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The total length of the innermost channel is 2 vy, so there are 2 vy cells in the inner channel, and then the effective width of the disk is 45-y, then the total number of cells is 2 v, *y*(45-y), and the maximum value is taken when y=.
However, the title says"The outer circumference is not a track", so when y is slightly less than the maximum.
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Solution: 1999 1999-1998 2002 The cube root of the root number 3 to the power of -2 + (-64 27).
If x a, x b, there is no solution, then a>b
So -a<-b
So 3-a<3-b
Therefore, the solution set of x 3-a, x 3-b is an empty set.
The cube root of the root number 1 4 + the root number to the 2nd power.
Solve the inequality group: 2x-7 3(x-1), 4 3x+3 1-2 3x solution inequality 2x-7 3(x-1) yields:
2x-7<3x-3
3x-2x>-7+3
x>-4
Solve inequality 4 3x+3 1-2 3x to get:
4/3)x+(2/3)x
2x≥-2x≥-1
So the solution set of the inequality group is x -1
x-1) to the power of 2 + (2x+1) (x-1) + 3x to the power of 2 = (x-1) 2 + (2x + 1) (x-1) + 3 (x 2-1) = (x-1) [(x-1) + (2x+1) + 3 (x+1)] = (x-1) (x-1 + 2x + 1 + 3x+3) = (x-1) (6x+3).
3(x-1)(2x+1)
where x = root number 2 2
Original = 3 (root number 2 2
1) (root number 2 + 1) = 3 (1 - root number 2 2-1) = (3 2) times root number 2.
Little brother (sister): I don't know if the title is like this, the method should be fine.
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Connect to the AC PD CP
ap/pf=ae/af=cd/df
Therefore, PD is parallel to AC
angular cad=adp=acp
Angular CDA=CPA
AC = AC triangle ACD is all equal to CPA
ap=cd
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5 (3x+1)-4 (3y+2)=0 i.e. 5 (3x+1)=4 (3y+2) i.e. 5*(3y+2)=4*(3x+1) i.e. 15y=12x+4-10
5 (2x-1)-4 (3y-2)=0 i.e. 5 (2x-1)=4 (3y-2) i.e. 5*(3y-2)=4*(2x-1) i.e. 15y=8x-4+10
That is, 12x-6=8x+6
So 4x=12 x=3
Substituting any of the original equations yields y=2
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Are you talking about 1/5 and 2/4?
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What is 5/1, that is not 5.
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5/1 and 4/2? Could it be a mistake?
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