Ask for advice! How did you get interested in math?

I think the landlord may not really dislike math, but he just doesn't have confidence in math.

In fact, I feel that the landlord may have a misunderstanding, that is, only people who are good at mathematics like mathematics, in fact, the real cause and effect relationship is not like this.

Mathematics is something that everyone could have liked, but it was made into a miasma by our test-taking education, such as those Olympiad mathematics or something. But actually, what I want to tell the landlord is that math can be loved.

The mathematics I like is definitely not the usual test-taking mathematics, but exponentialism, including calculation, including reasoning, including deduction, and so on.

Of course, mathematics is not only about topics, if you think that mathematics only has topics, it must be boring and useless, we should pay attention to mathematics, we should pay attention to those mathematical ideas and methods.

So I think if the landlord just wants to improve his grades now, just do some moderately difficult questions like the upstairs said, and then summarize the methods.

If you want to be interested in mathematics, you must first be confident and try to accept mathematics first. I think the landlord is fully capable of doing math. At the same time, it is also necessary to understand that many problems actually have a fixed idea of solving the problem, and the landlord must also sort it out slowly by himself.

Math is actually very pleasant at the moment when the answer is solved. After that, the landlord can try to solve multiple problems to solve multiple problems, propose and ** mathematical methods by himself, or try to discuss or even argue with others.

The real charm of mathematics should be speculation, it should be the process of thinking.

I used to play in the national league, after all, there are always problems that I can't do, but I don't think it's wise to reject math because of this, and if it's just a simple problem, then it shouldn't make it a vicious circle.

So I think what the landlord should do is to give yourself confidence and make thinking a habit.

Math is fun, and it's a good idea to try to help others with some math problems (within your ability).

I often see something that can be touched, but it won't, just look at other people's answers, and it's also interesting to encounter good methods and solutions.

When I was in high school, I only used a set of extracurricular questions, and I tried to solve each problem in as many ways as possible, and I often found a simple and clear method after a complex method, and I felt very happy.

It seems that you are smart, but it is just a matter of interest, and I believe that your foundation will not be too bad and you can catch up. In the lesson, first sort out the knowledge points, and know what you can and can't know, which is also very important.

When studying, you can find some topics to do, according to your own ability. Calm down and do each question, the difficulty of the question should also increase little by little, you can also do a few more questions when you have time, and slowly cultivate your interest. When I was in elementary school, I was seriously biased, and science was not good at all, but now that I am in junior high school, I decided to try to accept it.

It was with this method that my uncle taught me, I don't do more than a dozen uncomfortable tasks every day, sometimes the topic is not written, and I even think about it when I sleep, and even get up in the middle of the night to do it, resulting in no energy the next day. My teacher was also surprised that my science grades were improving by leaps and bounds, so he gave up a class for me to introduce this method to my classmates. It's a really good idea.

Hope I am the best, thanks! I also wish you to improve your math scores by leaps and bounds like mine!!

Based on the textbook, the examples and exercises in the textbook are excellent question types and the difficulty is in the low to medium range. Thoroughly reading the textbook will allow you to score at least 120 points.

Your current math foundation is too poor, it is recommended that you read more textbooks first, and then do more problems, starting with relatively simple problems, and then take your time.

Haven't learned slope in the third year of junior high school? To put it simply, there are two kinds of problems that involve slope.

1.Do you know the one-time function y=kx+b? k is the slope of the image (a straight line) of this function.

2.Given two points a(x1,y1) and b(x2,y2), the straight line ab can be determined, as long as ab is not a straight line perpendicular to the x-axis, there is a straight line ab with a slope of: (y2-y1) (x2-x1).

Theorem: If two straight lines are perpendicular, then the product of their slopes (if both exist) is -1

In fact, the slope is a very simple thing, and you can know it at once. Now that most of the people who have completed high school have a systematic mathematical thinking, they can't strictly distinguish between junior high school and high school knowledge, please forgive me.

Otherwise, you use the Pythagorean theorem, oa 2 + oc 2 = ac 2There should always be a distance between two points, right?

(32+28) (1+2)=20 people.

28-20=8 people So 8 from B to A.

32+28=60

A = 40, 8 people from engineering team B to engineering team A.

Day 1: 45 pages.

Day 2: 45 pages (1-20%) = 36 pages.

36 pages (1 4) = 144 (pages).

<=|x-1|

1)x>=7/2:

2x-7+1<=x-1

x<=5

That is, there are 7 2 < = x < = 5

That is, there are 3< = x<7 2

3)x<1:

7-2x+1<=1-x

x>=7

No solution. To sum up, the solution is 3<=x<=5

2. There is x, there is f(x)=|2x-7|+1<=ax1)x>=7/2:

2x-7+1<=ax

a>=2-6/x

Therefore, there is a>=2-6 (7 2)=2-12 7=2 7, that is, there is a>=2 72)0=8 x-2

Therefore there is a>=8 (7 2)-2=16 7-2=2 73)x<0:

7-2x+1<=ax

a<=8/x-2

Therefore there is a<=-2

In summary, the range is a>=2 7 or a<=-2

f(x)<=|x-1|

2x-7|-|x-1|+1<=0

When x<=1, 7-2x-1+x+1<=0

x>=7 (rounded).

When 1=3, so 3<=x<=7 2

When x>7 2, 2x-7-x+1+1<=0x<=5

So 7 2 sum up the solution set as.

1.(1) When 2x-7>=0, that is, x>=7 2 2x-7+1<=x-1 x<=5 7 2<=x<=5 (2) When 2x-7<=0 and x-1>=0, i.e., 1<=x<=7 2 x>=3 3<=x<=7 2 (3) When x-1<=0, that is, x<=1 x>=7 does not meet the above 3<=x<=5

1、f(x)>=1

There are two cases: when x>=1, 1-x<=f(x)<=x-12x>=7 and 2<=2x<7

At x<1, f(x) > x-1, and f(x) <1-x