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Question 3: (1) :(10+4) 2=28

3) Approximately equal to.

4): 6 +12 =18 is approximately equal to.

Question 4: (1): 4 (2 3)-4 (2 2)=24-16=8

3. (1) Circumference (10 4) x 2 28;(2) 14 x 4 64 (middle digit multiplied by 4, ** illegible).

3) x 2 (4)6 12 18 cm.

4. (1) 1 4 x x6 x6-1 4 x4 x4 = 5 = square centimeters.

2)(1 4 x 4x4-4x4 x 1 2)x2=8 16 This is the shadow area in the upper right corner.

1 2 x x4x4 - (8 -16) = 16 This is the area of a blank space.

The shadow area sought is 8x8 - 2x16 = 32 square centimeters.

3) (1 4 x 16-1 2 x4 x4) x 2=8 -16 upper half shadow area.

1 2 x (8+16) x 4-1 2 x 16=48-8 off-duty portion shaded area.

The area sought is 8 16 48 8 32 square centimeters.

Solution: If A takes x days, then it takes 3 2x days You can set the amount of work to be 1 unit, then A does 1 x every day 1 x has done 1 3 2x6 x+6 3 2x=1 every day

x = 10 because A is going to do what he has done 2 3 days.

F=10 divided by 2 3=15

Answer: It takes 10 days for A and 15 days for himself.

From top to bottom, from left to right (1): 21 10 (2): 2 3 (3) Shan Shi Zao: 9 20 (4): 2 21 (5): 17 15 (6) Tease: 89 114

Twenty tenths plus eighteen thirties plus twenty-five tenths of thirty equals sixty-three thirties.

Do you want to have a process?

I'm a middle school student, column equations, the stupidest method. Let x pieces be sold at the list price, and the price is q, q*85%=[qx+(76-x)*80%*q] 76 Solve x=19

Sell according to the fixed price and get money: qx. Get money at 80% of the list price:

76-x)*80%*q。The sum of the two items is the amount of money received after the sale, and then divide by the total number of pieces to get the average amount of money per piece. That's 85% of the list price:

q*85%。

Eliminate q on both sides of the equation, solve 19 pieces, and sell 19 pieces according to the price price.