Is it better to use a diode to buck the mobile phone charger to change the water heater battery to b

I don't know if the loud sound of the ignition you are talking about is the sound of electric sparks? Diode buck is not the same as resistance buck When current flows through the resistor, a voltage is generated at both ends of the resistor, and this voltage is the voltage of the resistance drop. The calculation formula is U=IR, and it can be seen that the voltage dropped by the resistance changes with the current.

When you use the ignition, you need a voltage of 3V, so the resistance should be divided into 2 V, if you have a multimeter, you can measure the current of the ignition working normally, and then use the previous formula to calculate. If the ignition current is constantly changing, the resistance is powerless The voltage drop at both ends of the diode remains unchanged when it is used, and the voltage drop of 1N4007 is therefore the voltage drop of the three strung together, so it is just right to use it directly, but the heat of the circuit becomes a little larger, and the general circuit has a margin in the design, so there will be no problem If you must use 3V, it is recommended to use a 3V regulator tube.

You actually don't use a diode to buck the voltage, you can use it directly by connecting it, and the water heater at home has been used like this for a long time. It's been over a year without any damage and is easier to fire than a battery. And save money.

The voltage of the charger is the same as that of the sealant Tsumiko'The dry cell voltage is slightly higher, but that's okay.

Left and right, string three diodes just right.

How many people are in kindergarten on the day chart.

Two fundamentally different components, not interchangeable or subplaceable.

The diode is a unidirectional conduction characteristic, but the resistance does not distinguish polarity, and only plays the role of step-down and current limiting in the circuit, and the performance is not the same, so it cannot be replaced.

The diode of the charger is not uncommon, and it is not high, and most of the stores of radio accessories in the electronic city can be reached, and there is no need to replace it.

If the space of the charger is suitable, it is better to switch to a diode with a higher power and a higher withstand voltage.

Hard City has this model, you can go and see if there is any information on this.

Yes, but the power consumed on the resistor will be large, the resistor will heat up, and if the rated power of the resistor is exceeded, the resistor will burn out.

But to cut the line short, it is difficult to control

DC circuits are discussed.

The current-limiting resistor uses the flowing load current to generate a voltage drop on itself, thereby reducing the voltage at both ends of the load to limit (reduce) the load current. For a current-limiting resistor of the same resistance, the greater the load current, the greater the voltage drop generated.

When the ordinary diode is turned on, it will also produce a voltage drop of approximate, which can also reduce the voltage at both ends of the load, so it has a similar effect as a current limiting resistor. However, after the diode is turned on, the voltage drop across the diode is basically stable, regardless of whether the current flowing through it is large or small.

For example, if we have a 5V mobile phone charger and want to use it on a 3V radio, we can connect 3 diodes (such as 1N4001) in series to limit the working voltage of the radio to approx.

In AC circuits, ordinary diodes do a completely different role than current-limiting resistors!

However, in some specific circuits, diodes can also play the role of "current limiting". For example, in the past, we used incandescent bulbs to make the light source of stair lights, in order to save electricity and make the bulb more durable, we often put a diode into the bulb, and use the unidirectional conduction characteristics of the diode to reduce the voltage of the bulb by half, and the current is also reduced by half, and the power becomes the original 1 4, the temperature of the filament is reduced, the evaporation is less, and the bulb is durable.

Current limiting with resistors. Limit the maximum charge current: (

Current at full charge: (

Choose 8 10 1 2W resistor step-down current limit, charging current 200 80mA, when fully charged, the lithium battery protection circuit will automatically protect and stop charging. This is to charge the positive and negative poles of the battery with a protection circuit.

It is also possible to connect the diode in parallel, and then connect the resistor in series, fast charging and slow charging can be combined; Diode step-down voltage-limiting string resistor current-limiting charging without protection circuit.

5V can be obtained by passing two diodes in series (e.g. 1N4007).

1. Resistance step-down consumes a lot of electrical power.

2. The diode step-down is a half-wave conduction power supply, and the power consumed is very small.

It should be that the diode acts like a fuse to prevent accidents and the resistance does not.

You can use it without changing it, and the effect is even better! If you have to change it, connect a voltage-limiting diode and a resistor in series on the power supply circuit, and then connect it to the water heater. I personally used the water heater battery is originally equipped with two batteries, I add one more battery is very useful, 3 batteries are also electric, and then I use a mobile phone charger is no problem, there is no mobile phone charger, I use ordinary electrical appliances to remove the power supply with a transformer to add a 7805 or 7806 to it is also the same, now there is no problem for a few years.

If you can change it, don't bother, just use it directly.

1. IN5408 rectifier diode, rated current 3A, reverse voltage 1000V, silicon tube, forward voltage drop.

2. The scheme is feasible, and it is recommended to use 7 threads in series.

3. If you use 4 in series, 12-4*.

Considering that the charging current of the children's car battery may be too large and damage the battery, it is recommended to connect the current limiting resistor in series.

No, the diode buck is only about 3 volts. 2,2 electrodes will heat up severely. 3. Charging management is required for battery charging.

The charger current is unknown, it may be 2A, and the diode does not burn out.

The charging current of the 6V battery is not known, and the capacity is not known. It is possible that the current is too high.

The 1N5408 is a high-voltage low-frequency rectifier and the voltage drop may not be, but. It may be hot at high frequencies of the charger.

12V charger limits, 6V battery limits, 10 or 6 series buck diodes.

You can use 4 diodes in series to charge the 6V battery, after series connection, the diode is connected to the positive pole of the 10 L2 battery, the negative pole of the diode is connected to the 10 poles of the 6V battery, and the negative pole of the 12 battery is connected to the negative pole of the 6V battery.

The forward voltage drop of the rectifier diode can still be used to reduce the voltage of the charger, the general forward voltage drop is volt, with the slight proportional change of the current flowing, 8 10 are required to be connected in series into the charging circuit, and the number of diodes can be adjusted by increasing or decreasing the charging current.

Generally, the forward voltage drop of a diode requires about 10 diodes of the same type in series.

No, because you can't downgrade 12V to 6V.