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You don't have any questions, what are the answers? Are the reward points an exhibit?
Pony 2... What a novel creature is that...
3 unknowns, 2 relations, and the answers are not fixed.
You can first solve the title:
100 horses, 100 tiles, 3 large camels, and two ponies carrying one. Q: How many big horses and ponies are there? Then replace the big horse and the pony with the second horse.
Count below the number of 100 horses and ponies carrying a total of 100 tiles, horses and ponies.
100*3-100) (Assuming that all are Malaysian's solutions.......)80 ponies and 20 horses were to carry a total of 100 tiles.
The number of pack tiles.
Malaysia: Two Horses: Ponies = 3:2:
First, if we replace the quantitative relationship between an equal number of ponies and horses with two horses, 3-2) :(3 ......It's hard to understand, think about ......
Yes, the number of tiles for 5 horses is the same as for 3 horses and 2 ponies.
Then replace 3 large horses and 2 small horses with 5 second horses with an equal relationship.
Get a series of data, 20 0 80
Hopefully, for the sake of such a hard work!
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Solution: Set up big horses, medium horses, and small horses each have A, B, and C horses.
a+b+c=100 ①
3a+2b+c/2=100 ②
2 gets 6a+4b+c=200
Get 5a+3b=100
a=20-3b/5≥0
b≤30bac
Thus, there are 7 groups in total.
Malaysia has , 11, 8, 5, 2
There are middle horses and small ponies have
If you want to have them, then you have to remove this group
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If you don't have a master, help you solve it, and if you want the process, you can ask your teacher and let him not help you.
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This question can be used.
Analytically proves the inequality.
Here's how to solve it!
Got it.
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Open the root number, 2 opened the root number, and then multiply by 3, the result is, plus 4 is, this is calculated according to 3 times the root number 2, because it looks like what you write is not like opening 3 power.
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;Subtract the two to see if the result is greater than 0.
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The dumber way is to honestly calculate the derivative step by step and bring in x=0
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Associative Law Add 2 and 3/7 and 2 and 4/7 to get 5, and then.
The one on the right adds 5/12 and 7/12 to 1, and then 2/9 gives 1 and 2/9
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Question 4:
Analysis: Laughing Uncle Zhang.
I am 7 years old and 33 years old.
After x years 7+x 33+x
The key to solving equations is to find equiquantity relations; Uncle Zhang is 3 times older than Xiaoxiao after X years, according to this equation of the equivalence off series:
3(7+x )=33+x
Therefore, this question is selected: b
Question 5: Bring x=3 into the given option, choose a. Mathematics is generally a multiple-choice question, and you don't need to count it down after confirming that it is A.
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