Which fairy helped me solve a 5th grade math problem? Detailed .

<> this group of rabbits has a total of 13+24+35+6 = 78 (only)1) 13 of the rabbits who love to eat turnips do not like cabbage, that is.

Eating radish alone + eating both radish and grass: a+d = 13 (only) 2) 24 of the rabbits who love cabbage do not like grass, that is.

Simple cabbage + both cabbage and turnips: b + e = 24 (only) 3) 35 of the little rabbits who love grass do not like to eat turnips, that is.

Simple grass + eating both grass and cabbage: c + f = 24 (only) 4) Rabbits who love to eat all three foods: g = 6

All rabbits are a+b+c+d+e+f+g = 78 (only) satisfied, please ask if you don't know.

Sort out knowledge, help others, and enjoy yourself.

Welcome to the "Mathematics and Physics Infinity" team.

Draw three circles to represent the love of radish, love of cabbage and love of grass, and the overlap of the three circles is the 6 that all three love. And then you find out what each represents, which is 13 + 24 + 35 + 6 = 78

The test is a collection, and I can do it on paper to give you the process, which is not very convenient to do on the computer.

When solving the problem in the fifth grade math problem, you should first find the quantitative relationship in the math problem, find the corresponding number through the quantitative relationship, and then substitute it into the quantitative relationship to find the final result.

In fact, the math problems in the fifth grade of primary school are more or less the concept of Olympiad mathematics in them, so these problems, as long as we understand the causes and consequences of his front and back sequences, I think it is also easy to answer.

There is no problem with the fifth-grade math problem, you can send the content of the problem over, so that it can help you solve it, after all, the fifth-grade problem should be relatively easy to solve.

Please list this question and let us see what it is and if we can solve it for you.

From the title, we know that the butterfly's flight time is hours, and the distance is 3 kilometers. So we can know that the speed of the butterfly is: distance divided by time, that is:

3 m-h=km-h.

And then the bee is twice as fast as the butterfly, so we know that the speed of the bee is: kilometers per hour.

So the answer is: 18 km/h.

According to the speed = distance time, the butterfly speed = distance 3 km hours = km hours; And because the speed of the bee is twice the speed of the butterfly, the speed of the bee = km! So the bee speed is kilometers per hour!

In fact, this is a very good problem to solve.

One uses, three kilometers to remove.

On the scale, so that in the end is your answer.

In fact, this formula has been listed.

So it's a trivial matter, I believe you have learned addition, subtraction, multiplication and division, right?

Solution: Butterflies can fly in an hour (speed):

3 km) The speed of the bee:

km) Answer: Slightly.

The process of solving the equation is called solving the equation, and the solution of the equation must appear at the end x= To solve the equation, pay attention to: 1. Write "solution:" 2 equal signs to its 3 equal signs to reflect the process of simultaneous changes on both sides of the equal sign 4 Each step is a square.

Solution: Set the number of tables to be x; The total number of people who can sit = 4x+2;10 tables sitting: 4 10 + 2 = 42 people; According to the question, there is 4x+2=38 solution, x=9 Answer: 10 tables sit 42 people; 38 people need 9 tables.

20 times 20 times 10 = 4000cm3

30 cubic = 27000cm3

27000 divided by 4000 = 6 remainder 3000cm3 up to 6.

How to pretend to draw your own drawings can be solved.

5 boxes last month the teacher let us make it, and our teacher laid it out for us.

Is it an order or a fraction that is not exhaustive?

Just use a calculator to do the math, I can solve the equations.

24×3+2x=90

2x=18x=917×12-2x=17

2x=187

x=x=4x-2x=3×18

2x= 54

x=273x=x=

x=20x+4=13

x=94x-（

4x=12x=32x-56÷8=18

2x=25x=3x+48÷12=58

3x=54x=18

3x+3x=

x=41/6

x=15(x+

x+x=3x+2x+6=30

5x=24x=

It's so hard, I won't, because I'm only in the first grade of elementary school. But to tell you, you can click on the bottom left of the computer, all programs, accessories, calculators, etc

Are you lazy or won't do it yourself.

With a computer: Click Start and find all programs, accessories, computers.

1.Bei Bei and Tian Tian went from A to B at the same time, Bei Bei took 10 hours, 4 hours more than Tian Tian, and the speed difference between the two is known to be 5 kilometers. What is the distance between A and B? (Solved with equations).

Let the speed of Beibei be x kilometers per hour, and the distance between A and B is y kilometers.

y=10xy=(10-4)(x+5)

x = kilometers per hour.

y = 75 km.

The distance between A and B is 75 km.

2.Do the math, a, b, and c represent 3 integers, respectively, and we know: a b c 5 a b-c 12 a-b 84

So what is the result of a b c?

Quadratic a b c 5

Formula A B-C 12

Three-form a-b 84 a=b+84 is substituted into one formula, two formulas.

Find a=90

b=6c=3

a×b×c=90*6*3=1620

3.Li Ping has 64 **, and after sending 12 ** to Zhang Hua, the number of ** of the two is equal, how many ** did Zhang Hua have?

64-12-12 = 40 sheets.

Zhang Hua originally had 40 sheets**.

4.A monk in a temple eats steamed buns. 100 monks eat 100 steamed buns, one big monk eats four, four small monks eat one, ask how many big and small monks are there?

Set up x people for each big monk and Y for small monks.

x+y=100

4x+y/4=100

x=20y=80

There are 20 big monks and 80 small monks.

5.In the tree planting activity, 10 fewer trees were planted in the sixth grade than in the fifth grade, and 62 more trees were planted in the sixth grade than in the fifth grade. Q: How many trees are planted in each of the two grades?

X trees were planted in the sixth grade, and y trees were planted in the fifth grade.

x=2y-10

x-y=62

x=134y=72

134 trees were planted in the sixth grade and 72 trees were planted in the fifth grade.

6.The elevation of six students in a group was 160cm, 140cm, 145cm, 150cm, 142cm, and 157cm, respectively, and the median of this set of data was requested.

Arranged from largest to smallest: 160cm, 157cm, 150cm, 145cm, 142cm, 140cm

The median of this set of data.

7.The age of a kindergarten child is as follows: 16 children aged 4 years, 18 children aged 5 years, and 16 children aged 6 years old.

5) years, median (5) years.

(1) Solution: Let the distance between A and B be x kilometers.

x/(10-4)-x/10=5

Solution: x=75

A: The distance between A and B is 75 km.

2) Solution: a b c 5, i.e. (a b) c 5

a÷b＝5c

and a b-c 12, i.e. 5c-c=12

4c = 12, i.e. c = 3

a b 15, i.e. a = 15b

a-b 84, i.e. 15b-b 84

14b = 84, i.e. b = 6

a=90a×b×c=90*6*3=1620

64-12=x+12

Solution: x=40

4) Solution: Set up big monks x people, small monks (100-x) people.

4x+1/4(100-x)=100

Solution: x=20

100-x=80

A: There are 20 big monks and 80 small monks.

5) Solution: Set up x trees in the fifth grade.

2x-10=x+62

Solution: x=72

x+62=134

A: 72 trees were planted in the fifth grade.

6) 140 142 145 150 157 167 Median: (145+150) 2=

7) Average age: (4*16+5*18+6*16) (16+18+16) =5

Median: 5 years.

Happy Chinese New Year!

1.Let the distance be x km, then the velocity of Beibei is x 10, the velocity of Tian Tian is x 6, and according to the equation of the question column, x 6-x 10 = 5 is obtained, and the solution is x = 75

2.From a b c 5, a b = 5c, substituting a b-c 12 obtains, c = 3, i.e. a b = 15, all a = 15b, substituting a - b 84 to get b = 6, then a = 90, then a b c = 1620

4.It is relatively simple to use the system of equations, and here it is solved by "chickens and rabbits in the same cage".

Assuming that 100 monks are all great monks, 400 steamed buns are needed, and each big monk eats (4-1 4) more than the small monks.

400-100) (4-1 4) = 80, i.e. 80 for small monks and 20 for big monks.

5.If x trees are planted in the fifth grade, then the sixth grade is (2x-10), the column equation is 2x-10-x=62, and the solution is x=72, that is, 72 trees in the fifth grade and 134 trees in the sixth grade.

6.The order is: 140cm, 142cm, 145cm, 150cm, 157cm, 160cm, then the median is (145+150) 2=

7.The average is: (16*4+18*5+16*6) (16+18+16)=5 years old.

Median: 5 years old.

1.Let the speed of Beibei be x kilometers per hour, and the distance between a and b is y kilometers y=10x

y=(10-4)(x+5)

x = kilometers per hour.

y = 75 km.

The distance between A and B is 75 km.

2.Quadratic a b c 5

Formula A B-C 12

The three formulas a-b 84 a=b+84 are substituted into one formula, and the two formulas are obtained by a=90

b=6c=3

a×b×c=90*6*3=1620

Zhang Zhanghua originally had 40 **.

4.Set up x people for each big monk and Y for small monks.

x+y=100

4x+y/4=100

x=20y=80

There are 20 big monks and 80 small monks.

5.X trees were planted in the sixth grade, and y trees were planted in the fifth grade.

x=2y-10

x-y=62

x=134y=72

134 trees were planted in the sixth grade and 72 trees were planted in the fifth grade.

6.。Arranged from largest to smallest: 160cm, 157cm, 150cm, 145cm, 142cm, 140cm

The median of this set of data.

1.Let the language be dispersed as x, mathematics is 184-x, and English is 186-x

184-x+186-x=99×2

86 in Chinese, 98 in math, and 100 in English

2.Let the small one be x

x-10=（x+2×83）÷2

x=88 Small fraction is 88

Explain that Maths is 1x2 = 2 points higher than English.

99x2+2=200 200 2=100 Math is 100 points.

1 Let the language be x, mathematics be y, and English be z, then you can have a system of equations (x+y) 2=92 (x+z) 2=93 (y+z) 2, and let the small math score be x=99, and the solution is x=86 y=98 z=100

2. Let the small math score be x, then.

2*83+x）/3=x-10

x=983, the time used by A to B is 240 80 = 3 hours, and the time used by B to A is 240 60 = 4 hours.

The total time is 7 hours, and the average speed is 480 7 which is approximately equal to kilometers of hours.

1.（99+93+92）x2÷2=284

English: 284-92x2=100

Language: 284-99x2=86

Math: 284-93x2=98

2.Solution: Let the small math score be x

x-10=(2x83+x)÷3x=98

240x2÷（3+4)=480/7

1.The total score of the three subjects is 92 + 93 + 99 = 284, and the English score is 284-92 x 2 = 100

The math grade is 284-93x2=98

The language score is 284-99x2=86

2.Let the small math score be x

3x-(85x2+x)=30

x=1003.The time taken by A to B is 240 80 = 3 hours, and the time it takes B to A is 240 60 = 4 hours.

The total time is 7 hours, and the average speed is 480 7 km/h.