There is an answer process, a simple math problem!!!!!!!!!!!!!!!!!!!!

Draw a straight line and mark the arrow to the right at the far right. (i.e. x-axis).

Draw a vertical line on the 0 scale and mark the arrow at the top. (i.e. y-axis).

Also take a series of points (the same distance) on this line

And from 0 to the scale upwards, respectively: 1, 2, 3, from 0 to the scale downwards, respectively, -1, -2, -3

Find a point of -2 on the x-axis and draw a dashed line perpendicular to the x-axis, and find a dotted line on the y-axis to find a dotted line on the y-axis. The intersection of these two points is the point a(-2,3).

With respect to the x-axis, symmetry point c coordinates i.e., the x value does not change, and the y value is its opposite.

That is, find the point of -3 in the y-axis, and draw a dashed line perpendicular to the y-axis. The intersection of these two points is the point c(-2,-3).

Any point of symmetry at the point (a,b) with respect to the x-axis is (a,-b) a,b is a real number.

Because its y value is going to be the opposite of the original number.

In the same way, any point of symmetry at point (a,b) with respect to the y-axis is (-a,b) a,b is a real number.

There are not so many reasons for this kind of question, and you can directly fill in the answers in the college entrance examination, and you don't need to go through the process.

The symmetry point about the x-axis is the same abscissa and the ordinate is the opposite of each other.

Let the symmetry point coordinates (x,y), then there is a system of equations x=-2,y+3=0; The solution is x=-2, y=-3, and you can also use the graphing method.

None of the three.

is an obtuse triangle.

Use the formula for the distance between two points in space: [x2-x1) y2-y1) z2-z1).

AB = [ 0-3) 2-0) 0+1) = 14, BC = [ 2-0) 4+2) 2-0) = 44, CA = [ 3-2) 0-4) 1+2) = 18

It can be proved that the triangle is not an isosceles triangle, not an equilateral triangle, nor a right triangle (does not satisfy the Pythagorean inverse theorem).

The cosine formula can also be used: the angle a is deduced as an obtuse angle, (omitted).

It is also possible to use the quantitative product of the space vector to deduce: (The process is as follows).

First vector ab = (0-3, -2-0, 0+1) = (-3, -2, 1).

Vector ac = (2-3, 4-0, -2+1) = (-1, 4, -1).

Since the product of the quantity of the vector ac and the vector ab = -3*(-1)+(2)*4+1*(-1) = -6 < 0, it can also be inferred that the angle a is obtuse.

It is actually the greatest common divisor of the sum.

Therefore the greatest common divisor is 2*2*

Therefore, the maximum square area is square meters.

The greatest common factor of 56 and 32 is 8, which shows that the cement floor should be planned into a square, and the maximum side length of the square is, that is, the area is up to square meters.

Find the greatest common divisor of length and width is , then it is the area!

Take the common divisor of length and width, so the square area is square meters.

Therefore, when the side length of the square grid is meters, the grid used is the least, that is, the maximum square area is square meters.

Replace rice with rice, that is, find the greatest common divisor of 56 and 32 8 meters.

One-half minus one-quarter, one-eighth minus, one-sixteenth minus, one-thirty-two, one-sixty-fourth, one-hundred-twenty-eighth.

1 1/2) (1/2 1/4) (1/4 1/8) (1/8 1/16) (1/16 1/32) (1/32 1/64) (1/1 128/64).

1 1/2 1 1/2 1 128/1

1 in 128

Are you junior high or high school?!

If you are in high school, you can use the first n terms of the proportional number series and the formula to substitute it for a calculation.

Add a 1 in front of it, and then subtract it by one, that is, all the terms you said are negative, and if you want to mention the negative sign, you can use the equation of the proportional number series.

If it's junior high school, it's ......It's not hard to calculate.

One in twenty-eighth. I don't know what the pattern is, trust yourself, and you'll find it soon.

1/2-1/4-1/8-……=1/4-1/8-1/16……=……

So, each time the subtraction is twice the subtraction, and the difference is equal to the subtraction, so the answer is 1 128(Does that count as a simple calculation?) ）

Dutong divides into one hundred and twenty-eight, and then subtracts and comes out.

Hello Snow Fairy:

Area: 400 500) 100 2 45000 (m²) hectares) Wheat harvested: kg) ton) 60 (ton).

So 60 tons of wheat could not be received.

Solution: (1) If the production of A kind of tiles x 10,000 pieces, then B kind (50-x) 10,000 pieces (< = is less than or equal to the meaning).

Solving this inequality gives 30<=x<=32

Because x is a positive integer.

So x takes 30, 31, 32

50-x=20,19,18.

Therefore, using the existing raw materials, the plant is able to complete the task as required. There are three production options:

Plan 1: Production of 30 A kinds of tiles and 20 B kinds of tiles;

Plan 2: Production of 31 A tiles and 19 B tiles;

Plan 3: Production of 32 A tiles and 18 B tiles.

2) The total cost is:

If x=300,000 yuan).

If x=310,000 yuan).

If x=320,000 yuan).

Therefore, the third production scheme designed (32 pieces of A type of tiles and 18 pieces of B type tiles) has the lowest total cost, and the minimum cost is 10,000 yuan.

If A x 10,000 pieces, then B (50-x) 10,000 pieces.

Solution x 35

2x+5(50-x) 145, the solution is x 35 so x = 35, 50-35 = 150,000 pieces.

10,000 yuan answer: to complete the task, there is only 1 plan, A and B are 35, 15 each, and the cost is 690,000 yuan.

Solution: (1) If the production of a kind of brick x 10,000 pieces, then B kind (50-x) 10,000 pieces can be solved by this inequality group 30<=x<=32 and because x 0, so x=30,31,32 50-x=20,19,18

So there are three production options:

Plan 1: Production of 30 A kinds of tiles and 20 B kinds of tiles;

Plan 2: Production of 31 A tiles and 19 B tiles;

Plan 3: Production of 32 A tiles and 18 B tiles.

2) The total cost is:

If x=300,000 yuan).

If x=310,000 yuan).

If x=320,000 yuan).

Therefore, the third production scheme designed (32 pieces of A type of tiles and 18 pieces of B type tiles) has the lowest total cost, and the minimum cost is 10,000 yuan.

Solution: (1) If the production of X bricks of A is established, then the production of B kinds of tiles (50-X) blocks.

Solution: x=29,30,31,32

50-x=21，20，19，18

There are four options.

Plan 1: Production of 29 pieces of type A tiles and 21 pieces of type B.

Plan 2: Production of 30 pieces of A type tiles and 20 pieces of B species.

Plan 3: Production of 31 pieces of A type of tiles and 19 pieces of B species.

Plan 4: Production of 32 pieces of A type of tiles and 18 pieces of B species.

2) Set: The total cost is w

w=k=y decreases as x increases.

When x=32.

y has a minimum value = 10,000 yuan).

Option 4 has the lowest total cost and the lowest cost is RMB.

ps: I don't know if the count is correct, but it shouldn't be a problem.

Obviously, when m is fixed above and below the ellipse, the angle f1mf2 is the largest (this can be proved), so cos=(2a-4c) 2a0, so a-2c0

1-2e²≤0e∈[√2

(1) The factory can make a profit of 10,000 yuan from the production of Type A masks.

The production of Type B masks can earn a profit of 10,000 yuan.

2) y=Since there must be no less than a type A mask, x>=

From the production capacity of the plant, it is obtained: (x <=8 and x<=, so the range of the independent variable x is <=x<=

3) y= is an increase function, y becomes larger with the increase of x, so when the profit is maximum, x takes the maximum value x= and substitutes it.

y=, get y=10,000.

If you want to complete the task in the shortest time, let t=(x take the minimum value, this function is an increase function, when x takes the minimum value, the minimum value t=7 days, at this time, the production of type A masks 10,000, type B masks 10,000.

(1)（2）y=

x < = 8

The value range of the independent variable x is: 0=(3) 10,000 A-type and 10,000-B-type.

The maximum profit is: 10,000 yuan.

Production of 10,000 A-type, 10,000-B-type.

Minimum time: days.

If the first batch arrives at x kilograms, the second shipment arrives at kilograms.

16 Solution: x 1380

(2/3*x*

x = 150 upstairs less divisor number. Ha ha.