Equation application problems. plus process fast as the title Thank you

B travels x kilometers per hour, A travels x + 1 km per hour 4x+4(x+1)=36,x=4 B travels 4 kilometers per hour Small: Medium: Large = 8:

3:12 Let small 8x, medium 3x, large 12x then 5*8x+10*3x+15*12x=250x=7500,x=30 small240, medium90, large 360 a x, b y x+y=10 8x+3y=60 solution x=6,y=4 a6, b4 x people per group 12x+15=9x+27 x=4 a total of 12*4+15=63 people.

1. Solution: Let B travel x kilometers per hour, then A travels x + 1 km per hour From the meaning of the question, it can be obtained 4 * (x + x + 1) = 36 x = 4 kilometers Therefore, B travels 4 kilometers per hour 2, Solution: The ratio of small cars and medium-sized vehicles is 8:

3, the ratio of the number of medium cars and large cars is 1:4 can be set the number of small cars is 8x, the number of medium cars is 3x, the number of large cars is 12x, then 5 * 8x + 10 * 3x + 15 * 12x = 7500 x = 30 Therefore, the number of small cars is 240, the number of medium cars is 90, and the number of large cars is 360. 3. Solution:

If there are x in box A, then there are 10-x in box B From the meaning of the title, we can see that 8x+3*(10-x)=60 x=6 So, box A has 6 and box B has 4.

The coordinates of the point p are set as family return (x,2x+1), and the distance from point p to point (2,3) is 6

x-2)²+2x+1-3)²=6

x-2)²+2x-2)²=36

Solution: x=(6 4 11) 5

Point p is in the second quadrant.

x＜0x=(6-4√11)/5

Substituting x into y=2x+1 results in: y=(17-8 11) 5 0 is inconsistent with the condition.

There is no point p

Question 1: 5 cents coin: (piece).

5 dime: 20 12 = 8 (pieces).

2 questions: 130 (1-7 9).

585（km）

Question 3: A and B traveled for two whole trips.

45×2＋15×2）÷2=60（km）

Question 1:

Solution: Let the 5 cents coin have x pieces, and the 5 dimes are 20-x x x = 12

5 Dime: 20-x = 20-12 = 8 pieces. Question 2:

585 km.

Question 3: When the two cars A and B met, they traveled a total of 2 whole courses.

60 km.

(1) 5 minutes x x x x = 12 20-12 = 8 (2) Car A takes 16 hours to get from Dongcheng to Xicheng and meets in 9 hours, and Car B takes 1 (1 9-1 16) = 144 7 from Xicheng to Dongcheng

Car B has been driving for 16 hours, there are 144 7-16 hours left, and there are 130 kilometers left, so the speed of car B is 130 (144 7-16) = 455 16 The distance between the east and west cities is 455 16 * (144 7) = 585 kilometers (3) Line A 90 Line B 30

60 kilometers from A and B.

1) Coins with 5 cents and 5 jiao are x and y respectively.

Then x+y=20;

Then: y=8x=20-8=12

A: 12 5 cents and 8 5 dimes.

2) Let the speed of car A and car B be v and u respectively, then 9(v+u)=7(v+u)+130

This gives v+u=65

Therefore, the distance between the east and west cities is 9(v+u)=9 65=585 kilometers.

3) According to the title, the total distance traveled by A and B in 3 hours is twice the distance between AB, and the total distance traveled by A and B is 2 (45+15)=120 km, so the distance between AB is 120 2=60 km.

It's not an equation, it's an inequality.

A year ago, Lao Zhang bought x rabbits.

Lao Li is also x.

Now Lao Zhang x+2.

Lao Li 2x-1.

So x+2 (2 3) (2x-1).

3x+2≤4x-2

4x-3x≥2+2

x 4 A: A year ago, Lao Zhang bought at least 4 rabbits.

Let's say that a year ago, Lao Zhang bought x rabbits, so Lao Li also had x;

A year later: Lao Zhang raised (x+2) only; Lao Li: (2x-1) The number of rabbits raised by Lao Zhang does not exceed 2 3 of the number of rabbits raised by Lao Li, that is:

x+2≤2(2x-1)/3

3x+6≤4x-2x≥8

This title is an inequality Let Lao Zhang buy rabbits, then 2&+1 is less than or equal to (2 -1) multiplied by 2/3 to solve greater than or equal to 8

Set the distance to x km, the bus time is 1 3 bus time + 2 3 taxi time + 10 minutes (1 6 hours).

x/30＝1/3x/30+2/3x/60+1/6

x 15 km.

1) Need to subtract x 19x15-x=77 x=285-77=208 2) Set length x x*(x-10)=600 x 2-10x-600=0 x=30 x=-20 (rounded) x-10=30-10=20 The length is 30 meters wide and 20 meters wide 3) The width of the lace x 40-3*6=2*3x+2*6x+4x*x 22=18x+4x 2 (2x-2)(x+11)=0 x=1 x=-11 (rounded).

1 Let the side length of the part to be subtracted be a, according to the meaning of the topic (15-2a)(19-2a)=77 simplify a 2-17a+52=0 (a-13)(a-4)=0 a=13 or a=4 a=13 is not suitable for the topic to remove So a=4Answer: You need to cut the squares with a side length of 4 at the four corners of the paper.