Learning Mathematics !! for Secondary 3 Senior sisters and buddies, please!!

At that time, our teacher was in the last month before the high school entrance examination every day to do a round big question, it is estimated that the question type is almost finished, the high school entrance examination is also handy, of course, the most important thing now is to grasp the foundation, the formula is definitely to remember, you better do the book questions now, don't blindly do the high school entrance examination questions, you now do the high school entrance examination questions then you will not have nothing to do next year! Take it one step at a time, don't rush! I also teach a little kid the chapter now, most of the teachers in the school have just finished the knowledge of this chapter, don't do that kind of comprehensive topic, do the basic!

Hehe, by the way, show off, I got a perfect score in mathematics in the high school entrance examination! Ha ha! But I'm a senior now, and a good girl doesn't mention being brave back then!

If you have any questions, you can send them to my mailbox.

I'm good at math and just graduated.

I think it's because I don't know what method to use, so I can't do it more to find the feeling.

Fill in the blanksOur last question is mostly to find patterns, which is completely an ability question.

Do more questions, do mid-term exam questions, don't be afraid, don't panic, believe in yourself during the exam.

I wish you good results in the high school entrance examination.

I don't know what is good about the reference books, but I have some small experiences that I hope will be useful to you

First of all, it is necessary to practice more, the foundation is more important, and practicing is an important way to improve speed. In addition, I think the most important thing is the mentality, when you encounter a problem, you estimate that you are already a little afraid in the subconscious, you have to consciously adjust this mentality in ordinary times, tell yourself, even if you can't do the result, the first few steps to make it have a score (what needs to be said here is, don't underestimate the 3 points and 4 points, in fact, the score gap of the whole paper is composed of this small score) The final answer is not necessarily made, as long as you can solve what you can do.

For circles, the basic concepts and relationships must be firmly remembered, in fact, those basic concepts are inseparable from them.

When you do the questions, circle the key information, it is best to stage the calculation in the paper, the important thing to improve the question is the idea, generally the third year of the improvement questions are those types, do a few more combined with the answer summary method, encounter the same type of questions directly apply carelessness This point is not easy to overcome, you can only do it yourself, take the usual questions as exams, don't be too nervous during the exam, usually pay more attention to the exercises, especially those taught by the teacher.

This is my personal advice (I don't usually go down 115 in 9th grade math) and math is my strong point right now.

It's best to focus on the basics first.

In general, no points will be lost for the basic questions.

A high score is no problem.

But stick to it every day.

It must not be perfunctory.

You look for a book called "Instructions for the High School Entrance Examination" that is full of high school entrance examination questions that should be helpful to you.

There is also the same as the last session to borrow that five-year high school entrance examination three-year simulation, it is best to bring the answer analysis, and the analysis is very good.

Which region are you in Different provinces have different difficulties.

You're nervous about exams! Practice more questions on a regular basis, set a time for yourself, and find someone to supervise you when the time comes. Practice a lot.

Steps: 1. Plant x peach trees.

2. The number of peaches planted in a year should be (original + x) * 1000-2 * (original + x). It can be merged, but Ling Slip is so easy to understand. The meaning of the minus sign in front of (original +x)*1000 is:

Now the total number of peach trees planted is multiplied by the number of peaches produced by each tree equals the theoretical yield. However, in fact, the yield of each tree is reduced by 2, so it is necessary to subtract 2* (original +x).

3. The number of peaches obtained according to this scheme is obtained minus the number of original production, that is, the part of the increased yield, and this part of the dan is divided by the original production. A simple equation.

Original+x)*1000-2*(Original+x)-1000*Original.

Original*1000

154*Original.

Then solve this equation x=——

If there are 30, then 4-5 should be planted.

If there are 100, then 15 should be planted. In order to reach the mold Wang to let you say this increase in production.

Solution: Set up a deficit and a variety of x trees.

1000-2x)(100+x)=100*1000*(1+

I guess I can...Lost....Li Ying.

Untie; If there should be many x peach trees, then (100+x)(1000-2x)=1000 100 (1+

Determination of parallelograms:

Two sets of quadrilaterals with opposite sides parallel to each other are parallelograms. A set of quadrilaterals that are parallel and equal to the opposite sides is a parallelogram. Two sets of quadrilaterals with equal opposite sides are parallelograms.

Two sets of quadrilaterals with equal diagonal angles are parallelograms. A quadrilateral with diagonals bisecting each other is a parallelogram.

Rhombus: 1, a set of parallelograms with equal adjacent sides is a rhombus 2, quadrilaterals with equal sides are rhombic 3, and quadrilaterals with diagonals perpendicular to each other and bisected are rhombuses.

Square: 1: A diamond with equal diagonal lines is a square.

2: The rectangle with diagonal perpendicular to each other is a square,The diagonals are perpendicular to each other, and the quadrilaterals that are bisected and equal are squares.

3: A group of quadrilaterals with equal adjacent sides and three corners that are right angles is a square.

4: A set of rectangles with equal adjacent sides is a square.

5: A set of parallelograms with equal adjacent sides and one corner at right angles is a square.

6: The quadrilateral with all four sides equal and the diagonals bisected perpendicular to each other and equal is a square.

7: A diamond with a right angle is a square.

8: A quadrilateral that is both a diamond and a rectangle is a square.

Rectangle: 1A parallelogram with an angle of right angles is a rectangle 2A parallelogram with equal diagonals is a rectangle 3A quadrilateral with three corners that are right angles is a rectangle.

Trapezoid: 1 A group of quadrilaterals with opposite sides parallel and another set of quadrilaterals with opposite sides that are not parallel is a trapezoid (a set of quadrilaterals with opposite sides parallel and unequal is a trapezoid) 2 A trapezoid with two equal waists is an isosceles trapezoid 3 A trapezoid with two equal angles on the same base is an isosceles trapezoid 4 A trapezoid with an inner angle of right angles is a right-angled trapezoid 5 A trapezoid with equal diagonal lines is an isosceles trapezoid 6The median line of the trapezoid is equal to half of the sum of the upper bottom and the lower bottom, and is parallel to the upper and lower bottoms.

A quadrilateral with two sides parallel is a parallelogram.

A quadrilateral that is parallel and equal on one side is a parallelogram.

A quadrilateral with diagonals bisecting each other is a parallelogram.

A parallelogram with diagonal lines perpendicular to each other is a diamond.

A set of parallelograms with equal adjacent sides is a rhombus.

A quadrilateral with equal sides is a diamond.

Quadrilaterals with equal diagonals and bisected from each other are rectangulars.

A parallelogram with an internal angle of 90 degrees is rectangular.

The rectangle perpendicular to the diagonal is a square.

That's all there should be for the main thing.

In general, squares and rectangles are proved to be parallelograms before further proofs ......Hope it helps you (*hee-hee......

Parallelogram (3 types): two groups of opposite sides are parallel; or a set of opposite sides parallel and equal; The two groups are equal diagonally.

Rhomboids (3 types): quadrilaterals with equal sides; parallelograms with equal adjacent sides (first prove parallel dead edge rows and then prove that a group of adjacent sides are equal); quadrilaterals with perpendicular diagonals and bisecting each other;

Witness square (3 types): a diamond with a right angle; a diamond with equal diagonals; A rectangle with equal adjacent edges.

Rectangle (3 types): a parallelogram with a right angle; A parallelogram with equal diagonals.

Trapezoid: a set of quadrilaterals with parallel opposite sides;

Isosceles trapezoid: a trapezoid with equal diagonals; trapezoidal with equal waists;

That's all I know, I hope it helps!

It is proved that the two sides are parallel and equal, the diagonal is perpendicular and bisected, the rectangle proves that it is parallel and perpendicular, the trapezoid proves that a group of opposite sides are parallel, the isosceles trapezoid can extend the waist to the intersection point, and then it is proved that it is an isosceles triangle.

A square is a special form of a rectangle.

The master is in!

If the triangle abp is a regular triangle, then k = 3k under the root number, k = 32x + 1 = 0, x -y = 0

x=-1/2，y=1/4

The coordinates of the points on the parabola y=x +2mx+m are (-1 2,1 4) No one has to answer this kind of question with me!

Ace's!

Let the line parallel to the line y x b be y x b, and the system of equations with the parabola yields:

y＝x^2－3x－2

y x b subtract y to get:

x^2－4x－2－b＝0

The discriminant formula of the root of the order is equal to zero

16－4(－2－b)＝0

Solution: b 6

That is, this straight line is y x 6

Intersect with the y-axis at the point (0, 6).

The distance from this point to the straight line y x is 3 2, and the distance from the straight line y x 6 has only one intersection point with the parabola, and the distance from this point to the straight line y x is 3 2

On the other side of the line y x, there are two intersections of the line y x 6 and the parabola, both of which are at a distance of 3 2 to the line y x

Thus, when the radius of p is 3 2, there are only three points on the parabola so that the circle centered on p is tangent to the line y x.

Calculate it yourself.

Step 1 Find the point on the parabola where the tangent slope is equal to 1 (2, -4).

The distance from this point to the straight line is calculated as the radius r=3, and the root number 2

There should be and only 3 points, so one of the points must be y=x 2-3x-2 on the vertex Find the vertex coordinates The distance to the straight line is the radius.

Draw the image of y=x and y=x 2-3x-2, you will find that if the circle with a fixed radius moves, there are only three points, that is, there are three points with the same distance to y=x, then only the point with the tangent slope of 1 is the point that satisfies the condition, and this point is easy to obtain (2,-4) (using the slope of any point of the parabola), and the distance from this point to y=x is 3 with the sign 2

When the second row travels out of 40km, the speed ratio of the first row and the second row can be expressed as: 40When the first row arrives, the speed ratio of the first row and the second row can be expressed as: x (x-20) The two equations are equal, and x can be found

Solution: four digits, such as the number on the single digit and the thousand digit has been determined, assuming that the number on the ten digits is 0, then the number on the hundred digits may be one of 0-9, to try 10 times, similarly, assuming that the number on the ten digits is 1, then the number on the hundred digits may be one of 0-9, but also try 10 times, and so on, to open the lock needs to be tried 100 times, and only one of them can be opened, so the probability of being able to open the lock at one time is 1 100

1.Solution: According to the inverse theorem of the proportionality theorem of parallel line segments, that is, "three straight lines are truncated by two straight lines, if the corresponding line segments are proportional, then the three straight lines are parallel", analyze and judge

A, B, and C are all proportional to the corresponding line segments intercepted, so DE AC can be obtained;

D, de and bc are not intercepted line segments, so de bc may not be able to be obtained, so d is chosen

2.Solution: a b = b c b 2 = ac = 16 a = 4

The first question can be similar to abc according to ade, and d is on ab side, e is on ac side, and de can be deduced parallel to bc by b

If it refers to the circle, then a 4