Physics If a beam of light is taken as a reference frame for another light, will its velocity still

Updated on science 2024-04-05
28 answers
  1. Anonymous users2024-02-07

    First of all, it's the speed of light.

    According to Einstein's special theory of relativity, the principle of invariance of the speed of light (i.e., the speed of light remains constant in all inertial frames of reference).

    Taking another beam of light as a frame of reference, this other beam of light is moving at a uniform speed satisfies being an inertial frame of reference.

    So one beam of light takes another beam of light as a frame of reference, and this speed of light does not change regardless of the direction.

  2. Anonymous users2024-02-06

    I'm more in favor of the upstairs view. But I would add the concept of frame of reference.

    I remember that the frame of reference was used in conjunction with Newton's second law.

    The most basic qualifier of Niu Er is the macro low speed.

    And light and photons are obviously microscopic and high-speed, so the first sentence is wrong.

    Well, as the first floor says, light doesn't make a frame of reference.

    So this question is obviously problematic.

    But if it's a high school or junior high school question, that's exactly what it does.

    Because after all, it's shallow to learn.

    Then the answer to this question is: still.

  3. Anonymous users2024-02-05

    This is Einstein's principle of invariance of the speed of light. Our common sense seems inconceivable. Because it's ultra-low-speed.

    That is, there is basically no ruler shrinkage effect and bell slow effect. But in the surrounding space that moves at the speed of light. These two effects are evident.

    So your question is valid. I don't know if my understanding is right or not, so I won't be ugly.

  4. Anonymous users2024-02-04

    No, one of the assumptions of Einstein's theory of relativity is that the speed of light is constant, no matter what the frame of reference is, and it turns out that the theory of relativity is correct, so this assumption is also correct

  5. Anonymous users2024-02-03

    Einstein's special theory of relativity does mention two assumptions.

    1. The principle of speed invariance: the speed of light remains constant in all inertial frames of reference;

    2. The principle of relativity: for all inertial frames, the physical laws expressed by space and time using the reference frame are all in the same form;

    The first hypothesis will solve the problem you asked!!

  6. Anonymous users2024-02-02

    You're saying they're moving in the opposite direction! If so: yes, they are twice as fast as each other.

  7. Anonymous users2024-02-01

    There is a theory of the invariance of the speed of light, Guan can not pass as a frame of reference, if you have the heart, take a look at this experiment, interesting, but very puzzling, difficult to understand, if you really want to know, you can take a look at the "Theory of Relativity".

  8. Anonymous users2024-01-31

    No, according to the special theory of relativity, matter moving relative to each other in any frame of reference will not exceed the speed of light.

  9. Anonymous users2024-01-30

    As far as this question is concerned, it seems that it is really the same thing, speed is relative, and this is the same thing in our daily life, the relative speed of trains traveling in opposite directions is the sum of the speeds of two trains. But if this is true, then isn't Einstein's theory of relativity broken? Because Einstein believed that the speed of light is the maximum speed at which an object can move.

    In fact, one point that needs to be considered here is the influence of the speed of light on this relative motion, we often say that the relative velocity of two objects is the subtraction of the velocity vector of two objects, but there are still restrictions on the calculation of this relative velocity, that is, the speed of this object cannot be close to the speed of light, because when the object is close to the speed of light, then its mass and space, time will have a huge change, and this change can no longer be ignored.

    When an object approaches the speed of light, then the mass of the object increases, time slows down, and space is distorted, and in this case, it makes no sense to calculate the relative velocity. Because of the influence of this time and space factor, the speed at this time can be regarded as absolutely stationary.

    Why do you say that, when the speed is close to the speed of light, time will infinitely tend to be stationary, and when the speed of light is completely reached, then time is completely stationary, that is, the time of the two beams of light is stationary, and the time is stationary, then the relative velocity of the two beams of light is 0.

    When approaching the speed of light, the theory of relativity is used, not Newtonian mechanics, and it is not necessary to bring Newton's worldview into the understanding of the theory of relativity, because then it would be impossible to understand what the theory of relativity is talking about. This is because the worldview of relativity and Newton's worldview are different, in the theory of relativity, space-time are mutually influencing and not independent, and space-time can be bent and will be affected by motion. To put it bluntly, a centimeter or a second may be different for people in different frames of reference.

  10. Anonymous users2024-01-29

    Light cannot be a reference for another beam of light, and it cannot be a reference frame for measuring the motion of any objectThe speed of light is the limit of space-time detachment, and for light itself, there is no time and space, and the distance of light through 100 million light years is the same as the distance of 1 meter, and it does not require any time, nor does it have any measure of space. Therefore, there is no precise position, not even relative position. Therefore, light cannot be used as a reference frame to measure the motion of any object, and of course it cannot be used as a reference for another beam of light, that is, we cannot use one beam of light as a reference object to measure the speed of another beam of light, even if it is two beams of light traveling in opposite directions.

    Because the two beams of light have no time and space for themselves, they don't have any speed to speak of. Not to mention twice the speed of light, not even twice the speed of light.

    Secondly, the reference object of light is space-time, and nothing conventional can be the reference object of light. Einstein's principle of invariance of the speed of light in relativity states that the propagation speed of light in a vacuum is constant for any frame of reference. The magnitude of this speed is 299792458 meters and seconds.

    It's strange to see someone here: the speed of light has a specific size, it has a reference, and its reference is any frame of reference, how can it be said that anything conventional cannot be a reference of light? Don't be surprised, a frame of reference is not a regular thing, in the theory of relativity, it represents space-time.

    We usually measure the velocity of an object, using a relatively stationary object, such as the earth, as a reference, but in fact, the space-time in which the earth is located as a reference. This is especially true for measuring the speed of photons.

    Velocity is equal to space divided by time, and the motion of any object is against the background of space-time, any velocity.

    The size is a measure of space-time, and light is no exception, no matter how fast it is, it is also moving in space-time, and the invariance of the speed of light is also a comprehensive embodiment of the relativity of space-time. Therefore, only space-time can be the reference system of light, ordinary conventional things cannot be made, and of course light cannot be the reference of light, because light is not space-time. It's just that light is closely related to space-time, and the speed of light is constant relative to space-time where objects in different states of motion are located.

    This shows that light and the speed of light are essential properties of space-time.

    Although light has a constant velocity for the space-time frame of reference, it has no velocity for itself or other light. For two beams of light in opposite directions, the speed of the other beam of light is not twice the speed of light, but there is no speed, because the light cannot be a reference, including a reference of the other light. The only thing that makes light a reference is space-time, and the speed of light is constant relative to any frame of reference (space-time).

  11. Anonymous users2024-01-28

    First of all, light cannot be a reference for another beam of light, nor can it be a frame of reference for measuring the motion of any object.

  12. Anonymous users2024-01-27

    Because light is not static, it cannot be used as a frame of reference.

  13. Anonymous users2024-01-26

    Because, there are many other factors that play a role.

  14. Anonymous users2024-01-25

    Because light travels very fast.

  15. Anonymous users2024-01-24

    It is possible that there are other factors in the universe.

  16. Anonymous users2024-01-23

    Light cannot be used as a frame of reference to measure the motion of any object.

  17. Anonymous users2024-01-22

    Light cannot be a reference to another beam of light.

  18. Anonymous users2024-01-21

    No, Newtonian classical mechanics is limited to macroscopic low-velocity objects, and the speed of light is out of this category, and in Einstein's theory of relativity, the speed of light is constant, even with respect to another beam of light.

  19. Anonymous users2024-01-20

    Taking a beam of light as a frame of reference, the other beam of light is also twice the speed of light, not twice the speed.

  20. Anonymous users2024-01-19

    No, this is a fallacy, according to the principle of the invariance of the speed of light in special relativity, the speed of another beam of light is still the speed of light.

  21. Anonymous users2024-01-18

    It is not twice the speed of light, and one of the basic assumptions of special relativity is the principle that the speed of light does not change. That is, the speed of light in a vacuum is the same for any observer and does not change with the relative motion of the light source and the observer's frame of reference. Therefore, the speed of light is always constant.

  22. Anonymous users2024-01-17

    Yes, if one beam of light is used as a frame of reference, the opposite beam of light is twice the speed of light, which is explained according to the theory of relativity. If it is in the same direction, the velocity is zero.

  23. Anonymous users2024-01-16

    Actually, what I said above is not true, it is not C.

    According to v(x)=(v(x)-u) (1-v(x)u c 2), the case is 0 0, which is not only meaningless from the point of view of the formula, but also the mathematical derivation process of the velocity formula of special relativity itself does not hold.

    But it is conceivable that in this case, a beam of light can never be observed by another co-speed frame of reference, so the "god" in this frame of reference does not think that the light does not exist, that is, there is no speed to speak of.

  24. Anonymous users2024-01-15

    The speed of light does not change, so it is still c

  25. Anonymous users2024-01-14

    What is the velocity of two beams of light in the same direction relative to the other?

    Do you think the word relative is relative in time? The relative of space? Spatial relativity is meaningless.

  26. Anonymous users2024-01-13

    The so-called speed of light is the speed of other objects as a reference, such as the earth as a reference, we can understand that the speed of light is the absolute speed. Your problem is the relative velocity, the reference given is another beam of light in the same direction, so the relative velocity is 0

  27. Anonymous users2024-01-12

    Or c, the relative velocity cannot be calculated according to general physics. (For reference only, not necessarily right).

  28. Anonymous users2024-01-11

    The empirical formula for the relationship between n and in normal dispersion is the Kochy equation: n=a+b 2+c 4.

    When the wavelength variation is not large, the Kochy equation can be approximated in the form n=a+b 2 dn d =2b 3

    The empirical formula for the relation to n and under anomalous dispersion is the Sellmeier equation.

    f=v/λ=c/(λn)=nc/(λ

    From the above formulas, it can be obtained: increase, n decrease. and =c=299792458 (m s), so when it is large, n is also large.

    But the frequency of light is its essential property, and the relationship between it and the refractive index is not an independent variable and a dependent variable.

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