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Anonymous users2024-02-10Gen No. (1+sin40°) - Gen No. (1-sin40°), Gen Shiji Town No. (1+cos50) - Gen No. (1-cos50), Gen Fengju No. (1+2cos 25-1) - Gen No. (1-2sin 25-1), Gen No. 2cos25 - Gen Sou Coarse No. 2sin25
2sin(25-45)
2sin20
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Anonymous users2024-02-09√（1-sinα）+1+sinα）
（sin²（α2）+cos²（α2)-2sin(α/2)cos(α/2））
（sin²（α2）+cos²（α2)+2sin(α/2)cos(α/2））
（sin（α/2）-cos（α/2）)²sin（α/2）+cos（α/2）)²
sin（α/2）-cos（α/2）|+sin（α/2）+cos（α/2）|
When a (0, 2), cos( 2) sin( 2) 0
Original formula = cos( 2) -sin ( 2) + cos ( 2) + sin ( 2) = 2 cos( 2).
When [2, ), 0 cos( 2) sin( 2).
Original formula = sin( 2)-cos( 2) + sin( 2) + cos( 2) = 2sin( 2).
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Anonymous users2024-02-081-sin = [sin( 2)-cos( 2)] 1+sin = [sin( 2)+cos( 2)] root number(1-sin) + root number(1+sin)=|sin(α/2)-cos(α/2)|+sin(α/2)+cos(α/2)
2sin (2), (2 times).
Root number (1-sin) + root number (1+sin) = |sin(α/2)-cos(α/2)|+sin(α/2)+cos(α/2)
2cos(2), (0< <2).
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Anonymous users2024-02-07Solution: original = root number ((sin( 2)-cos( 2)) 2) + root number ((sin( 2) + cos( 2)) 2).
1) When 2< ", sin( 2)-cos( 2)>0, then.
Original formula = sin(2)-cos(2)+sin(2)+cos(2).
2sin(α/2)
2) When 0< 2, sin(2)-cos(2)<0, then.
Original formula = sin(2)-cos(2)+sin(2)+cos(2).
2cos(α/2）
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Anonymous users2024-02-06The root number (1-sin) + root number (1+sin) is very cumbersome to write, and it may not be clear, mainly using two formulas: sina 2+cosa 2=1, sin2a=2sinacosa
0 2 2, so sin(a 2)>0, cos(a 2)>0 can be brought in, and the root number can be crossed out.
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Anonymous users2024-02-05Think of sina as a double angle, and write 1 to get a perfectly flat way. Pay attention to positive and negative discussions.
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Anonymous users2024-02-04Solution: From the meaning of the question, it can be obtained: <2 , so 2< 2< so cos( 2)>0
1+cosθ=2[cos(θ/2)]^2
So [(1+cos) = 2cos(2)
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Anonymous users2024-02-03You may have missed a square. Once you add it, it's easy to simplify.
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Anonymous users2024-02-02Root number (1-2sin40° cos40°) cos40° - root number (1-sin50°) = root number ((sin40°-cos40°) 2 ) cos40° - root number ( (cos25°-sin25°) 2 ) = (sin40°-cos40°) cos40°- cos25°-sin25°) = tan40°- 1- root number 2 sin(45°-25°) = tan40°- 1- root number 2 sin20°
a-b)*(a-b) (a+b)*(a+b) 2(a*a-b*b) = --
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