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tan(16) + tan(44) + root number 3 tan(16) tan(44) = tan(16+44) [1-tan(16) tan(44)] + root number 3 tan(16) tan(44) = root number 3 [1-tan(16) tan(44)] + root number 3 tan(16) tan(44) = root number 3
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sin16/cos16+sin44/cos44+(sin16*cos44+sin44*cos16)/(cos16*cos44)+
sin(16+44)/(cos16*cos44)+sin60/(cos16*cos44)+
cos16*cos44)+
That is, the root number 3, replace all of the above with the root number 3, and the * sign is the multiplication sign.
It's really inconvenient to play math symbols.
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I don't know if I want the process).
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Hello, the root number is. This is because it can be written as tan(, and tan( can be solved with an inverse trigonometric function, i.e., tan(root. Therefore, the root number is.
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Then it can be directly expressed with 32 roots, because a number of its tan is also a symbol in mathematics, so it can be expressed with 32 numbers is the best.
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tan60° = root number 3 sin45° = 1 2 root number 2 tan 45 ° = 1 cos30 ° = 1 2 root number 3
So = 3-4 times the root number 3 + 4 + (root number 3 + 1) = 8-3 times the root number 3
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Obviously, Chongchang is not 0.。。。 Equal to tan15 Calculate tan15 yourself and judge it... tan(15)=tan(45-30), and then it's okay to go macro...
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tan30°=sin30 cos30=1 2 (root number 3 2) = root number 3 3
tan30°=tan(90°-60°) This letter is right.
But you can't tease tan30° so violently, because you don't know the value of tan90°.
tan15°=tan(45°-30°)=tan45°-tan30°)/1+tan45°tan30°)
1-Root No. 3 Slip Zhiwang 3) (1 + Root No. 3 3) If you don't understand, you can ask.
Have fun.
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tan45°=1
tan15°=tan(45°-30°)=tan45°-tan30°) (1+tan45°tan30°).
1- 3 3) (1+ Hupi3 3).
Blind 3-1) (3+1).
tan45° times tan15° = 2-3
45. First of all, you need to know: tan(a+b)=tana+tanb 1-tana*tanbtan(a-b). >>>More
3.The original equation can be reduced to tan(95-35)(1+tan95tan35)- x= x, tan95tan35, i.e., x= 3, so x=3is the root number.
tg(60) = root number 3 = tg(20+40) = tg20+tg40 (1-tg20tg40). >>>More
cos(2θ)=7/25
cos 2(2)-sin 2(2)=7 251-2sin 2( )=7 25, so sin =3 5 >>>More
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