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This can be done by dividing the first gunpowder into four sections (the uniform point of the division), dividing the second into three sections, and then the four sections of the first and the three sections of the second burning at the same time, if any of the four sections of the first is burned. and extinguish everything else for the time being. Divide the remaining three sections of the first gunpowder into four sections.
IN THE TIME TO IGNITE ALL ...
Plainly. The first gunpowder lead has four points burning at all times. And the second gunpowder lead has three points burning at any given moment.
So when the first gunpowder is just burned out. The time is 15 minutes. Such.
The second gunpowder ignited for 15 * 3 = 45 minutes. The remaining gunpowder can be burned for 15 minutes. Such.
Drain the second gunpowder and burn the rest to give you 15 minutes.
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This question is probably not from elementary school.
First of all, let one gunpowder citation be a and the other be b
Fire both ends of A and one end of B at the same time.
When A is all burned, extinguish B, and 30 minutes have passed, and the remaining length of B can be burned for 30 minutes.
Then ignite both ends of b at the same time, so that you can get 15 minutes.
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Burn any strip in front of the watch for 45 minutes, and the rest is 15 minutes.
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Twist the two pills into one, fold them in half twice and burn them in half for 15 minutes.
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I think the question should be, how to burn both in 15 minutes.
The two pills are twisted into one and folded in half twice.
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By: gdsyshuzai - assistant secondary is on the drop.
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The hour hand turns twice, and the route it has drawn is two circles, calculate the circumference of the circle, multiply it by 2, and you can do it.
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The tip of the hour hand takes the route of a day and night, that is, the trace of the 24-hour hour hand, that is, two circles.
So find the circumference of the circle by multiplying it by 2
The length of the hour hand is also the radius of the circle.
5*2*cm).
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Knowing the radius of the hour hand, the hour hand travels 2 times a day and night, that is, the circumference of a circle with a radius of 5 cm = pi, radius, 2·2
Centimeter.
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A day and night are 24 hours, and if the hour hand crosses a circle, the radius is 5 cm.
c =2 π r
10 (cm) because of the two weeks of rotation 2c=2 10 =20 (cm).
A: There are 20 centimeters in total.
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Centimeter.
A: There are centimeters in total.
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Since the clock face is circular and 5cm is the radius, the circumference of the circle is required: 5x2x =
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To walk in one circle is to draw the circumference of a circle, because the hour hand takes two circles in one day and night, so it is twice the circumference of a circle with a class of five, level 2*
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It can be understood as: how many centimeters are there around a circle with a radius of 5 centimeters?
The diameter is 2*5=10 cm cm.
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Isn't that counting the length of a circle. A circle with a radius of 5 centimeters, its circumference is the answer.
2 r=2 cm.
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The hour hand turns twice, so yes.
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It takes 60 minutes for the minute hand to turn around (360 degrees), so the speed of the minute hand is 6 degrees It takes half a day for the minute hand to turn around (360 degrees), that is, 60 minutes multiplied by 12, then the speed of the hour hand is the degree minute.
When Xiao Ming leaves the house, it is three o'clock, that is, the minute hand and the hour hand are 90 degrees apart, assuming that Xiao Ming leaves the house for x minutes, then the following equation can be obtained 6x-90=
A simple calculation shows that x=180 11 is about equal to more than 16 minutes after Xiao Ming left home.
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Suppose it is 6 o'clock x at this time, and the hour hand must be in front of the minute hand like a hailstorm!
At this time, the hour hand is at the sail angle with the slag of the figure 6.
x/(12*60)]*360
x 2 degrees. At this point, the angle between the minute hand and the figure 6.
6/12)*360-(x/60)*360180-6x
180-6x=x/2
13x/2=180
x=360/13=
It was 6:27:42.
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If you don't take into account the breaks:
08:00 20:00 is 12 hours, or 43,200 seconds.
43200 3000 = seconds.
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If you don't understand the learning problem, go to the elite official website to ask for advice
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Intelligence questions, IQ test. How many squares are there?
16 + 9 + 4 + 5 + 5 + 1 = 40 (pcs).
Quiz everyone: This is a math problem that can measure whether a person has business acumen. Master Wang is selling fish, a pound of fish at a price of 45 yuan, now a big sale at a loss, the customer bought a kilogram for 35 yuan, gave Master Wang 100 yuan fake money, Master Wang has no change, so he asked a neighbor for 100 yuan.
Afterwards, the neighbor found out that the money was fake in the process of depositing money, and it was confiscated by the bank, and Master Wang lost 100 yuan to the neighbor, how much did Master Wang lose in total?
Note: The difference between catties and kilograms.
A total loss of 100 + (45 2-35) = 100 + 55 = 155 yuan.
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Because it's an encounter.
So the time for A and B to go is the same.
Therefore, the ratio of the velocity of A and B is 3:5
So B's speed is 60*5 3=100km
h then 100*10=1000km
Here's the answer.
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Once at 6:30, once at 12:30, once at 18:30, once at 0:30, a total of four times.
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It should be counted as tomorrow, as long as the points are added to six in turn.
The key is in oneself, and everyone understands it differently.
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This question scores whether the courier company does not rest 24 hours a day, or does it have an off-duty time and what time to get off work every day.
If there is no rest for 24 hours, the 24 hours are counted as a day, and 24:30 is counted as today. The first shipment is at 6:30, the second at 12:30, the third at 18:30, and the fourth at 24:30
If you leave work, you can only send it three times a day. 6:30, 12:30, 18:30. I will leave work at 24:30, and it will be impossible to ship.
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It's 3 times, definitely 3 times. 24:30 doesn't count.
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It can be obtained from the title.
Little red speed = (12 * 2 5) 2 = 12 5 km hours whole time = 12 (12 5) = 5 hours.
She arrives at her grandmother's house = 8:30 + 5 = 13:30
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It took 2 hours to walk two-fifths of the way, so the whole journey was 5 hours, so it was 13:30.
1) 5525 is obviously divisible by the smallest prime number 5 except 1, which is the easiest to see, so after dividing 5, we can get 1105, and the same as above can obviously be divided by 5 again, and we get 221, which is already a prime number, so the 3 prime numbers found are 5,5,221, so the surface area can be s=2(5*5+5*221+5*221)=4470 >>>More
1。The total length of this road is y.
40%*y+4+50%*y=y-36 >>>More
1 2000 can be simplified by hypothesis Hypothesis 1: (1+1 2+1 3)*(1 2+1 3+1 4)-(1+1 2+1 3+1 4)*(1 2+1 3) The result is 1 4 Hypothesis 2: (1+1 2+1 3+1 4)*(1 2+1 3+1 4+1 5)-(1+1 2+1 3+1 4+1 5)*(1 2+1 3+1 4) The result is 1 20 (1+1 2+1 3+. >>>More
I only thought of this method, so I'll talk to you.
A six-digit number, so the first digit can be taken from 1-9. >>>More
Assuming that the speed of A and B is that the distance between the two stations is Z, the first time is after the t1 time, and the second time is T2, when the first encounter, A and B have traveled the whole distance Z, because the first time they meet 12 kilometers west of the midpoint, and it is 12kmt1=z 2-12 xThe second meeting place is 20 kilometers away from the East Railway Station, and A has already traveled Z+20kmT2=Z+20 x The system of equations (Z 2-12) (x+y) x=Z can be obtained from the above; (x+y)(z+20) x=3zEquation2 Equation 1 yields (2z+40) (z-24)=3 and z=112