Math masters, come about word problems

After 30 minutes, car A is 5 kilometers in front of car B.

Then A walks 10 kilometers more than B in 1 hour.

When the speed of A is 10 kilometers greater than the speed of B.

Let A and B each travel x,(x-10) kilometers per hour.

200/x+1=200/（x-10）

x^2-10x-2000=0

x-50)(x+40)=0

Because velocity is non-negative. So x = 50 km-hours.

A and B travel 50,40 kilometers per hour.

After 30 minutes, car A is 5 kilometers in front of car B, which means that A travels 5*2=10 kilometers more than B in 1 hour.

Let B travel x kilometers per hour, and A travel x + 10 kilometers per hour.

200/x=200/（x+10）+1

x=40x+10=40+10=50

B travels 40 kilometers per hour, and A travels 50 kilometers per hour.

If driving normally, A will arrive 1 hour earlier than B, and at 30 minutes A travels 5 kilometers more than B, then A travels 10 kilometers more than B in 1 hour.

Let A travel x kilometers per hour and B travel y kilometers per hour, then.

x-y=10

200/y - 200/x = 1

Solve: x= 50, y = 40 or x = -40, y = -50

The latter solution does not meet the requirements, so A travels 50 kilometers per hour and B travels 40 kilometers per hour.

The walking speed of A and B is set to 3x and 2x respectively

A and B depart from point A and B at the same time, and if they go in the opposite direction, they meet one hour later.

then the distance between a and b = 3x

2x=5x, then A catches up with B.

5x (3x-2x) = 5 hours.

A: It takes 5 hours for A to catch up with B.

There are a total of 5 students, they donated a total of 16 times 5 equals 80 yuan, and the remaining savings are equal to the original three students' deposits, then they are equivalent to donating the original savings of two students, so they use the donated 80 yuan divided by 2 to get the original deposit of 40 yuan per person.

If each student has x yuan, then there is.

The remaining money of the five students is (x-16)*5

It turned out that the deposit amount of the three students was 3x

then there is (x-16)*5=3x

5x-80=3x

2x=80x=40 yuan.

Because after each person donated 16 yuan to the Hope Project, the remaining money of the five students was exactly equal to the amount of savings of the original three students.

Therefore, the remaining money of each student is exactly equal to 60% of the original deposit amount of each student

$16.

According to the title, 5 16s are equivalent to the number of deposits of 2 people: 5 16 = 80

The original deposit per person is: 80 2 = 40 yuan.

Solution: Set the original deposit of x yuan per person.

3x=5x-16*5

2x=80x=40

A: It turned out that each person had a deposit of 40 yuan.

It turns out that there is x yuan per person.

5x-5*16=3x x=40

It turned out to be 40 yuan per person.

Let the original deposit of a classmate be A, because the deposit of each classmate is the same, all the deposits of the five students are 5A and each person donates 16 yuan, and 5 people are 16 5 = 80 yuan, so the remaining money of 5 people is 5A-16*5. According to the question stem, the money left after the donation is the deposit of the original 3 students, so you can list the equation 5a-16*5=3a

$40. Let the original money be , and get 5 ( -16) = 3 . Got =40, so it turned out to be 40 yuan per person, children, have you learned the unknown? If you haven't learned it, I'm afraid this won't be useful to you. Good luck!

Set the original deposit of x yuan per person.

5 times x (is the original deposit and) - 16 (donated) = 3 times x (remaining).

1. If the first process is set up with x people, then the second process (10-x) people.

The number of pieces to complete the task in the two processes is the same, and the column equation is: 120*5*x=150*6*(10-x).

solution, get: x=6 (person);

Then the number of people in the second process is: 10-x=4 (people).

2. Set up z pieces to be completed every week; If x people are added to a process, there will be a total of (x+6) people in a process; The second path adds y people, and the second path has a total of (y+4) people. The following equations can be listed:

x+6)*120*5=(y+4)*150*6 (simplified to: 2x=3y);

x+6)*120*5=z(simplified to: 600(x+6)=z);

y+4)*150*6=z(simplified to: 900(y+4)=z);

z≤72000/8；

The above yields: z 9000;x≤9；y≤6；and 2x=3y. ——1）

Worker's wage = (x+6)*120*5*;

Raw material cost = 8z, sales = 16z. According to: sales - raw material cost - wage = profit, there are:

16z-8z-z 40000, i.e. Z 40000 7.

So: 600(x+6)=z 40000 7,900(y+4)=z 40000 7, gets: x ; y≥。—2）

According to (1) and (2), two sets of solutions can be solved, both of which are in line with the topic:

When y=4 and x=6, you can recruit 4+6=10 (people) again.

When y=6 and x=9, you can recruit another 6+9=15 (people).

Solution: (1) If the first process is completed by x people, then the second process (10-x) is 120 5x = 150 6 (10-x).

x=6 The first process arranges 6 people.

The second process is 10-x=4 people.

The ratio of the number of people in the first process to the second process is: 6:4=3:210 The number of workpieces completed by each person per week is: 120 5 6 = 3600 pieces, and the average number of workpieces completed per person per week is 360 pieces.

2) Set the number of processed products to be y.

8y≤72000

Solution: 40000 7 y 9000

The number of people required to complete Y products is m, then:

40000/7/360≤m≤9000/36016 ≤m≤25

The ratio of the number of people in the first process to the second process is: 3:2

20 ≤m≤25

The number of people that can be re-recruited by the factory is: 10 or 15 people.

(1) If the first process is arranged with x people, then the second process is arranged with 10-x people 120 5 x = 150 6 (10-x).

x=610-6=4 (person).

The two processes should be arranged with 6 people and 4 people respectively.

2) The selling fee should be the selling price. Set the weekly production of a piece of product 4 10000 (

40000/7≤a≤9000

40000/7÷(120×5×6)≤a÷(120×5×6)≤9000÷(120×5×6)

100/63≤a/3600≤5/2

Minimum re-enrollment: (100 63-1) 10 5 maximum re-enrollment: (5 2-1) 10 = 15.

1.Set up x people to complete the first process.

120×5x=150×6×（10-x）

x=6, the second process is 10-x=4

2.3,600 pieces per week for 1 person and 10 people is equivalent to 360 pieces per person per week.

Set up another recruit of Y people.

360(10+y)(16-8-1)≥40000360×8（10+y）≤72000

First, the first process needs x people, and the second process needs to be x people, then, x+y=10 120x left5=150yleft6 leftovers x=6 y=4

(1) If the first process is completed by x people, then the second process (10-x) is 120 5x = 150 6 (10-x).

If x=6 is solved, then the second process is 10-x=4

2) The second question is that I don't understand the meaning of Shenma.

If the price increases by x yuan, then the profit of 1 piece is buried = 20 + x yuan.

Sell 5x less, and talk about friends is 400-5x

So profit = (20+x)(400-5x)=-5x 2+300x+8000

5(x-30)^2+12500

x=30 is the largest trouser servant.

At this time, the selling price = 60 + 20 + 30

Therefore, when the price is 110 yuan, the maximum profit is 12,500 yuan.

1. Solution: Two cases: 598 = 138 + (40 + 52) x can get x = 5h

598=（40+52）x

x=8h can be obtained

2. Solution: If you do the x problem correctly, then: 8x

5(10-x)=41

You can get x=7

3. Solution: Let the number a remain unchanged, and c is the number hidden after b moves to the right, then: a+c=,a+b=,10b=c, a=,b=,a=,b=,a=,a=,b=,a=,a=,b=,a=,a=,b=,a=,a=,b=

4. Solution: Set the train length x meters, then: 1320 + x = 700x3, you can launch x = 7805, solution:

Multiply by ., respectively001 can be obtained019656. Solution:

You must move 2 squares first, and then you must sum up the numbers you and your opponent say to 4, and you will win! Pure old.

1): Set x hours.

40x+52x+138=598

x=52)

The wrong answer is yx+y=10

8x+（-5)y=41

Equations. x=7

y=3 So the correct answer is 7 questions.

3): The two of Shewu Hong are x

yx+y=x+10y=

I'm moving the y decimal point by one place.

That's a 10-fold expansion.

Get x=y= so the answer is these 2 numbers.

4) Set the length of the car x meters.

Get 2x+1320=2100

x=390

5) Answer: Dou with the case is.

6) This is not clear.

I'm sorry.

1) (598-138) (40 + 52) = 5 (hours) 2) Set the imitation grinding coarseness to do the wrong problem of x, and the two equations can be obtained by x+y=108x-5y=41, and x=7 can be obtained

3) Unsolved (4) Speed 700 60 Beizhen 35 3180 35 3-1320 = 780 (m).

I haven't thought of a good way yet.