Geared motor Answers to some questions about geared motors!

The problem of oil leakage in the use of the geared motor is generally due to the poor sealing of the geared motor itself, which leads to oil overflow, or the geared motor exceeds the limited amount when refueling and causes overflow, and the other is caused by eating heat, and the uneven heating leads to the overflow of gear oil.

If the noise emitted by the geared motor is really loud, then it is necessary to check whether the geared motor lacks lubrication, or the shaft is damaged and rubbed.

Before choosing a geared motor, you must know what the working load of the geared motor you need is approximately, and you must choose the geared motor according to the actual working situation.

Shenzhen Zhaowei is a high-tech enterprise specializing in the production of various micro geared motors, the company's micro geared motors have stable performance, low noise and high performance.

Just change the oil.

Shanghai Tianhai of reduction gearbox plastic is good, and there are many die-casting in Ningbo.

1.The oil leakage of the geared motor is caused by poor sealing, a itself sealing oil problem b the seal is worn c, the gear is heated, resulting in oil thinning and oil leakage.

2.The motor will produce noise, which is a problem of motor production, as long as the motor will have sound, but the size is different, the reducer also has a sound, and the friction sound of the gear will be relatively loud in use, and the manufacturer may be better if it is good.

There will be noise... This is a problem caused by the performance of the motor itself. German and Japanese geared motors are recommended. The performance is relatively good.

The reducer can be more stable and better to use the effect, which is a very important part of the selection of the motor, the selection of the motor must be matched with the reducer, otherwise it may cause damage problems, let's learn some common sense of matching.

The motor and the reducer must be matched with the power. You can't take the big with the small, and you can't bring the big with the small. The power of the motor we can pass the nameplate.

See, the parameters of the reducer (speed, torque, etc.) must be determined first, and then the appropriate motor must be matched according to the parameters of the reducer.

The two self-schemes, first calculated, according to the torque value of the output shaft and the speed of the output shaft, the output power is calculated.

This value is then multiplied, which is called the power margin. Another way is very simple, directly ask the staff who sell reducers: how big a motor should be equipped with their reducer. This is standardized, and the manufacturer's design engineers are more professional.

If the power of the reducer is not the same as the power of the motor, the motor resistance is at least 2 times the rated torque when overloaded, and the reducer is easily damaged. This is not done unless there are reliable protection measures in place or to ensure that an overload condition is never possible.

When the reducer is connected with the motor, it is directly set on the main shaft of the working machine, and when the reducer is running, the reaction torque acting on the box body is also installed on the reaction moment bracket or balanced by other methods, and it is directly matched, and the other end is connected with the fixed bracket.

The motor is matched with the reducer to make it run better and improve work efficiency at the same time.

When matching the motor to the reducer, a Zen pin must follow the correct method, or directly find the manufacturer or sales staff to match, so that it is easier to make a correct judgment.

According to the power formula of the motor: p=t

When the output torque of the stepper motor is nm, after the deceleration of the reducer, the angular velocity at this time is one-tenth of the original angular velocity, then if the friction and mechanical loss in the process are not considered, the torque output of the reducer is ten times the torque of the motor, that is, the output torque is 1nm at this time, and this process is equivalent to sacrificing speed to increase the torque.

If the output torque of the stepper motor is 1 nm after the acceleration reducer, the final output speed of the reducer becomes 1/10. It is equivalent to sacrificing speed to increase torque.

After the stepper motor is connected to the reducer, the output torque will increase, but the output speed will also decrease proportionally. If the equipment is running at a higher speed, it is better to choose a motor with a higher torque and reduce the reduction ratio.

It can be roughly equal to this, and the premise is that the mechanical loss of the gear is 0 (ideal, haha).

1. The use of reducer can effectively maintain the role of the motor. During operation, the gear unit receives more torque. When overloaded, it is transmitted to the motor as long as the overload is divided by the value of the reduction ratio.

2. Save the use cost, if directly borne by the motor, it may cause damage to the motor. When the overload is very large, the reducer is destroyed first, and only the replacement of spare parts is needed to restore the normal operation of the reducer. The cost is relatively low, and if the direct damage to the motor is repaired relatively slowly, the cost is also higher.

3. Effectively reduce the moment of inertia, and the reducer can control the start-stop and speed change in time. After the reducer increases, the torque is equivalent to increasing the input power, and the balance can reduce the power required by the input motor (where the speed adjustment is required), and the motor is generally more expensive than the reducer, so consider using the reducer. 4. It can effectively save energy, and the use of reducer can meet the requirements of motor output torque and current.

5. The reducer can effectively reduce the speed of the motor, increase the torque, and output the corresponding doubling and reduction ratio according to the motor output. 6. Effectively reduce the load inertia of the motor. Numerical inertia is the square value of the reduction ratio.

Different motor inertia values are different.

The "torque" of the motor in n·m (Nm).

It is calculated as t=9549 * p n.

p is the rated (output) power of the motor, the unit is kilowatts (kw), the denominator n is the rated speed, the unit is rpm per minute (r min), and the torque you are looking for is (9549*

The above brother gave the correct formula, of course, the reducer also counts the transmission ratio and transmission efficiency.

m=9550*p*i*η/n

Torque m" in n·m (Nm).

p is the rated (output) power of the motor, the unit is kilowatt (kw), the denominator n is the rated speed, the unit is rpm per minute (r min), i speed ratio, n motor speed, transmission efficiency.

Are you sure that the speed ratio of your reducer is 1:23? Is the speed of the geared motor 85 rpm?

Is the motor a six-pole motor 970 rpm? Because the geared motor parameters you provided don't match. If the four-pole motor is 1460 rpm, the speed of the stirring slurry is 63 rpm, and if the six-pole motor is used, the speed of the geared motor is 42 rpm.

So you made a mistake when you purchased the geared motor.

You can do without pulley rotation when you start designing, unless your agitator requires multiple speed changes. The spiral bevel gear reducer motor has a hollow flange installation method, which can be placed directly on the frame and connected to the mixing shaft. Vertical reducer can also be used.

The selection of motor power is related to the speed of the motor, the characteristics of the material, the type of pulp, and the height setting of the baffle. The gear reducer motor found Yu Dongxing.

Each geared motor has its permissible torque, as long as it does not exceed it. And you increase the pulley on the basis of the original design to increase the speed, not to slow down. Q937 Sanlu 7996

Just ask a manufacturer who makes a blender and let them give you a plan.

1. High-power gear reduction motor.

2. Coaxial helical gear reduction motor.

3. Parallel shaft helical gear reduction motor.

4. Spiral bevel gear reduction motor.

5. YCJ series gear reducer motor.

6. Worm gear and worm reducer motor To determine the model of a reducer motor, the following parameters need to be determined:

1. Determine the running speed of the machinery, and calculate the reduction ratio of the gear reducer motor according to this speed (reduction ratio = inlet shaft speed, output shaft speed = motor speed, mechanical required speed);

2. Calculate the torque of the load, select the output of the gear reducer motor according to this torque (refer to the "output torque table" provided by the gear reducer motor manufacturer), and determine the model of the gear reducer motor;

3. Determine the additional functions of the deceleration motor, such as power-off brakes, energized brakes, frequency conversion, shrinking frames, shell materials, etc., some additional functions can only be provided by specific factories, so when choosing, communication with the first business is very important.