Time math problems elementary school will do, elementary school math time problems

Updated on educate 2024-04-06
28 answers
  1. Anonymous users2024-02-07

    This can be done by dividing the first gunpowder into four sections (the uniform point of the division), dividing the second into three sections, and then the four sections of the first and the three sections of the second burning at the same time, if any of the four sections of the first is burned. and extinguish everything else for the time being. Divide the remaining three sections of the first gunpowder into four sections.

    IN THE TIME TO IGNITE ALL ...

    Plainly. The first gunpowder lead has four points burning at all times. And the second gunpowder lead has three points burning at any given moment.

    So when the first gunpowder is just burned out. The time is 15 minutes. Such.

    The second gunpowder ignited for 15 * 3 = 45 minutes. The remaining gunpowder can be burned for 15 minutes. Such.

    Drain the second gunpowder and burn the rest to give you 15 minutes.

  2. Anonymous users2024-02-06

    This question is probably not from elementary school.

    First of all, let one gunpowder citation be a and the other be b

    Fire both ends of A and one end of B at the same time.

    When A is all burned, extinguish B, and 30 minutes have passed, and the remaining length of B can be burned for 30 minutes.

    Then ignite both ends of b at the same time, so that you can get 15 minutes.

  3. Anonymous users2024-02-05

    Burn any strip in front of the watch for 45 minutes, and the rest is 15 minutes.

  4. Anonymous users2024-02-04

    Twist the two pills into one, fold them in half twice and burn them in half for 15 minutes.

  5. Anonymous users2024-02-03

    I think the question should be, how to burn both in 15 minutes.

    The two pills are twisted into one and folded in half twice.

  6. Anonymous users2024-02-02

    By: gdsyshuzai - assistant secondary is on the drop.

  7. Anonymous users2024-02-01

    The hour hand turns twice, and the route it has drawn is two circles, calculate the circumference of the circle, multiply it by 2, and you can do it.

  8. Anonymous users2024-01-31

    The tip of the hour hand takes the route of a day and night, that is, the trace of the 24-hour hour hand, that is, two circles.

    So find the circumference of the circle by multiplying it by 2

    The length of the hour hand is also the radius of the circle.

    5*2*cm).

  9. Anonymous users2024-01-30

    Knowing the radius of the hour hand, the hour hand travels 2 times a day and night, that is, the circumference of a circle with a radius of 5 cm = pi, radius, 2·2

    Centimeter.

  10. Anonymous users2024-01-29

    A day and night are 24 hours, and if the hour hand crosses a circle, the radius is 5 cm.

    c =2 π r

    10 (cm) because of the two weeks of rotation 2c=2 10 =20 (cm).

    A: There are 20 centimeters in total.

  11. Anonymous users2024-01-28

    Centimeter.

    A: There are centimeters in total.

  12. Anonymous users2024-01-27

    Since the clock face is circular and 5cm is the radius, the circumference of the circle is required: 5x2x =

  13. Anonymous users2024-01-26

    To walk in one circle is to draw the circumference of a circle, because the hour hand takes two circles in one day and night, so it is twice the circumference of a circle with a class of five, level 2*

  14. Anonymous users2024-01-25

    It can be understood as: how many centimeters are there around a circle with a radius of 5 centimeters?

    The diameter is 2*5=10 cm cm.

  15. Anonymous users2024-01-24

    Isn't that counting the length of a circle. A circle with a radius of 5 centimeters, its circumference is the answer.

    2 r=2 cm.

  16. Anonymous users2024-01-23

    The hour hand turns twice, so yes.

  17. Anonymous users2024-01-22

    It takes 60 minutes for the minute hand to turn around (360 degrees), so the speed of the minute hand is 6 degrees It takes half a day for the minute hand to turn around (360 degrees), that is, 60 minutes multiplied by 12, then the speed of the hour hand is the degree minute.

    When Xiao Ming leaves the house, it is three o'clock, that is, the minute hand and the hour hand are 90 degrees apart, assuming that Xiao Ming leaves the house for x minutes, then the following equation can be obtained 6x-90=

    A simple calculation shows that x=180 11 is about equal to more than 16 minutes after Xiao Ming left home.

  18. Anonymous users2024-01-21

    Suppose it is 6 o'clock x at this time, and the hour hand must be in front of the minute hand like a hailstorm!

    At this time, the hour hand is at the sail angle with the slag of the figure 6.

    x/(12*60)]*360

    x 2 degrees. At this point, the angle between the minute hand and the figure 6.

    6/12)*360-(x/60)*360180-6x

    180-6x=x/2

    13x/2=180

    x=360/13=

    It was 6:27:42.

  19. Anonymous users2024-01-20

    If you don't take into account the breaks:

    08:00 20:00 is 12 hours, or 43,200 seconds.

    43200 3000 = seconds.

  20. Anonymous users2024-01-19

    If you don't understand the learning problem, go to the elite official website to ask for advice

  21. Anonymous users2024-01-18

    Intelligence questions, IQ test. How many squares are there?

    16 + 9 + 4 + 5 + 5 + 1 = 40 (pcs).

    Quiz everyone: This is a math problem that can measure whether a person has business acumen. Master Wang is selling fish, a pound of fish at a price of 45 yuan, now a big sale at a loss, the customer bought a kilogram for 35 yuan, gave Master Wang 100 yuan fake money, Master Wang has no change, so he asked a neighbor for 100 yuan.

    Afterwards, the neighbor found out that the money was fake in the process of depositing money, and it was confiscated by the bank, and Master Wang lost 100 yuan to the neighbor, how much did Master Wang lose in total?

    Note: The difference between catties and kilograms.

    A total loss of 100 + (45 2-35) = 100 + 55 = 155 yuan.

  22. Anonymous users2024-01-17

    Because it's an encounter.

    So the time for A and B to go is the same.

    Therefore, the ratio of the velocity of A and B is 3:5

    So B's speed is 60*5 3=100km

    h then 100*10=1000km

    Here's the answer.

  23. Anonymous users2024-01-16

    Once at 6:30, once at 12:30, once at 18:30, once at 0:30, a total of four times.

  24. Anonymous users2024-01-15

    It should be counted as tomorrow, as long as the points are added to six in turn.

    The key is in oneself, and everyone understands it differently.

  25. Anonymous users2024-01-14

    This question scores whether the courier company does not rest 24 hours a day, or does it have an off-duty time and what time to get off work every day.

    If there is no rest for 24 hours, the 24 hours are counted as a day, and 24:30 is counted as today. The first shipment is at 6:30, the second at 12:30, the third at 18:30, and the fourth at 24:30

    If you leave work, you can only send it three times a day. 6:30, 12:30, 18:30. I will leave work at 24:30, and it will be impossible to ship.

  26. Anonymous users2024-01-13

    It's 3 times, definitely 3 times. 24:30 doesn't count.

  27. Anonymous users2024-01-12

    It can be obtained from the title.

    Little red speed = (12 * 2 5) 2 = 12 5 km hours whole time = 12 (12 5) = 5 hours.

    She arrives at her grandmother's house = 8:30 + 5 = 13:30

  28. Anonymous users2024-01-11

    It took 2 hours to walk two-fifths of the way, so the whole journey was 5 hours, so it was 13:30.

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