Evaluate and define a domain, evaluate a range and define a domain

Updated on educate 2024-04-06
11 answers
  1. Anonymous users2024-02-07

    0 or more under the root number

    2sinx+1>=0

    sinx>=-1/2

    sin(2k - 6) = sin(2k +7 6) = -1 2 so 2k - 6<=x<=2k +7 6 defines the domain [2k - 6,2k +7 6]1 9<=x<=9

    3^(-2)<=x<=3^2

    log3(x) is an increment function if the base number is greater than 1.

    So log3[3 (-2)]<=log3(x)<=log3(3 2)2<=t<=2

  2. Anonymous users2024-02-06

    sinx≥-1/2

    x (2k, 5 6+2k), k is an integer.

    2.When x=1 9, log3x=log3(1 9)=-2, when x=9, log3x=log39=2

    After log3x=t, the definition field of x becomes [-2,2].

  3. Anonymous users2024-02-05

    1, under the root number, greater than "=0".

    That is, 2sinx+1>=0

    So sinx>=-1 2

    So 2k - 6<=x<=2k +7 6, so the domain is defined as [2k - 6,2k +7 6]2,1 9<=x<=9

    log3(x) is an increment function if the base number is greater than 1.

    log3(1 9)<=log3(x)<=log3(9), that is, log3(1, 9)<=t<=log3(9), that is, -2<=t<=2

  4. Anonymous users2024-02-04

    In the deformation investigation of the exponential function image and properties, it is necessary to consider that the denominator of the unknown is not equal to 0 in the denominator.

  5. Anonymous users2024-02-03

    Since the denominator of the division is not zero, the first question, the definition domain is.

    ∞,1)u(1,+∞

    The range is (0, 1)u(1, +

    Question 2: Defining the domain is.

    ∞,1/4)u(1/4,+∞

    Range: Same as the range of the first question.

  6. Anonymous users2024-02-02

    Process RT ......I hope to accompany the bend to help Yuanyuan to your orange mess.

  7. Anonymous users2024-02-01

    Question 1: Let y=x-1

    Let the function be intentionally searchable or meaningful.

    then 1-(1 2) y 0

    Then (1 2) y 1

    y 0 is leaked x-1 and let Wu 0

    So define the domain x 1

    value range [1, positive infinity].

    2 questions. <>

  8. Anonymous users2024-01-31

    f(x)=x |x|≤1

    f(x)=x² 1<|x|≤4

    f(x) is defined in the domain -4 x 4

    f(x²)=x² |x|≤1

    f(x²)=x⁴ 1<|x|≤2

    f(x) is defined in the domain -2 x 2

    f(x+3)=x+3 -4≤x≤-3

    f(x+3)=(x+3) 7 x<-4 -3g(x): -2 x 1

    g(x)=x⁴+(x+3)² 2≤x≤-1g(x)=x²+(x+3)² 1

  9. Anonymous users2024-01-30

    You can first classify and discuss the different ranges of the congregations according to the topic, find out the percolation noise in different value ranges, and then take the union set. For the Li rent definition domain, the title has been given, that is, the range x given by the title.

  10. Anonymous users2024-01-29

    The exponential function has no requirements for exponents, so the domain is defined as r, the exponent is 3+2x-x, and its value range is (- 4), and (1 2) x is a subtraction function, so as for that.

  11. Anonymous users2024-01-28

    Range'-1--third, defines the domain'Except for 120-120 degrees away from everything.

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