It is known that the function y x 2 2x 5 indicates the direction of its opening, the axis of symmetr

Solution 1: Since the coefficient of x 2 is 1, its opening is upward.

The axis of symmetry is -b 2a=-2 2=-1

When x=-1, y=1-2-5=-6

Therefore, its vertex coordinates are (-1, -6).

Solution 2: When the function intersects with the x-axis, y=0

i.e. x 2+2x-5=0

(x+1) 2=6

The solution is x1= 6-1 x2=- 6-1

Therefore, the points a and b are ( 6-1,0)(-6-1), respectively, and x=0 when the function intersects the y-axis

Substituting has y=-5

That is, the coordinates of c are (0,-5).

Solution 3This function is a parabola with the opening pointing up, -1 as the axis of symmetry, and vertex coordinates (-1, -6).

Solution 4 due to y=(x+1) 2-6

When you translate it two units to the right, the axis of symmetry becomes -1+2=1, and when you translate upwards, it becomes -6+4=-2

At this point y=(x-1) 2-2

x^2-2x-1

Solution: Move it 1 unit to the right, the axis of symmetry is x=-1+1=0 and translate it up 6 units to get -6+6=0

In this case, the analytic expression of the function is y=x 2

y=x^2+2x-5=(x+1)^2-6

1) The coefficient of the quadratic term is 1>0, the opening is upward, the vertex coordinates are (-1, -6), and the axis of symmetry is x= 1

2) y=x 2+2x-5=(x+1) 2-6=0, the two roots of the equation are 1 root number 6 and 1 root number 6

The intersection point with the x-axis is a(1 root number 6,0), b(1 root number 6,0) makes x=0, resulting in y=-5, and the intersection point with the y-axis is (0, 5).

It should be -x squared -2x, right?

The opening is downward, the axis of symmetry x -1, the vertex coordinates (-1, -1).

The opening is up, the axis of symmetry: straight line x=-2, vertex coordinates (-2, -9), when x=-2, y minimum = -9

Intersect with (1,0) (-5,0) with the x-axis

We just happened to be revising.

Opening Direction: Up.

Axis of symmetry Kamito Bu: x=1 2

Vertex coordinates of Yousui: (1 2,-9 Fan Town 4).

The opening is facing up and the axis of symmetry x= the fixed-point coordinates are (1 2, 9 4).

Solution: y=-2x +4x+6

2(x²-2x+1-1)+6

2(x-1)²+8

Since a=-2 0, the function opening is downward.

From x-1=0, the axis of symmetry is x=1, and the vertex coordinates are (1,8).

Let y=0, we get -2x +4x+6=0

x²-2x-3=0

x+1)(x-3)=0

The solution yields x=-1 or x=3

So the intersection of the function with the x-axis is (-1,0), (3,0) so that x=0, and y=6

So the intersection of this function with the y-axis is (0,6).

Solution: y=-2x 2+4x+6

2(x-1)^2+8

and a=-2<0

The opening of the function is downward, the axis of symmetry is: x=1, and the vertex coordinates are the intersection of (1,8) and the x-axis, i.e., the solution of the function when y=0, -2x 2+4x+6=0

Solution: x=-1, x=3

The coordinates of the intersection point with the x-axis are (-1,0), and the intersection point of (3,0) with the y-axis is the value of the function when x=0, i.e., the coordinates of the intersection point with the y-axis are (0,6).

Function for y=ax 2+bx+c mode:

1) a=-2<0, so the opening is downward;

2) axis of symmetry x=-b (2a) = -(4 (-2*2)))=1, so the axis of symmetry is x=1;

3) The vertex coordinates are: (-b 2a, (4ac-b 2) 4a) = (1, 8);

4) The intersection point with the x-axis is: let y=0, then 0=-2x +4x+6, i.e. (x-3)(x+1)=0 gives x=3 or x=-1

So the coordinates of the intersection point with the x-axis are (3,0) and (-1,0).

5) The intersection point with the y-axis is: let x=0, then y=6, so the coordinates of the intersection point with the y-axis are (0,6).

1。up, x=-3, (-3, -1 2).

2。down, x=1, (1, 5).

3。downward, x=-1, (-1, 0).

4。down, x=0, (0, -1).

5。downward, x=3, (3,0).

Direction: up, down, down, down, axis, symmetry, x=-3, x=1, x=-1, x=0, i.e., y-axis, x=3, vertex coordinates: (-3, -1, 2), (1,5), (1,0), (0,-1), (3,0).

1）y=5(x-3)^2-2;

The opening is upward; Axis of symmetry: x=3;vertex coordinates: (3,-2)2)y=;

The opening is downward; Axis of symmetry: x=-2;vertex coordinates(-2,0)3)y=7(x+5) 2+10;

The opening is upward; Axis of symmetry: x=-5;Vertex coordinates: (-5,10)4)y=-5 4(x-6) 2

The opening is downward; Axis of symmetry: x=6;Vertex coordinates (6,0).

1.The opening is upward, the axis of symmetry x=3, the vertex coordinates, (3,-2)2The opening is downward axis of symmetry x=-2 vertex coordinates (-2,0)3

Opening up Axis of Symmetry x=-5 Vertex coordinates (-5,10)4Opening up axis of symmetry x=6 vertex coordinates (6,0) looking !! Instructions can be given.

The opening direction looks at the coefficient of the quadratic term, positive numbers open up, and negative numbers go down.

The axis of symmetry is the form of y=a x 2+bx+c, and x= -b 2a is the axis of symmetry.

Vertex coordinates (-b 2a, 4ac-b 2 4a).

It should be -x squared -2x, right?

Speak to the salute late stool, axis of symmetry x -1, vertex coordinates.

Opening direction: Go up to the bridge.

The axis of symmetry is voltile: x=1 2

Vertex coordinates: Missing mountain (1 2, -9 4).