length, wire material, and wire cross-sectional area. If you change the power of the charging pile, the loss of the wire will change.

In general, the loss of the wire is proportional to the square of the current, that is, if the power is increased to 10 kW, the current will increase accordingly, and the loss of the wire will be greater than at 6 kW, rather than the same or less.

If the power is reduced to kW, the current will decrease accordingly and the loss of the wire will also decrease. However, the exact amount of loss depends on factors such as the length, material, and cross-sectional area of the wire.

There is a close relationship between the current and the linear loss, and the proportional relationship between the two can be represented by the generator curve, that is, the abscissa on the curve represents the current, and the ordinate represents the line loss. The larger the current, the greater the resistance of the Duan Feng line; The smaller the current, the smaller the line loss.

The power loss of the wire is calculated as follows:

1. Calculate line resistance: 20, aluminum resistivity: ; Copper, the total length of the single-phase 220V circuit is 2*L, the total length of the three-phase is 2*L, and the cross-sectional area of the wire is S, then, the line resistance R = resistivity * total length S.

2. Line current: the current value can be measured or calculated, single-phase 220V line current = equipment rated power 220, three-phase line current = equipment rated power rated voltage power factor.

3. Wire loss: Single-phase 220V circuit wire loss power = line current square * r, three-phase circuit wire loss power = line current square * 3 * power factor square * r.

4. When the three-phase is unbalanced, it is calculated according to the maximum current.

Use a multimeter to measure the total resistance r of the three wires, calculate the current i = p 380 (p is power, the unit is watts), and the electricity lost (unit is degrees) = i square * r * 10000 degrees 1000p (here the unit of power p is kilowatts). If you don't understand, send me a message.

Hello, the calculation method of wire power loss is as follows: 1. Calculate line resistance: 20, aluminum resistivity:

Copper, the total length of the single-phase 220V circuit is 2*L, the total length of the three-phase is 2*L, and the cross-sectional area of the wire is S, then, the line resistance r = resistivity * total length Line current: the current value can be measured or calculated, the single-phase 220V line current = the rated power of the equipment 220, the three-phase line current = the rated power of the equipment The rated voltage The power factor. 3. Wire loss:

Single-phase 220V circuit wire loss power = line current square * r, three-phase circuit wire loss power = line current square * 3 * power factor square * three-phase unbalanced, calculated according to the maximum current.

Is there anything else I can do to help you.

The data is not all that cannot be calculated, the necessary data:

1》Wire length: L

2》Wire Material: (Copper wire resistivity:,Aluminum wire resistivity:

3》Wire cross-section: S

4》Current through the wire: i

5》Voltage drop due to wire loss: u

Find the resistance of the wire (single wire) according to the wire material, length, cross-section, and passing current

r＝ρ×l/s)

Voltage drop based on wire resistance and passing current (single wire):

u ri to find the wire loss power according to the voltage drop of the wire (single wire).

p＝ui

Resistance value = resistivity * length cross-section (the formula is correct).

However, a 12-volt wire with a voltage of 28 ohms cannot pass a current of 2 amps, and the loss of electrical energy can be calculated using Joule's law, which is the square of the current passed by the resistance * of the wire.

The remaining voltage can be resisted by the supply voltage-current*.

To determine according to the load at the end of the line, calculate the loss of the line, in the electrical calculation is a professional problem, he should consider the internal resistance of the line, the temperature of the use environment, the heat dissipation conditions, the distance of the line, the cross-sectional area of the wire, the type of load at the end, whether it is an inductive load or a resistive load and so on.