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Anonymous users2024-02-10Conservation thought, ammonium and hydroxide reactions. Therefore, there are as many ammonium as there are hydroxide roots.
Calcium hydroxide, that is, ammonium ions are also altogether.
So, ammonium is so nitrogen is.
The mass fraction of nitrogen is b
If you're a junior high school student, think like this, conservation thought, ammonium and hydroxide reaction. Therefore, there are as many ammonium as there are hydroxide roots.
2 ammonium and one calcium hydroxide react, column that proportion, ammonium is equal to the mass of ammonium divided by calcium hydroxide.
The mass of ammonium can be found, so the mass of nitrogen can be found.
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Anonymous users2024-02-09b Ca(OH)2+2NH4Cl=Heating=CaCl2+2NH3 +2H2OCA(OH)2+(NH4)2SO4=Heating=CaSO4+2NH3 +2H2O
ca(oh)2---2nh4---2n
x74 x = The mass fraction of nitrogen in this fertilizer is approx.
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Anonymous users2024-02-08The reaction with calcium hydroxide is the ammonium in the reactant, n (calcium hydroxide) = then n (hydroxide) = is the ammonium in the reactant, multiply by the molecular weight of nitrogen 14 to get and divide by 12 is the mass fraction of nitrogen, I hope it can help you.
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Anonymous users2024-02-07Na2CO3, CaCO3 (each amount is 1mol).
Analysis: Because half of the oxygen in sodium peroxide will be changed to oxygen in the reaction, it can be understood as the form of sodium oxide and atomic oxygen (ultimately oxygen): , HCO3 in the question is disassembled into H and CO3, and the oxygen in H and sodium oxide satisfies 1:
The above results are obtained when 1 is treated as OH and 2:1 is treated as water, and the atomic oxygen is removed, and the remaining components are considered.
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Anonymous users2024-02-06A Sodium carbonate : 1 mol + naoh mol
b Sodium carbonate: 1 mol
c Calcium carbonate 1 mol + sodium carbonate mol + naoh mol
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Anonymous users2024-02-05a 1 Mo of sodium carbonate and 1 Mo of sodium hydroxide.
b Sodium carbonate 1 mo.
c 1 Mo of calcium carbonate and 1 Mo of sodium carbonate.
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Anonymous users2024-02-04After careful examination of the question, it was found that this was an information question. Although there are many texts in the questions, the test is actually about the knowledge and some basic knowledge of valence.
First question: It can be counted that y2ba4cu6o12 is composed of four elements: y ba o cu.
Question 2: There is a sentence in the title: "The valency of all elements in this process does not change". That is to say:
In the process of obtaining Y2Ba4Cu6O12 from Ymon, the valency of all elements remains unchanged. Thus, we can know that ba is +2 valence (because carbonate is -2 valence, which is something that should be remembered) and cu is +2 valence because oxygen usually shows -2 valence.
So in Y2Ba4Cu6O12, we can get according to the rule that the total valency of the compound is zero.
The valency of y is: +2 valence.
Question 3: So it can be concluded that the formula of ymon is yo.
Last question: A little bit of textbook content is involved.
We know that there is such a reaction:
CaCO3 = (high temperature) CO2 + CAO
This is an important reaction and an industrial way to produce quicklime (CAO).
By the same token, since a common gas is produced, you should think of the following reactions:
BAC3 = (high temperature) Bao + CO2. Carbon dioxide is a common gas. And this reaction is very similar to the reaction of industrial quicklime.
So the answer to the fourth question is carbon dioxide.
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Anonymous users2024-02-03...Coincidentally, I'm writing this.
1) 4 types; +3 valence; The last empty will not.
2) Carbon dioxide or CO2
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Anonymous users2024-02-022h2s+so2=2h20+3s
Yellow solid s, and small water droplets are produced.
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Anonymous users2024-02-01151000*
So if you don't understand the choice c, you can ask me again.
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Anonymous users2024-01-31Solution: (1) Sulfuric acid.
2) Let the mass of zinc in the reaction be x, then.
zn+h₂so₄=znso₄+h₂↑
65 2x65/x=2/
x=znMass fraction=(
A: The mass fraction of zinc is 65%.
3) Let the mass of sulfuric acid in the dilute sulfuric acid consumed be x when the zinc is completely reacted, then.
zn+h₂so₄=znso₄+h₂↑
x65/x=98*
Let the mass of sulfuric acid in the second sample be y, then.
zn+h₂so₄=znso₄+h₂↑
98 2y98/y=2/
y=98*Mass fraction of sulfuric acid=(
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Anonymous users2024-01-30It's not easy, what grade are you in?
B. should be chosen
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