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3(x-1)=y+5 simplified: y=-5+3x-3=3x-8 (one) 5(y-1)=3(x+5) simplified: 5y-5=3x+15 simplified: 5y=3x+20 (two).
1 formula) * 5 = (2 formulas) so get: 5 (3x-8) = 3x + 20 15x-40 = 3x + 20 12x = 60 from this x=5
Combine x = 5 generations to get y=15-8=7
So x=5 y=7
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3x-3=y+5
3x+15=5y-5
The synthesis yields 4y=28
Obtain y=7 and substitute x=5
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The addition of 12 formulas simplifies y, and substituting x
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x=6,y=4
5x+3y=42 ①
x+y=10 ②
From x=10 y
Substitute x=10 y
Get 5 (10 y) 3y = 42
y=4 substitute y=4 into x=10 y
x=6x=6, y=4
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2x+2y=80
xy=750
x+y=40
x-y) Defeat cover inspection trouble=(Yu Da x+y) -4xy=40 -4 750=-1400 0 No solution.
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a=150,b=
Subtract the two formulas to give b=; Substitution yields a=150
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The one on the first floor seems to have miscalculated?!! b=2/3,a=700/3
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Solution: a+b=-3 2
a*b=-7/2
a=-3/2-b
b(-3/2-b)=-7/2
b2+3/2b-7/2=0
2b2+3b-7=0
a=(-3+root65)4,b=(-3-root:65)4,a=(-3-root:65)4,b=(-3+root:65)4,
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a=(-3+root65)4,b=(-3-root:65)4,a=(-3-root:65)4,b=(-3+root:65)4,
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Misunderstanding in the range of real numbers.
The above system of equations can be deformed as: 2a 2-3a+7=0 because (-3) 2-4*2*7=-47<0, so there is no solution in the range of real numbers.
However, there is a solution in the imaginary range.
It should be provided for i 2 = -1;1) = i can be used to find the root formula.
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The first equation touches x=()y
Then substitute equation 2 to solve one.
Then substitute the first formula and pull it.
This equation is generational and generational. I don't count the data, I didn't learn math well in primary school...
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The addition of the two formulas yields 60 y=3
Therefore, y=30 can be solved, then x=25
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From the formula (1) to get a = b + 3, and then substitute this formula into (2) to get: 16 (b + 3) + 4b - 3 = 5, 20b = 56, so b = then a =
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Simplifying 2 first, we get 4a+b=2 b=2-4a.Substituting b=2-4a into equation 1 gives a-2+4a-3=0, a=1, substituting a=1 into equation 1, there is 1-b-3=0, and b=-2
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