A couple of 6th grade simple math problems, a 6th grade ultra simple math problem

Question 1 4:3 16:9

Question 2 1:9

Question 3 Floor area 36 Maximum capacity 180 Question 4 The thickness is about meters.

1), the ratio of side area is: 4:3 volume ratio is 16:92), the ratio of height is: 1:9

3), floor area s= x(12 2) 2=36 (square meters) maximum capacity: v=sxh=36 x5=180 (cubic meters).

You can bring it in and count it yourself. ）

4), first find the radius of the bottom surface of the cone r=m, and then find the volume of the cone v=1 3x x2 cubic meters).

Then the thickness of the bunker h=v 6 4=2 6 4=

The height of the two cylinders is equal, the ratio of the radius of the bottom surface is 4:3, and the ratio of the side area of the two cylinders is (4:3). The volume ratio is (16): 9).

The volume of a cylinder and a cone is equal, the base area of the cylinder is 6dm, the ground area of the cone is 2dm, and the ratio of the height of the cylinder to the cone is (1): 9)?

A cylindrical reservoir with a bottom diameter of 12 meters and a depth of 5 meters, what is the area of this tank? What is the maximum capacity of the pool. Area = square meters; Maximum capacity = cubic meters.

The school transported a batch of yellow sand piled up into a cone, the circumference of the bottom is meters, the height is, and the yellow sand is filled in a sand pit with a length of 6 meters and a width of 4 meters, what is the thickness of the sand in the sand pit??? Cone radius = m, sand thickness = 1 3 * (m.)

Question 1: 4; 3

Question 2: 9; 1

Question 3: Question 4: 600 157.

The ratio of side area is (4):3). The volume ratio is (16):(9) and the ratio of the height of the cylinder to the cone is (1): 7).

The size of this pool is about 48* The maximum capacity of the pool is 180* The thickness of the sand in the bunker is (12)m

1) Since r1:r2=4:3, the ratio of side areas is equal to 2(r1) h:2(r2) h=4:3, and the ratio of volumes is equal to h(r1) 2: h(r2) 2=16:9

2) The ratio of volume = s1 * (h1) :( 1 3) s2 * (h2) = 1:1, and because s1:s2 = 3:1, h1:h2=1:9

3) Floor area s= (d 2) 2 = 36, water capacity v = s * h = 36 * 5 = 180

4)2πr=,r=2,v=(1/3)hπr^2=2π=,h=v/s=

Question 1: (4) :(3).

Question 2 1:9

Question 3: Floor area: (12 2) 2

Maximum Capacity: Question 4: (Look.)

There is no easy way to just remove the brackets and merge similar items.

The final answer to this question is 0, there is no need for any easy way, first use the distributive property to remove the parentheses, and then find the same denominator to merge the same kind of terms, it is very simple.

Get 0. Just separate them according to the distribution rate, and then write them together according to the same denominator, and the answer will come out.

Their sum is equal to eighty-five ninety-eight....Their difference is equal to thirteen ninety-eight....Their quotient is equal to eighty-five tenths of a thirteen....

1.The distance is the same, and the speed is inversely proportional to the time.

The speed ratio of naughty to laughing is 12:10=6:5

The ratio is 6 5=

2.A is 5 parts, 15 5 = 3 each

B is 4-3 less than C = 1 part.

B is less than C: 3 1 = 3

Composite formula: 15 5 (4-3)=3

3.The ratio of A and B is 2:3 = 2 4:3 4 = 8:12, the ratio of B and C is 4:5 = 4 3:5 3 = 12:15, and the ratio of A and B and C is 8:12:15

1、 10/12=5/6=

2. The number B is 9, the number C is 12, and the number B is 3 less than the number C

1 The speed ratio is 5:6

The ratio is 5 to 6

2 B is 9 and C is 12

1. The speed ratio of the first question is the reciprocal of the time ratio, that is, 12:10, that is, 6:5

2, let A 5x, B 3x, C 4x, known A 15, we can know that x=3, and B is less than C x, that is, less 3

3. Find the least common multiple, A: B = 2:3 = 8:12. B: C = 4:5 = 12:15. So the answer is A: B: C = 8:12:15

10:1 12=6:5 The velocity ratio of the two of them is 5 (4-3)=3 B is 33 less than C, A:B=2:3=8:12

B: C = 4:5 = 12:15.

The ratio of A, B and C is 8:12:15