Solve a system of 2 element 1 order equations, and solve a system of 2 element 1 order equations

1)31a+5b=11 (1)

62a+15b=77 (2)

2)-(1)*2 to get 5b 55, b 11

Substituting (1) yields a -44 31

2)x+y+z=26 （1）

x-y=1 to x y+1 (2).

2x+z-y=18 （3）

Substituting (2) into (1) and (3) yields 2y+z 25 (4) and y+z 16 (5).

4)-(5) gives y 9, so z 7, x 102x+5y+z=7 (1).

5x-2y+z=8 （2）

3x-y-z=2 （3）

1)-(2)--3x+7y-1 (4).

1) + (3) to get 5x+4y 9 (5).

4) 5 (5) 3 get 47y 22, y 47 22 so, x 1 11, z -85 22

1: Multiply 3 93a+15b=33 minus 2nd ====>61a=-44==>a=-44 61

You can do it in your place, or you can multiply the first formula by 2 and subtract the following formula ==>-5b=-55==>b=11

2:x+y+z=26

x-y=12x+z-y=18 the first plus the third 3x+2z=44, the first plus the second 2x+z=27

>x=10 z=7 y=6

3: The first plus the third 5x+4y=9

The second plus the third 8x-3y=10

32+15)x= 40+27 x=67/47 (32+15)y= 72-50 y=22/37

.Is it wrong, why is it so messy? That's the way to do it!! It's not easy!!

31a+5b=11 －－62a+10b=2262a+15b-（62a+10b）＝77-22x-y=1－－－x＝y＋1

Bring in the other two equations.

Equation a: 2x+5y+z=7

Equation b: 5x-2y+z=8

Equation c: 3x-y-z=2

c×2-b －－x-3z＝-4

a＋2b＋c －－15x+2z＝25

x 1 40 y 1 40 490x 1 40 · 70 y 1 40 · 90 399

x＋x＋14y＝4900

98x＋126y＝39900

Expand 14x 14y 4900 7 times at the same time.

x＋98y＝34300

98x＋126y＝39900

Subtract the two formulas. 28y＝5600

y=200 is obtained by substituting y=200 into the formula.

x＋x＋x=1502.﹛x＋y＝7

10y x 10x y 100x y 10y x simplify 10y x 10x y 100x y 10y x 10y x 10y x 10y x 10y x 10y x 10y x 10y x 10y x 10y x 10y y 10y x 10y y 10y y 10y y 10y y 10y y 10y y 10y 10y y 10y y 10y y 1

y=6x is obtained by substituting the above equation into x+y=7. x=

y=63﹛x＋y＋z＝35

x／10＋y／16＋z／20＝2／5

x／20＋y／16＋z／10＝53/20

Simplify x 10 y 16 z 20 2 5x 20 y 16 z 10 53 20 respectively.

8x＋5y＋4z＝32

4x＋5y＋8z＝212

Finishing: x y z 35

8x＋5y＋4z＝32

4x＋5y＋8z＝212

x＝-37y=88z=-4

, multiply the above formula by 5, multiply the lower formula by 3, subtract v to get u=, and substitute the above formula to get v=-2

From the above equation to get y=3x, substitute the following formula to remove y, get x=2, get the limb argument y=6

From the following simple trembling formula we get 6x=-7y, substituting the above formula to get y=6, get x=-7

The following formula minus the above formula gives 2y+|x|-|x|-y=9-7, get y=2, get |x|=5, x=5 or -5 can be obtained.

From what is known|1/2a-1|It is definitely not a negative number, (b-3)2 is definitely not a negative number, and the sum of two numbers that are not negative numbers is equal to 0, then it must be 0, so a=2, b=3, the above formula plus the following formula subtract y, get x=2, get y=1

150y=4/5x

200(y-1)=x+25

Multiply by 5

750y=4x

Multiply by 4

800（y-1）=4x+100 ④

Get. 800（y-1）-750y=100

50y=900

y=18 substitute y=18 into , get.

x=750*18/4=3375

In summary, x=3375

y=18

1. x+y=350 y=200 x=150

Second, x+y=7 is 10y+x=11x+y10x=9y3 by the second formula

323x+457y=1103 (1)117x+543y=777 (2)(1) multiplied by 117 to get 37791x+53469y=129051 (3).

2) Multiply by 323 to get 37791x+175389y=250971 (4).

4)-(3) 121920y=121920 => y=1 substituting y=1 into (2) to get 117x+543=777 => 117x=234 => x=2

The solution of the system of equations is x=2, y=1

How to solve a system of binary equations!

Multiply each side of the two equations

9x+12y=48 3 formula.

10x-12y=66 4 formula.

Formula 3 plus 4, left = 19x

Right = 114

x=6y=-1/2

An equation in which both sides of the equation are integers, contain two unknowns, and the order of the terms containing the unknowns is 1, which is called a binary linear equation; The value of an unknown that equalizes the left and right sides of the equation is called the solution of the equation.

The understanding of the solution of a binary linear equation should pay attention to the following:

In general, there are an infinite number of solutions to a binary equation, and each solution refers to a pair of values, not to the value of a single unknown;

A solution to a binary equation is the value of a pair of unknowns that equalizes the left and right sides of the equation; Conversely, if a set of values equalizes the left and right sides of a binary equation, then that set of values is the solution of the equation;

When finding the solution of a binary linear equation, the usual practice is to use an unknown to represent another unknown, and then give a value to this unknown, and accordingly obtain the value of another unknown, so that a solution of the binary linear equation can be obtained.

How to solve a system of binary equations!

x=2y3 generations, such as the first equation.

2y/3）*6-5y=2

The solution is y=-2

x=-4/3