3 problems with division, math with division problems?

1.There are 60 3 20 divisible by 3, 60 4 15 divisible by 4, and 60 5 12 divisible by 5. There are 60 12 5 divisible by 3 and 4, 60 15 4 divisible by 3 and 5, 60 20 3 divisible by 4 and 5, and 60 60 1 divisible by 4 and 5.

So the number divisible by 3 or 4 or 5 is 20 + 15 + 12 - 5 - 4 - 3 + 1 36 (the first divisible by 3 and 4, divisible by 3 and 5, and divisible by 5 and 4 are counted 2 times, and the divisible is counted 3 times and subtracted 3 times).

2.Same as above, 500 2 250 500 3 166 (whole number of whole numbers) 500 7 71 500 6 83

So there are numbers that are neither divisible by 2, nor divisible by 3, nor divisible by 7.

500-(166+250+71-83-35-23+11) 143pcs.

3.There were 120+80,200 participants in mathematics competitions and 120+80,200 participants in language competitions.

So there are 200+200-260 140 students who participate in both subjects, and 140-75 65 girls participate.

Therefore, 80-65 15 girls only participated in mathematics competitions and did not participate in language competitions.

It is best to draw a ** decision for this question, and use a circle to indicate the number of people participating in a certain subject, and the intersection of the two circles is the number of people who participate in both subjects.

The first 2 questions are interesting, so do the math yourself. Remember that there are repetitions. Person.

Addition (1)98+25= (2)376+284= (3)135+48=

Subtraction: (1)517—348= (2)507—348= (3) 500—185=

Multiplication (1) 740 6 (2) 209 9 (3) 540 5 (4) 804 9

Division (1)160 4 (2)450 5 (3)455 5=

Application Questions:1The experiment is that Xiaohuai Buxue has built a 400-meter-long circular plastic runway, 130 meters have been completed, and the rest will be completed in 30 days, so how many meters will be built every day on average to complete the task?

2.To celebrate New Year's Day, the students made 65 red flowers and 25 yellow flowers, and asked Mingxing to tie every 5 flowers into a bunch, how many bouquets did the students make?

1.There are 15 apples divided equally among the five children, and how many are they divided into each of them?

1.1 yuan for a book, how much is 10 books?

2.How much is a ballpoint pen, 20 pieces?

3.There is 10 yuan, and it is divided equally among 2 children, how much yuan does each child share?

4.There are 20 pears, and they are divided equally among 5 children, how many are they for each child?

Apples, 2 for each child, how many children can be shared?

Yuan to buy a book, one yuan each, how many copies can you buy?

There are two requirements for this question, one is to circle and the other is to fill it in. You're doing the right thing.

1. The first question. The picture shows 11 pears, each in a group of 2. How many groups can it be divided into? How many are left?

This is the inclusion of division in division.

Find a few in it and use the division.

11 2 = 5 (group) ......1 (pcs).

2. The second question. There are 15 burgers, each in a group of 4, how many groups can be left?

This is the same as a small question, it is all about including division, that is, how many 4s are there in 15?

15 4 = 3 (set) ......4 (pcs).

What problems in life can the 132 divided by 2 you ask solve.

Did you miss a word? To the word, is to divide it.

If so, it's easy to say, this can solve the problem of distribution between two people in life, for example, there is 132 yuan, and the average score of two people is 132 2 = 66, and everyone can get 66 yuan.

There are three main types of division problems in the second grade, 1. There are 45 apples, which are placed on 9 plates on average, how many are placed on each plate? This category is actually an average score.

2. There are 45 apples, an average of 5 per plate, how many plates can be placed? This category actually contains the except.

3. Xiaohong has 15 apples, Xiao Ming has 5 apples, how many times the number of apples in Xiaohong is Xiao Ming? This category is the multiples relationship, find the multiples. However, there is another category in the multiplier relationship is to find a multiple, which does not seem to be the content of the second grade, and I can give another example:

Xiaohong has 15 apples, Xiaohong's number of apples is 3 times that of Xiaoming, how many apples does Xiaoming have?

As for the number, as long as it is a ninety-nine multiplication table, this is called intra-table division.

It is best to be able to talk about the problem and clarify the relationship between the quantities, otherwise it will be rote to memorize, and the thinking ability will not be exercised, and the analytical ability will not be strong in the future.

If you really ask for quantity, you can change the number of the above three questions, and you can change the things you want to score, and you can conjure up a lot of questions.

1. There are a total of 20 pieces of candy, 4 people, how many pieces can each person share?

Answer: 5 pieces. There are six types of meters, how many meters are in each category?

3. A tree planting team has 7 people and plants a total of 35 trees, how many trees are planted per person on average?

4. A person went to buy books, bought 5 books, and spent 40 yuan, how many yuan per book on average?

5. There are 7 cages and 35 birds, how many birds are in each cage? A: 5 pcs.

6. Divide 30 little bears among 5 children, how many are per person? A: 6 pcs.

7. The teacher brought 100 yuan to buy flowers. Each bouquet costs 5 yuan, how many bouquets can the teacher buy? Answer: 20 bunches.

8. There are 45 pieces of chocolate in a box of chocolates, which are distributed to 9 children, how many pieces are there for each person? Answer: 5 pieces.

9. 2 yuan per piece of sugar, and when these sugars were sold out, the idea was transferred to 18 yuan. How many pieces of sugar were there? Answer: 9 pieces.

There are 365 days in a year, and if there are only 365 people, at least no one can have a birthday on the same day. But.

When there are 366 people, at least 2 people have the same birthday.

When there are 367 people, at least 3 people have the same birthday.

When there are 368 people, at least 4 people have the same birthday.

When there are n(n>365) people, at least n-364 people have birthdays on the same day.

Therefore, out of 1000 classmates, at least 1000-364 636 classmates have the same birthday.

By "at least", you find as few ways as possible. If you say "2 per day, 3 in 270 days", then 1000 students are all on the same birthday as others.

1000 365 = 2 The remainder is 270. Then divide the remaining 270 people into other days equally, at least 2+1 people have birthdays on the same day, at least 3, not at least 2, at least number = quotient + 1

2010 Tsinghua University Independent Admissions Test Questions (Recall Version).

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