The relationship between the concentration of the solution and the concentration of ions!!

First of all, it is necessary to distinguish between strong electrolytes and weak electrolytes.

Strong electrolytes are strong acids, strong bases, and most salts.

Weak electrolytes are weak acids, weak bases.

The strong electrolyte is completely ionized, such as Naoh==NA+ +OH - the weak electrolyte is partially ionized (as for how much ionization comes out, it depends on how weak the specific weak electrolyte is) For example, NH3·H20==NH4+ +OH- The smaller the concentration, the greater the ionization, right, but have you ever thought that the concentration will become smaller, although the ionization degree will become larger, but the concentration of ionized ions will become smaller?

Tell you the calculation method of pH: pH = -LG [H+], that is, take the negative logarithm of the concentration of hydrogen ions, and the product of [H+]*OH-} in the solution is a fixed value, so the pH is equal, the H+ concentration is equal, and the OH concentration is also equal, and the decomposition of ammonia monohydrate in ammonia water produces 0H-, not all ionization, so the concentration is unequal.

pH represents the concentration of H+, at the same temperature, H+ in water is the same, then there must be OH- same, pH + POH = 14 at 25 degrees, since PH is the same, then POH must be the same.

H+ concentration = degree of ionization, concentration, both are related.

Ammonia water will continue to ionize OH-, but it also ionizes NH4+, and NH4+ will also be partially hydrolyzed, when ionization and hydrolysis reach dynamic equilibrium (equal), then the pH will not change when it is stable, not that the weak alkali can ionize infinitely.

The pH of the solution is 13, which means that the hydroxide is moles per liter.

Then the remaining Ba(OH)2 is moles per liter.

The remainder ba(OH)2 = mol.

Total BA(OH)2 is molar.

That is, Ba(OH)2 participating in the reaction is molar.

And the resulting barium sulfate is moles, that is, sulfuric acid is moles. The sulfate ion is moles.

Sulfuric acid consumes Ba(OH)2 moles, and the remaining molar Ba(OH)2 is consumed by hydrochloric acid, so hydrochloric acid is mol. Then the chloride ion is the mole.

The hydrogen ion is the sum of sulfuric acid and hydrochloric acid is mole.

So the sulfate ion concentration is moles per liter.

Chloride concentration in moles per liter.

Hydrogen ion concentration in moles per liter.

Analysis: n[ba(oh)2]=

n(baso4)=

ph=13，c(oh-)=

neutralized oh-:n(oh-)=

c(h+)=:1 neutralization).

The SO42- in the original solution all have BaSO4 precipitate:

c(so42-)=

Conservation according to charge.

c(cl-)=

The amount of a substance in solute (denoted by the letter B) is the amount of substance containing solute B per unit volume of solution.

c = n vn (amount of material in solute) = m (mass of solution) mm (mass of solution) = v

The solute mass of the solution = (mass fraction)· density)·v thus, n (the amount of the solute substance) = v m

c= n/v

ωv /m) /v

·v /m v

·m

The amount of the substance of the ion by volume l

The concentration of the solution is the solute solution, and the ion concentration is the ion concentration of zinc ions in the Zn2+ solution, which can be expressed in the following ways:

1. Mass fraction: the mass of Zn2+ The mass of the solution = 1 g 65 287 1001 g = %.

2. The amount and concentration of the substance: the amount of the substance of Zn2+ The volume of the solution = 1 287 mol 1L = 1 287 mol L

Generally, it refers to the amount and concentration of a substance.

The concentration of the solution is the solute solution, and the ion concentration is the ion concentration of zinc ion solution Zn2+, which is expressed in the following ways: 1. Mass fraction.

The quality of Zn2+ is the quality of the solution.

g×65/287

g2, the amount and concentration of the substance.

The amount of Zn2+ substance. Volume of solution.

mol1lmol/l

Note that the "concentration of hydrogen ions ionized by water" and "hydrogen ion concentration ionized by water" in the stem do not represent the concentration of hydrogen ions in the solution.

The addition of hydrochloric acid is divided into three processes:

1. The amount of hydrochloric acid added is not enough to complete the reaction: at this time, hydrochloric acid is added to react with ammonia, which reduces the "inhibition" of hydrogen ions by hydroxide in the ammonia aqueous solution, so hydrochloric acid is added before point C, "It is an ammonium chloride solution, which is acidic after hydrolysis of strong acid and weak alkali salt, and promotes the electrolysis of hydrogen ions by water."

3. When excessive hydrochloric acid is added, the hydrogen ions in the solution will increase, and the concentration of hydrogen ions in the acidic solution will inhibit the water from continuing to ionize hydrogen ions.

pH refers to the concentration of hydrogen ions in a solution, not "the concentration of hydrogen ions ionized by water", so it is not without two neutrals.

Hope, thank you!