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3. The surplus of 4 feet is the part of the rope outside the well, which is 12 feet in total.
The four-fold surplus of 1 foot is the part of the rope outside the well, which is a total of 4 feet.
Then the depth of the well is 12-4 = 8 feet.
Then the rope is 4*9=36 feet.
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Solution: Set the rope to be x feet and the well depth to be y feet.
x/3-y=4 ①
x/4-y=1 ②
Change to x 3-4=y and x 4-1=y.
x 3-4 = x 4-1
Solve x=36, then y=36 3-4=8 (feet), so let the rope be 36 feet, and the depth of the well is 8 feet.
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Let the depth of the well be x, the rope length is divided by 3-x is equal to twelve, and y divided by 4-x is equal to 4, and the well depth is 44, and the rope length is 192.
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So the rope is 36 feet and the well is 8 feet deep.
This is an elementary school question.
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It can be solved with binary equations!
Let the well be x and the rope length be y
The columnable equation y 3 = x + 4....1
y/4=x-1...2
The solution is x=16 y=60
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Let the depth of the well be x and the length of the rope be y
Then y 3 = x + 4
y/4=x+1
So x=8 y=36
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Rope length 3 - well depth 4*3
Rope length 4-well depth 1*4
The length of the rope is 96 feet, and the depth of the well is 20 feet.
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6 Case 1: 1+1 can be regarded as an overall alphabet, 2 + 2 = 2 (1 + 1) = 6 Case 2: 1 + 1 = 2 + 1 = 3
Case 3: 1+1=2 is an axiom, while 1+1=3 can be seen as a definition, similar to machine language. There is a one-way problem involved here.
That is, 1+1=3, 2=1+1 (pay attention to the direction), therefore, 2+2=1+1+1+1=3+3=6
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If you do this, all the algorithms will have to be redefined, and the conditions will not be enough.
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6 Analysis: Because 1+1=2 and 1+1=3 in the question, 2=3 can be obtained
Replace 2=3 with "2+2=? ", get: 2 + 2 = 3 + 3 = 6
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Because 1+1 is not equal to 2, you can't use the method of 1+1+1+1=6, I think 2+2=(3-1)+(3-1)=(3+3)-(1+1)=6-3=3. Be sure to use the condition 1+1=3, because it is the only condition. Or 2+2=(3-1)+(3-1)=(1+1-1)+(1+1-1)=1+1=3.
The person who came up with the question is so boring.
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First, prove that 2+2=1
1+1=3, subtract 1 from both sides at the same time, then 1=2, so 2+2=1+1 proves that 2+2=2, and subtract 1 from both sides at the same time, then 2+1=1 because 1=2, so 2+2=2
Then prove that 2+2=3, because 1+1=3, so 2+2=3 can also prove that 2+2=5,6....
The only thing that cannot be proved is that 2+2=4
So, the answer is, two plus any number of second rank other than four.
This question can be summed up in this truth:
Any one erroneous condition, with a finite number of correct deductions, can lead to any wrong conclusion, but not to any correct conclusion.
I don't have this level of direct pasting
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10 pcs. The first person sends his answer to the second person, and the second person, after receiving it, sends the first person's answer to the third person along with his own answer, and so on, and the ninth person sends his answer to the tenth person along with the answers of the first eight people. Then the tenth person came to ** and sent the answers of the ten people to the other nine people together.
It's very complete, and it should help you somewhat.
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