Write a program in C that can be used to read an array of integers from 5 to 5

C: Write a program that reads a 5x5 array of integers and then displays the sum of each row and the sum of each column.

#include ""

#define n 6

void main()

Put the sum of each column.

The sum of the releases at the beginning of each line, }; int i,j;

printf("Before calculating the sum of the rows and columns of the elements:");

for(i=1;iprintf("");

for(i=1;i}printf("After calculating the sum of the rows and columns of the elements:");

for(i=0;iprintf("");}

If you have any more questions?

#include

#include

#include

#include

int main()

Calculate the sum of each row and column, and if you wish, this calculation can be combined with the input for (i=0; i<5;i++)

Output. for (i=0;i<5;i++)

printf(" | 5d", a[i][5]);

for (i=0;i<30;i++)

printf("%c", '-');

printf("");

for (j=0;j<5;j++)

#include

using namespace std;

void main()

int a[5],max,sum;

cout<<"Please enter five integers:"max=sum=a[0];

for(i=0;i<5;i++)

if(a[i]>max)

max=a[i];

sum+=a[i];

cout<<"The largest number is:"

#include

using namespace std;

void main() test case}cout<<"The maximum value is:"

b[n][m]=ti(a[m][n]);

Access to this array has been out of bounds, and I don't understand what this ti(int a) function is for.

#include

#define m 5

#define n 5

void main(),int b[n][m];

b[n][m]=ti(a[m][n]);

printf("array a:");

for(i=0;i

I don't know what the use of your two paragraphs** is, the result is correct after commenting it out, and there is no problem with the idea.

#include

int main()

This is the first question.

#include

void sort(int *a, int n)}}int main()

This is the second question.

Remember to adopt it!

My shortest If you have any questions, please ask if you are satisfied, please adopt

press any key to continue#include ""

#define n 2

main()

for (i=0;iprintf("%d",minarry[i]);

There are multiple sets of test data, which are processed to the end of the file: this sentence means that Linux first press Ctrl+D, and press Ctrl+Z under Windows (I'm not sure about this, I only play programming under Linux) to end the input. So the cyclic condition should not be equal to EOF.

#include

#include

using namespace std;

int main()

for (int j = 0; j < i; j++)cout

Enter 5 pieces of data multiple times during the test, and press CTRL+D (window?) when you want to finish), the results for each group are output.

I won't write ** here, just give a few suggestions.

1.Define a two-dimensional array, based on space,''Separate the array elements.

2.Write a simplified version of the sorting method (e.g. simple selection, bubbling, etc.), and you can find the minimum value in one sort.

This way the mind is clearer. More in line with the concept of object orientation.

It seems that you can only check whether each number can be added at a time, and if it exceeds it, it will not detect the remaining numbers.