SOS 8th Grade Math Winter Vacation Paradise Answers, Urgent

Updated on educate 2024-04-13
14 answers
  1. Anonymous users2024-02-07

    Every year, students ask for homework answers, and of course I've looked for them online.

    But I can tell you that there are some questions that have answers.

    e.g.1 The answer to the exercise reads: See the next issue for the answer.

    3 Consult with classmates.

    Why some exercises don't have answers.

    Because the exercise is original and the answer is not published, there is no answer.

    Even if you have a winter vacation homework, unless you use a scanner to scan it onto your computer, think about it, would you scan it if you wrote? Will it be posted online after scanning? Right, so the answer is hard to find.

    I hope you can understand that this is really not!

    Besides, these questions are done by a small number of people, that is, the largest in your city, that is, in some of the surrounding areas, maybe someone has written the answers?

    If you have any questions, please send me a message Thank you.

  2. Anonymous users2024-02-06

    This problem mainly uses the perfect square formula and the square difference formula, and it is easier to simplify this problem by mastering these two formulas.

  3. Anonymous users2024-02-05

    Take it away or not, thank you, classmates pay attention to it, like it, hope.

  4. Anonymous users2024-02-04

    The three that are not red are moving.

  5. Anonymous users2024-02-03

    It's as simple as moving the 3 small sticks from the top to the bottom.

  6. Anonymous users2024-02-02

    Sad Baiyun, hello The answer process is as follows:

    Solution: (1) Let the distance between A and B be s, then: s 3a+2s 3 2b=2s 3c simplification yields a, b, c relations: 1 a+1 b=2 c;

    2) Substituting c=3 into the above equation obtains: 1 a+1 b=2 3, and 1 b-1 a=1 6

    The system of equations: 1 a+1 b=2 3 1 b-1 a=1 6, and the system of equations is solved to obtain a=4; b=12/5.

  7. Anonymous users2024-02-01

    (1) 1 3a+2 (3*2b)=1 3c (you can set the total distance as x, and then divide the left and right by x, and the result is the same).

    Multiply the left and right by 3 to get the relation 1 a+1 b=1 c(2), if c=3, then according to the above relation, we get: 1 a+1 b=1 3 according to the meaning of the question 1 b-1 a=1 6

    Add the two equations to get 2 b=1 2 to get: b=4 and subtract the same way to get 2 a=1 6 (you can also substitute b=4 into any equation to calculate a) to get: a=12

    So the answer is a=12 b=4

    Think more about the topic!

  8. Anonymous users2024-01-31

    Over F for FG AE, the vertical foot is G, connected EF

    The quadrilateral ABCD is rectangular.

    d=∠c=90º

    AF deuces DAE

    daf=∠gaf

    In DAF and GAF:

    d=∠fga=90º

    af=afdaf=∠gaf

    daf≌△gaf(aas)

    df=gf,ad=ag

    f is the midpoint of DC.

    cf=gfef=ef

    rt△fge≌rt△fce(hl)

    Ge = Ceae = dc + ce and ae = ag + ge

    dc=agdc=ad

    The quadrilateral ABCD is rectangular.

    A rectangular ABCD is a square.

  9. Anonymous users2024-01-30

    If the perpendicular line from F to AE is g, then Fg=FD=FC, then EC=EG, then AG=DC, and AG=AD, then AD=DC

  10. Anonymous users2024-01-29

    Cross the point F to make the perpendicular line of AE, cross AE at the point G, connect EF, ADF and AGF congruence, FGE and FCE congruence, ad ag, ce ge, ae=dc+ce=ag+ge=ad+ce, so ad=dc

  11. Anonymous users2024-01-28

    Set the original x yuan per piece, buy a total of y pieces, and list the equation:

    xy=4x-1/15) *

    This gives y=20

  12. Anonymous users2024-01-27

    Solution: If the first small commodity is x yuan per piece, then the second small commodity is x (1-1 15) yuan per piece.

    4/(x(1-1/15)):4/x=:1

    Then get rid of yourself!

  13. Anonymous users2024-01-26

    Your study methods are very problematic, your grades need to improve, and you have to think independently most of the time.

    Don't believe all those who have to do with education.

  14. Anonymous users2024-01-25

    It is an isosceles right triangle.

    Connect aooa=ob

    oac=∠b=45°bm=an

    obm≌△oan

    om=onbom=∠aon

    bom+∠moa=90°

    aon+∠moa=90°=∠mon

    It is an isosceles right triangle.

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