How many times a year does Xiaoxiao s dad swim and play, and the two payment methods use the same am

If you need money for swimming, one is to give money at a time, and the other is to apply for a card.

How many times a year does Xiaoxiao's dad swim and play two payment methods, so the amount of money is equal.

How many times a year can a smiling dad pay dividends? So the money is earned by you, I don't know what you mean.

Xiaoxiao's dad swims a year, and there are two ways to pay for as much as he wants, and all the money is equal. The father of the charcoal burden news has a reason to hit how many times in a year, and the two payment methods are suggested to be equal in number of this, but this year, the number of times the payment method is called, the trees used in the payment method, and so on. Communication is made up of a year of communication, communication with this kind of payment, all the money is double-equal in the shape of various payments.

Smiling Daddy Year Game. How much has it been? Only he knows. There are two ways to pay, one is that you can pay online, and the other is that you can also pay for buying equipment.

How many times a year does the smiling father swim and play, and the two pairs can be paid equally. Xiaoxiao's father loves swimming very much, so he can pay a lot of money for swimming every year, for example, he chose WeChat payment, and also thought of Alipay payment.

Dear, I don't understand, can there be a punctuation mark.

You didn't put the question into this question, generally speaking, there are two payment methods, two payment methods, one is more suitable for fewer times and one is more suitable for more times, I guess one is pay-per-time, and the other is yearly, but you didn't put it, so I don't know how to answer.

I don't understand the question of how many times a year does Xiaoxiao's father use the two payment methods, and the amount of money I use is the same.

Little Dad, I don't know how many times you play the game in a year, and you pay the same amount of money for the two payment methods, which means that the amount of money you play in the game is the same.

How many times a year does Xiaoxiao's dad swim and play, two payment methods, the amount of money is equal, you should pay once a year.

How many times a year does Xiaoxiao's dad swim, and the amount of money used for both payment methods is the same. You can pay monthly or annually.

How many times a year does the father swim and play, the two payment methods use the same amount of money, but the cost is different.

How many times a year does Xiaoxiao's dad swim and play, the two payment methods use the same amount of money, if you like to swim, we can get a card, you can get a half-year card is the most effective, and the price is also the most reasonable.

How many times a year does the smiling dad swim and play two payment methods, all the money. What does Hong Kong mean, it's really not clear about the description, I don't know much.

The dad of the driving school swims and plays how many times a year the two payment methods use the same amount of money, but I don't know what is equal to this, but.

How many times a year does the little dad swim, there are about two ways to pay. Equal, it's because it's typed, and the situation is all the same.

Your dad plays all the games a year, and the two out-of-pocket ways come to the whole method, which is very expensive, and the cost of playing games is very large.

Smiling Dad, how many times a year to swim and play the two payment methods use the same change, but it is difficult to see how many times a year Dad can shake.

Filial father, how many times a year to swim and play the two payment methods use the same amount of money, but what is the problem?

In order to expand a swimming pool with a length of 100 meters and a width of 60 meters into a large water playground with a circumference of 600 meters, and increase the length of the pool by x meters, then when x is equal to what, the area of the water playground is 20,000 square meters? If you can, you would like the value of x, and please say the reason if you cannot.

Solution: Now the length is: 100+x, then the width is: 600 2-(100+x)=200-x

That is: (100+x)(200-x)=2000020000-100x+200x-x 2=20000x 2-100x=0

x1=0,x2=100

That is, when the length is increased by 100 meters, and the width is increased: (200-100)-60=40 meters, the area is 20,000 square meters.

After purchasing a membership card, each admission ticket is two yuan cheaper than not buying a membership card, and it costs 80 yuan to buy a membership card.

Therefore, when buying 40 tickets, you will pay the same amount of money as if you did not buy a membership card.

When there are more than 40 tickets, it is more cost-effective to buy a membership card than not to buy a membership card.

When the purchase of ** tickets is less than 40, it is more cost-effective not to buy a membership card than to buy a membership card.

1.It's the same when you go 40 times.

2.More than 40 times to buy a membership card is more cost-effective than not to buy a membership card.

3.No more than 40 times It is more cost-effective not to buy a membership card than to buy a membership card.

Here's how it works:

If you buy a membership card and pay the same amount of money if you don't buy a membership card when you set up a district x times, then you have to pay the same amount of money.

3x=80+x

Solution x=40

Solution: After setting up x times, you can pay the same amount of money for buying a membership card as if you don't buy a membership card.

80+x=3x

x-3x=-80

2x=-80

x=40A: When you go 40 times, you pay the same amount of money for buying a membership card as if you don't buy a membership card, then, when the number of trips is less than 40, it is more cost-effective to buy a membership card without buying a membership card.

Absolutely).

Senior one mathematics refers to the mathematics learned in the first year of high school, the knowledge of senior one mathematics is mastered, the first year of high school questions account for about 60% of the college entrance examination score, five books to learn in one academic year, as long as the mathematics of the first year of high school is firmly mastered, the second year of high school, the third year of high school is just a review and supplement to the first year of high school. Any technique is based on a firm foundation of basic knowledge, so it is recommended that students in the first year of high school grasp the foundation and read more textbooks. In test-oriented education, only by memorizing more formulas and theorems, mastering problem-solving skills, and being familiar with various question types can you achieve the best results in the exam.

In the college entrance examination, only P> will be done

There were 3 people who participated in track and field and ball games at the same time, and 9 people who participated in only one swimming competition.

The process of solving the problem is as follows:

It's relatively easy to solve this problem with a veen image.

Answer; There are 3 people who participate in track and field and ball games at the same time.

There were only nine participants in one swimming competition.

For the function f(x), if x0 r exists so that f(x0)=x0 holds, then x0 is called the fixed point of the function f(x). It is known that f(x)=ax 2+(b+1)x+b-1(a≠0)

1。If there are always two different fixed points for b r, f(x) is the range of the real number a.

f(x) always has two different fixed points, so there are two different solutions to the equation ax 2 + (b + 1) x + b-1 = x, i.e. ax 2 + bx + b-1 = 0

b 2-4a(b-1)>0, which is true for any b r.

b-2a) 2-4a 2+4a>0, when b=2a, the minimum value is 4a-4a 2>0

02。Under the condition of 1, if the abscissa of two points on the image of y=f(x) is the fixed point of the function f(x), and the two points of ab are symmetrical with respect to the line y=kx+(a 2-4a+4), find the minimum value of b.

Let a(x1,y1), b(x2,y2), x1=y1, x2=y2

by ax 2+bx+b-1=0,x1+x2=-b a,x1x2=(b-1) a

ab two points are symmetrical with respect to the straight line y=kx+(a 2-4a+4).

kab=(y1-y2）/（x1-x2)=1,k=-1

The midpoint of ab (-b 2a, -b 2a) is in a straight line, and the person gets b=-a(a-2) 2

by 0< a<1, we can get the range of b: when a=3-5, b has a minimum value of 12 5-28< p>

Assuming that the customer is payable $x per month, then.

a*(a=

Hello! 1. Original formula =

2lg5(2/3)lg2³

lg5lg(2²×5)

lg2)²2lg52lg2

lg5)2lg2

lg5)(lg2)²

2lg52lg2

2(lg2)(lg5)

lg5)²lg2)²

2(lg5lg2)

lg5lg2)²

2lg10(lg10)²=3

2. Original formula = (lg5) (lg2).

[(lg2)/(lg5)

=[(lg5)/(lg2)

lg5)/(2lg2)]

lg2)/(lg5)

lg2)/(2lg5)]

lg5)/(2lg2)

lg2)/(2lg5)

3、lg(x-y)+lg(x+2y)

lg[(x-y)(x+2y)]

lg2+lgx+lgy

lg(2xy)

x-y)(x+2y)

2xyx²+xy-2y²=2xy

x²-xy-2y²=0

Divide both sides by y

x/y)²x/y

Solve x y-1 or 2

Because x,y>0, the negative value is rounded off.

Therefore, X Y2 can be asked if you have any questions. Have fun!

1. No, counterexample: 5>4,6>0,a-c>b-d; 5>4,3>0,a-c can,counterexamples:-1>-2,1>-3

AC is approximately equal to.

4. Less than, use x 2-(x-1), there is no root, indicating that x-1 is always less than x 2

5. This question is not clearly written whether it is m n+1 and n m+1 or m (n+1) and n (m+1), but no matter which one it is, it is uncertain and needs to be discussed in different situations, and there are three situations.

m>n.

m n+1>n m+1, m (n + 1)> n (m+1) m = n.

m/n+1=n/m+1,m/(n+1)=n/(m+1)

mb-c?If so, then it is correct, and the shift to a-b>d-c is clearly right.

If it's the original question, then it's definitely okay. But it doesn't seem to make much sense.

8, D, this belt number is a little faster, A generation 100, B generation 2, the result is D.

9. Greater than. You can think of this formula as the concentration of sugar water. A stands for sugar, B stands for sugar water, if you add a little more sugar to it, you think it will be sweeter, that is, the concentration is larger, so it is greater than it!

It took a bit of thought, and I hope you adopt it. Hehe.

1. That is, the equation 2x 2 + bx + 1 = 0 has no solution.

Just =b 2-8<0

i.e. -2 22, |x^2-3x+2|-x 2-3x+2) is not less than its absolute value of all real numbers.

So the set of solutions to this inequality is the whole real number r

One swimming pool, two drainage pipes, single open A pipe is filled in 3 hours, single open B pipe is filled in 6 hours, single open drainage pipe is drained in 4 hours, if 3 pipes are opened at the same time, how long can the swimming pool be filled?

4 hours.

1÷(1/3+1/6-1/4)

4 hours. Come) to illustrate the source:

A water intake per hour 1 3

B intakes 1 6 water per hour

Drain 1 4 per hour

The three pipes are opened at the same time, and the water intakes per hour (1 3 + 1 6-1 4) so the time required to fill up the water: 1 (1 3 + 1 6-1 4) If you are satisfied with the answer, please adopt it in time. Thank you.

The time that A opens a copy accounts for 1

3, B open.

The time bai accounts for 1 6, and the time when the two tubes are opened at the same time accounts for du1 3 1 6=1 2

Subtract the time it takes to drain the water pipe by 1 2 dao1 4That is: 1 2 1 4 = 1 4

Divide the unit "1" by 1 4, that is: 1 1 4 = 4 (hours) 4 hours can fill the pool.

Two in total? How to open three? Please ask the questioner to refine the question! If it's three drains! Then it's 1 (1 3+1 6-1 4)=4! It's an efficiency issue!

4 hours, if you are interested, you can take a look at the nine chapters of arithmetic.

Activity objectives: 1. Use symmetrical paper-cutting to cut out characters with continuous patterns.

2. Through the form of "hand in hand", pay attention to the cause of world peace and green cause.

Preparation for the activity: 1. Scissors, rectangular colored paper, square colored paper, double-sided tape, projection.

Today's children can't afford to be hurt, how can you hold it.

You ask for too little ... I suspect you asked us to help you write an elementary school essay...