The amount concentration of the chemical substance, the amount concentration of the substance

After adding an excess of barium chloride solution, a mixture of barium carbonate and barium sulfate is obtained when the white precipitate is obtained, and then after adding excess dilute nitric acid, all the barium carbonate is dissolved, and the gas generated is carbon dioxide, and only barium sulfate precipitate is left in the solution, that is, the mass of barium carbonate precipitate is.

The relative molecular weight of barium sulfate m = 233, so the amount of barium sulfate substance n = m m = mol is the amount of potassium sulfate substance n =

mol so the concentration of the amount of potassium sulfate in the original mixed solution c = n v = mol l

The relative molecular mass of barium carbonate m = 197, so the amount of barium carbonate substance n = m m = mol is the amount of potassium carbonate substance n =

mol, so the concentration of the amount of potassium carbonate in the original mixed solution is c = n v = 1mol lThe amount of carbon dioxide is equal to the amount of carbonate n=

mol, so v=n*v=

This is the concentration of the amount of push.

c = n v one liter of solution is 1000 ml, 1000* is converted to the total mass of the solution, and w mass fraction is the mass of the solute.

It is the mass of solute contained in each liter of solution, divided by the relative molecular weight to obtain the mass of solute in each liter of solution, which is the concept of molar concentration.

w=s/100+s

It's 100 grams of water dissolved in the solute of s grams, and s is the concept of solubility, and you can bring in the expression of w.

The next one is that the gas is soluble in water.

Put n=v gas 22400

Conversion under standard conditions.

m = 1000 (water) + nxm (solute).

mv (solution) is rolled out every time it is brought in. There is no pen and paper, just talk about the ideas, I hope it will help you.

First of all, it is clear that barium sulfate is insoluble in dilute nitric acid.

Since barium chloride and dilute nitric acid are excessive, sulfate and carbonate can be completely precipitated.

Therefore, the gram precipitation is the mass of barium sulfate, and the relationship between potassium sulfate and barium sulfate can be established, and the concentration of potassium sulfate can be found to be 20mol l

The mass of barium carbonate is the mass of the total precipitate minus the mass of barium sulfate, which is grams, so a relationship can be established between potassium carbonate, barium carbonate and carbon dioxide, and the concentration of potassium carbonate is 100mol l, and the gas produced is.

PS: I think the data in this question seems to be a bit problematic, and the concentration of the solution cannot be so high

mbaco3=

nbaco3=

nco3=n

baco3=

Launch. k2co3=

nbaso4=

So the concentration of the amount of the substance of potassium carbonate is.

The concentration of the substance of the amount of barium sulfate is.

Due to the conservation of the carbon element, n

c=nco3=

vco2=

The addition of nitric acid precipitates a reduction - > BaCO3 dissolves, Baso4 is insoluble in acid, i.e., the amount of Baso4 substance n =

mol Because in the system, SO4 - all ** is ** in K2SO4, so.

The amount of K2SO4 substance.

Concentration c = n v

BAC3 quality.

The amount of the substance is.

Same as above, so K2CO3 concentration.

The gas is carbon dioxide.

co3--x=v=

Concentration of the solution (mol l).

Soluble mass (g).

Melar mass of solute (g mol).

Solution volume (l).

As can be seen from the above formula, the concentration of the solution is directly proportional to the mass of the solute and the amount of solute, and inversely proportional to the volume of the solution.

Number of particles. Avogadro's constant.

The amount of the substance (mol).

Mass (g) molar mass (g mol).

It can also be seen from the above formula that the number of particles in a substance is directly proportional to the quantity and mass of the substance.

1 pc. cacl2

There is one Ca2+ and two Cl-, so the concentration of Ca ions in the solution is the same as CaCl2, and the Cl ions are 2 times that of CaCl2, Answer:

2mol/l

CaCl2 solution of Ca ions and Cl ions.

The amount of concentration of the substance.

2mol l respectively

4mol/l

The amount of substances of Ca ion and Cl ion is: N(Ca)=CV1molN(Cl)=CV

Number of mol particles.

n(ca)=n(ca), respectively

n(cl)=n(cl)

1. Molarity concentration molarity: It is a commonly used method of expressing the concentration of a solution.

Definition: The amount of solute B in solution divided by the volume of the mixture, referred to as concentration.

The symbol c(b) indicates that the mathematical expression is m(mol l) n(mol) v(l).

2. Expansion: 1. The volume in the quantity concentration formula of a substance refers to the volume of the solution, not the volume of the solvent.

2. Take out any volume of solution in the quantity concentration solution of a certain substance, and its concentration remains unchanged, but the amount or mass of the substance containing solute is different due to the different volumes. First bang.

3. The amount of solute is expressed by the amount of the substance, not by the mass of the substance. For example, when preparing 1mol l of sodium chloride solution, the formula of sodium chloride is 23+, so it is called sodium chloride, dissolved with water, and 1mol l of sodium chloride solution can be obtained by setting the volume to 1000ml.

4. The solute can be elemental, compound, or other specific combinations such as ions or molecules, such as C(NaCl). The non-electrolyte mill exists as a molecule in its aqueous solution, and the concentration of solute particles in the solution is the concentration of solute molecules. For example, in 1mol l ethanol solution, the concentration of ethanol molecules is 1mol l.

Strong acid, strong alkali.

Strong electrolytes such as soluble salts exist in their aqueous solutions in the form of anions and cations, and the concentration of various particles is determined according to the concentration of the solution and the ionization equation of the solute.

1. The concept of quantity and concentration of a substance.

1. Quantity and concentration of substance: The amount of solute B contained in the solution per unit volume is used to express the physical quantity of the solution and the amount and concentration of the substance called solute B. The symbol is c(b), and the unit is mol l (or mol·l-1), etc.

Note: 1) Solutes can be substances, molecules, or ions.

2) solutes are expressed in terms of the quantity of the substance rather than the mass; Volume indicates the volume of the solution, not the volume of the solvent, and the volume unit is L.

3) The solution has uniformity, that is, any volume of solution is taken out from the solution of a certain amount of substance concentration, and the amount and concentration of the substance remains unchanged, but the amount of solute substance is different with the change of the volume of the solution.

4) After the substance with crystalline water is dissolved in water, the solute is a compound that does not contain crystalline water, and the water in the solvent includes crystalline water.

2. The relationship between the amount of solute substance (n), the amount and concentration of the substance of the solution, and the volume of the solution.

3. Conversion between N, M, V (gas) and CB.

2. Preparation of a certain substance concentration solution.

1) The use of volumetric flasks and precautions.

The laboratory prepares a solution of the amount and concentration of a substance with a volumetric flask. The most commonly used volumetric flasks are 100 ml, 250 ml, 500 ml and 1000 ml.

1.The volumetric flask is a thin-necked, pear-shaped glass container with a ground glass stopper.

The volumetric flask is equipped with a ground glass stopper or rubber stopper on the finish. The volumetric flask is marked with a graduation mark, applicable temperature, and capacity. Be sure to check the volumetric flask for leaks before use, by:

Add a certain amount of water to the bottle, plug the cork, hold the cork with your left index finger, hold the bottom of the bottle with your right hand, and turn the volumetric flask upside down to see if there is any water leakage. If there is no leakage, rotate the stopper 180° and repeat the above operation, and the volumetric flask that does not leak twice can be used.

2.Notes:

1) To prepare a solution with a certain amount and concentration of a substance, it is to fix the volume of a certain mass or volume of solute in a selected volumetric flask according to the volume of the solution, so there is no need to calculate the amount of water at all.

2) It is not possible to use a volumetric flask to prepare a solution with a certain concentration of a certain substance in the volume of Zaoling, because the specification of the volumetric flask stool search is fixed, and the appropriate volumetric flask should be selected according to the volume of the required solution when preparing the volumetric flask.

3) Do not use volumetric flasks to dissolve, dilute or store solutions (especially alkaline solutions), and do not carry out chemical reactions in volumetric flasks. After the preparation of the dissolution, the solution should be poured into a dry, clean reagent bottle.

According to the conservation of solute mass, let the mass of the original solution be x

22%x=14%(x+100)

x=175(g)

The mass of nano3 in the original solution = 175 * 22% = the amount of the substance concentration = (

Conversion. Both represent the composition of the solution and can be converted to each other by a certain relationship. When converting the mass fraction of solute into the quantity concentration of the substance, it is necessary to first calculate the mass of solute contained in 1L of solution, convert it into the amount of the corresponding substance, and sometimes convert the mass of the solute into the volume of the solution, and finally convert the mass of the solute into the volume of the solution, and finally convert the amount and concentration of the substance into the solute.

When converting the quantity concentration of a solute to the mass fraction of a solute, the amount of the solute is first converted to the mass of the solute, and sometimes the volume of the solution is converted to the mass of the solute, and then to the mass fraction of the solute.

The above content reference: Encyclopedia - Quantity and concentration of substances <>

The quantity concentration of a substance is a commonly used way to express the concentration of a solution, and the definite branch is the amount of the substance with lead in the solution divided by the volume of the mixture, referred to as the concentration, which is represented by the symbol C.

The quantity of matter: The quantity of matter is a physical quantity, which represents a collective containing a certain number of particles, the symbol is n, the unit is mole, referred to as mole, the symbol is mol.

Molar mass: Molar mass is the abbreviation of the mass possessed by the quantity of a unit substance, which is represented by the symbol m.

When the amount of a substance is measured in mol, the unit of molar mass is g mol, which is numerically equal to the mass of the proto-tuber or molecular mass of the substance.

For a compound, its molar mass is fixed. The mass of a substance changes with the amount of matter.

Molar mass of gas:

The volume occupied by a gas per unit of substance, this volume is called the molarity volume of the gas, and the unit is l mol (liter mol).

Under standard conditions (stp, 0 ,,1 mol, the volume of any ideal gas is about liters, and the molar volume of gas is l mol. At 25, the molar volume of the gas is approx. <>

Let the quality of the original lead-solubilized solution be xg, which can be obtained according to the constant noise of the solute before and after dilution

22%x=14% (1+100).

x = 175 of the original solution.

is c=n, v=(175*22%, 85).

The amount of concentration of the substance. The estimation is as follows: according to the conservation of solute mass, let the mass of the original solution be x.

22%x=14%(x+100)。

x=175(g)。

The mass of nano3 in the original solution = 175 * 22% =.

The amount of concentration of the substance.

Conversion between the twoBoth represent the composition of the solution and can be converted to each other by a certain relationship. When converting the mass fraction of solute into the quantity and concentration of a substance, it is first necessary to calculate the mass of solute in 1L of solution, which is converted into the amount of the corresponding substance, and sometimes the mass of the solution needs to be converted into the volume of the solution, and finally the amount and concentration of the substance that is converted into solute.

When converting the quantity and concentration of solute substances to the mass fraction of solutes, first the amount of substances in the solute is converted to the mass of the solute, and sometimes the volume of the solution is converted to mass, and then converted to the mass fraction of solute.

Quantity concentration of a substance: A commonly used way to express the concentration of a solution.

Because Ca(OH)2 is a slightly soluble substance, at room temperature, the mass of solute dissolved in 100 grams of water is less than 1 gram, so the gram cannot be dissolved.

There are two ways to find the quantity concentration of a substance, one is the amount of the substance with a solution solute and the volume of the solution:

c = n (amount of solute material) v (volume of solution).

The other one can be obtained directly by using the density and mass fraction of the solution

c = 1000 W m (molar mass of solute).

The second one works well in practical calculations.