Junior high school math is very grateful, and junior high school math is also a problem Thank you

The main purpose of this question is to understand the meaning of the question: it is obvious that this is an application problem of inequality.

Let's first set up x people to grow A vegetables. Then there are 10-x people who grow B vegetables. Just list the inequalities.

Then, the total income of A vegetables is. Type B. To make the total income greater than 10,000, there is.

0＜x≤10)

Solution. 0x≤4

That is, up to 4 people can be arranged to grow A type of vegetables.

I've found a similar answer to your question! There is a specific process, very clear I found it on the "Solution", if you have other questions that you can't, you can go to the "Solution" to search for the answer, I have been using Oh is to hit one or two sentences of the question, you can search, the question bank in it is huge. And you don't need to register, just search directly

The detailed process of solving the problem also writes the test point and the idea of solving the problem.

Hope!!!

Set up x race A and (10-x) race B.

3x x 4A: A maximum of 4 people can only be arranged.

Solution: If x person grows vegetable A, then (10-x) person grows vegetable B.

Solve x 4

A: A maximum of 4 people can be arranged to grow A vegetables.

The answer is D.

This kind of problem is better solved by sine or Yuxuan's theorem.

This problem can be used sine theorem: two same angles correspond to the unified edge ae, in the triangle ade, you can use the sine theorem for dae, dea two angles, you can determine, the sin value of the angle is greater than 0, not equal to 1, not equal, adopt ah pro

Choose a, when the stem proposes the inverse ratio of x+4 and y-3 (the denominator is x+4, and the x coefficient of the numerator and the denominator should be reduced to 3), the selection of a is obtained, and then x=-2 is brought in to obtain y=5, which is true.

As a multiple-choice question, the easiest way to do this question is to substitute x=-2 and y=5 directly to see which of the four options is true.

If it is a big problem, it should be set to x+4=k (y-3).

Substituting x=-2 and y=5 to get k=4

So x+4=4 (y-3).

xy-3x+4y-12=4

xy+4y=16+3x

So y=(16+3x) (x+4).

Choose a, (x+4)(y-3)=k

Substituting yields k = 4

Simplify to get a answer.

To be honest,,It doesn't have to be counted at all... You can see it when you see it... Since FCE is a right angle and EDF is a right angle, the circle with EF as the diameter must pass through C and D, and the smallest diameter of the circle with C and D at the same time is the root number 2, because ACB is an isosceles right triangle, D is at the midpoint of AB, and the circle is drawn with CD, E is in BC, and F is in AC, which must be symmetrical.

It can be found that the small angles inside are all 45 degrees, Cd is equal to EF, and the minimum EF is the root number 2

a＋b＋c＝1,c＝3。Then a b -2. You can change the right -3 of your 5 to -2.

<> the picture touched the game and laughed at Chang La.

Ditch three Zhongyuan empty shares sell blind four Xuan crack answer five!